Volume 2021, Issue 1 5524430
Research Article
Open Access

Fourier Transformation and Stability of a Differential Equation on L1()

Hamid Rezaei

Corresponding Author

Hamid Rezaei

Department of Mathematics, College of Sciences, Yasouj University, Yasouj-75914-74831, Iran yu.ac.ir

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Zahra Zafarasa

Zahra Zafarasa

Department of Mathematics, College of Sciences, Yasouj University, Yasouj-75914-74831, Iran yu.ac.ir

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Lotfollah Karimi

Lotfollah Karimi

Department of Mathematics, College of Sciences, Hamedan University of Technology, Hamedan-65169-13733, Iran hut.ac.ir

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First published: 15 July 2021
Citations: 1
Academic Editor: Theodore E. Simos

Abstract

In the present paper, by the Fourier transform, we show that every linear differential equation with constant coefficients of n-th order has a solution in L1() which is infinitely differentiable in ∖{0}. Moreover the Hyers–Ulam stability of such equations on L1() is investigated.

1. Introduction

One of the main mathematical problems in the study of functional equations is the Hyers–Ulam stability of equations. S. M. Ulam was the first one who investigated this problem by the question under what conditions does there exist an additive mapping near an approximately additive mapping? Hyers in [1] gave an answer to the problem of Ulam for additive functions defined on Banach spaces. Let X1, X2 be two real Banach spaces, and ε > 0 is given. Then, for every mapping, f : X1X2 satisfying
(1)
There exists a unique additive mapping g : X1X2 with the property
(2)

After Hyers result, these problems have been extended to other functional equations [2]. This may be the most important extension in the Hyers–Ulam stability of the differential equations.

The differential equation φ(y, y, …, y(n)) = f has Hyers–Ulam stability on normed space X if, for given ε > 0 and a function y such that ‖φ(y, y, …, y(n)) − f‖ < ε, there is a solution yaX of the differential equation such that ‖yya‖ < K(ε) and limε⟶0K(ε) = 0.

In the theory of differential equations, we search for a classical symmetric solution or a weak or generalized solution. Usually, these solutions at least satisfy the equation almost everywhere. It seems that the ϵ-solution provides us a wider notion of a solution, and for some physical applications, it models the underlying physics more appropriate. We hope this paper is a beginning for further research about the ϵ-solution of a differential equation. In the theory of differential equations, it is particularly important for problems arising from physical applications that we would prefer our solution changes only a little when the data of the problem change a little. It is called the continuity of the equation with respect to data. See [3] and section 3.2 in [4]. It is straightforward to check that the Hyers–Ulam stability of our problems is equivalent to the continuity of the equations φ(y, y′, …, y(n)) = f with respect to the right-hand side f.

Alsina and Ger [5] were the first authors who investigated the Hyers–Ulam stability of a differential equation. The result of the work of Alsina and Ger was extended to the Hyers–Ulam stability of a higher-order differential equation with constant coefficients in [6]. We mention here only the recent contributions in this subject of some mathematicians [615].

Rus has proved some results on the stability of ordinary differential and integral equations using Gronwall lemma and the technique of weakly Picard operators [13, 14]. Using the method of integral factors, the Hyers–Ulam stability of some ordinary differential equations of first and second order with constant coefficients has been proved in [9, 15].

We recall that the Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. It maps a function to a new function on the complex plane. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions. Applying the Laplace transform method, Rezaei et al. [16] investigated the Hyers–Ulam stability of the linear differential equations of functions defined on (0, +).

Fourier transforms can also be applied to the solution of differential equations of functions with domain (−, +). They can convert a function to a new function on the real line. Since the Laplace transform cannot be used for the functions defined on (−, +), in the present paper, we apply the Fourier transforms to show that every n-order linear differential equation with constant coefficients has a solution in L1() which is infinitely differentiable in ∖{0}. Moreover, it proves the Hyers–Ulam stability of the equation on L1().

It seems that authors of [17], Theorem 3.1, by using the Fourier transform, proved the Hyers–Ulam stability of the linear differential equation of functions on (0, +). But, this is not a new result because the restriction of the Fourier transform on the space of functions with domain in (0, +) is the Laplace transform, and it has already been proven that the Laplace transform established the Hyers–Ulam stability of the linear differential equation of functions on (0, +) (see [16]).

2. Fourier Transform and Inversion Formula

Throughout this paper, will denote either the real field, , or the complex field, . Assume that is absolutely integrable. Then, the Fourier transform associated to f is a mapping ℱ(f) : defined by
(3)
Also, the inverse Fourier transform associated to a function fL1() is defined by
(4)
By the Fourier Inversion Theorem (see Theorem A.14 in [18]) if fL1() and f and f′ are piecewise continuous on , that is, both are continuous in any finite interval except possibly for a finite number of jump discontinuities, then at each point t where f is continuous,
(5)

In particular, if f, ℱ(f) ∈ L1(), then the abovementioned relation holds almost everywhere on (see Theorem 9.11 in [19]).

In the following, some required properties of the Fourier transform are presented.

Proposition 1. Let fL1(), F = ℱ(f), and u be the step function defined by u(t) = 1 for t ≥ 0 and u(t) = 0 for t < 0. Then,

  • (i)

    ℱ(eztu(t))(w) = (1/iw + z) provided that Re(z) > 0

  • (ii)

  • (iii)

  • (iv)

    ℱ((−it)nf(t))(w) = F(n)(w)

  • (v)

    ℱ(y(n)(t))(w) = (iw)nℱ(y)(w).

Proof. Parts (i)–(iii) are obtained by the definition of Fourier transform. For part (iv), see Theorem 1.6, page 136, in [20]. For part (v), see Theorem 3.3.1, part (f), in [21].

We recall that the convolution of two functions f, gL1() is defined by
(6)
Then, fgL1(), ‖fg1 ≤ ‖f1g1, and
(7)

Moreover, we have the following theorem.

Theorem 1. Let f, gL1(); then,

  • (i)

    ℱ(fg) = ℱ(f)ℱ(g).

  • (ii)

    −1(fg) = ℱ−1(f)∗ℱ−1(g).

  • (iii)

    If either f or g is differentiable, then fg is differentiable. If f exists and is continuous, then (fg)  = fg.

Proof. For part (i), see Theorems 1.3 and 1.5, page 135, in [20]. Part (ii) follows from the definition of ℱ−1 and the Fourier Inversion Theorem. For part (iii), see Proposition 2.1, page 68, in [22].

Note that if u is the step function, then
(8)

The following corollary is deduced from Theorem 1.5, page 135, in [20].

Corollary 1. Let fL1(); then,

(9)

3. Hyers–Ulam Stability of the Linear Differential Equation

Before stating the main theorem, we need the following important proposition.

Proposition 2. Let fL1() and p be a polynomial with the complex roots w0, w1, …, wk−1, k ≥ 1. Then, there is a function y0L1() which is infinitely differentiable in ∖{0}, (k − 1)-times differentiable at zero, and satisfying

(10)

Proof. First assume that and Im(w0) ≠ 0. Put z1 : = −iw0 when Im(w0) > 0 and z2 : = iw0 when Im(w0) < 0. Since Re(zi) > 0, i = 1,2, Proposition 1, part (i), implies that

(11)

In the second case, using part (ii) of Proposition 1 for t0 = 0 and k = −1, we get

(12)

According to the abovementioned computations, the function is defined by

(13)

It satisfies the equation

(14)
and by part (iv) of Proposition 1, we see that
(15)

Now, we put

(16)

Then, y0L1(), by Theorem 1 part (ii), y0 is infinitely differentiable in ∖{0}, exists, and

(17)
for ww0. In the next case, we suppose that Im(w0) = 0, namely, w0 is a real number. In this case, the argument is different. Indeed, let f0 = f and
(18)
for i = 0,1,2, …, k. Then, by Corollary 1, we have
(19)
and so, by (iii) of Proposition 1,
(20)

Hence,

(21)

Continuing in this way, we get

(22)

Therefore,

(23)

Finally, we put y0 : = ikfk. Then, y0 has the requested properties and satisfies in (10) for , and in this case, the proof is completed.

Now, we suppose that p(w) expresses as a product of linear factors

(24)
for some complex number wi, i = 1, …, k and some integer ki, i = 1,2, …, k. Applying the partial fraction decomposition of 1/P(w), we obtain
(25)
where λij is a complex number for i = 1,2, …, k and j = 1,2, …, ni. Considering the first part of proof, there exists a yijL1() which is k-times differentiable on ∖{0} and
(26)
for every integer 1 ≤ ik and 1 ≤ jni. Then, we put
(27)
and use the linearity of Fourier transform and (26) to obtain
(28)

Theorem 2. consider the differential equation

(29)
where a0 is a nonzero scalar such that Re(a0) ≠ 0 and fL1(). Then, there exists a constant M with the following property: for every yL1() and for given ε > 0 satisfying
(30)
there exists a differentiable solution yaL1() of the equation such that .

Proof. Let

(31)

Then,

(32)

Hence,

(33)

By the preceding proposition, there exists a function yaL1() such that

(34)

According to (33), for h = 0, we find that ya, in fact, is a solution of the equation. Without loss of generality, we suppose that Re(a0) > 0. Then, by considering (33) and part (i) of Proposition 1, we obtain

(35)

Consequently, and

(36)

This completes the proof.

We denote by Cn() the space of all n-times differentiable continuous functions on .

Theorem 3. consider the differential equation

(37)
where fL1(), n > 1, and a0, a1, …, an−1 are given scalars such that Re(an−1) ≠ 0. Then, there exists a constant M with the following property: for every yL1() and for given ε > 0 satisfying
(38)
there exists a solution ya of equation (37) such that yaCn()∩L1() and
(39)

Proof. Let

(40)

Applying Proposition 1, part (v), we may derive

(41)
where p is a complex polynomial determined by
(42)

Applying relations (40) and (41) for h = 0, we find that y is a solution of (37) if and only if

(43)

Now, from (41), we deduce that

(44)
where w0, w1, …, wn−1 are the roots of the polynomial p(w). By Proposition 2, there exists a function yaL1() such that
(45)

Since every function satisfying (43) is a solution of (37), we find that ya is a solution of equation (37), and from (44), we obtain

(46)
and consequently,
(47)

By the definition of h and the inequality (38), ‖h1ε, so

(48)

Now, by considering part (i) of Theorem 1, we have

(49)
where
(50)

To see the last relation, looking at (42) and the fact that w0, w1, …, wn−1 are the roots of polynomial p, we get

(51)

Since Re(an−1) ≠ 0, there exist some 0 ≤ jn − 1 such that Re(wj) ≠ 0. Then, by Proposition 1, part (i), there exist some yjL1() such that

(52)

Let q(w) = ∏kj(iwwk). Then,

(53)

Since yjL1(), by Proposition 2, there exist some yjL1() such that

(54)

Comparing the abovementioned relations, we see that

(55)
and hence,
(56)

Therefore, (37) has Hyers–Ulam stability, and the proof is completed.

Remark 1. Note that Proposition 2, in fact, states that equation (37) has a solution in L1() which is infinitely differentiable in ∖{0}, (k − 1)-times differentiable at zero.

Remark 2. In Theorem 2, it is easy to see that M = 1/|Re(a0)| is the minimal Hyers–Ulam constant. To see this, let the assumptions of Theorem 2 hold with the Hyers–Ulam constant M. Suppose that Re(a0) > 0 and δ = Re(a0)ε. Putting , we see that fδL1(), and by Remark 1, the equation y(t) + a0y(t) − fδ(t) = 0 has a solution yδL1() satisfying

(57)

In this case, the function h in the proof of Theorem 2 is obtained by the following equation:

(58)

Applying Theorem 2, there is a solution ya of the equation y + a0yf = 0 such that . Considering the proof of Theorem 2 for and yδ instead of y, we obtain

(59)

Hence, , and considering δ = Re(a0)ε, we obtain (1/Re(a0)) ≤ M.

The following example shows that the condition Re(an−1) ≠ 0 in the abovementioned theorem is necessary and cannot be removed.

Example 1. Every nonzero solution of equation y′(t) − iy(t) = 0 has the form y = λeit which is not in L1(). Hence, y = 0 is the only solution of equation in L1(). Now, for ϵ > 0, consider the function

(60)
which is in L1(). To see this, note that
(61)

On the other hand, for t < 0, . Thus,

(62)

If the equation, y′(t) − iy(t) = 0 has Hyers–Ulam stability, and there must be a solution yaL1() of the differential equation such that and limε⟶0K(ε) = 0. Since the only solution of equation in L1() is zero function, ya = 0, and on the other hand,

(63)

Therefore,

(64)
which is a contradiction with the fact that limε⟶0K(ε) = 0.

4. Conclusions

The main conclusions of this paper are as follows:
  • (1)

    Every differential equation , where fL1(), n > 1, and Re(an−1) ≠ 0 has a n-times differentiable solution in Cn()∩L1()

  • (2)

    Equation (37) is stable on L1() in the sense of Hyers–Ulam

Disclosure

This manuscript has been submitted as a preprint in the following link: http://export.arxiv.org/pdf/2005.03296.

Conflicts of Interest

The authors declare that they have no conflicts of interest.

Data Availability

No data were used to support this study.

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