Volume 2016, Issue 1 7072606
Research Article
Open Access

Various Fixed Point Theorems in Complex Valued b-Metric Spaces

Anil Kumar Dubey

Corresponding Author

Anil Kumar Dubey

Department of Mathematics, Bhilai Institute of Technology, Bhilai House, Durg, Chhattisgarh 491001, India bitdurg.ac.in

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Manjula Tripathi

Manjula Tripathi

Department of Mathematics, U.P.U. Government Polytechnic, Durg, Chhattisgarh 491001, India

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Ravi Prakash Dubey

Ravi Prakash Dubey

Department of Mathematics, Dr. C. V. Raman University, Kota, Bilaspur, Chhattisgarh 495113, India cvru.ac.in

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First published: 03 November 2016
Academic Editor: Yurong Liu

Abstract

We prove some common fixed point results for a pair of mappings which satisfy generalized contractive conditions with rational expressions having point-dependent control functions as coefficients in complex valued b-metric spaces. The results of this paper generalize and extend the several known results in complex valued b-metric spaces. Finally, examples are provided to verify the effectiveness and to usability of our main results.

1. Introduction and Preliminaries

The concept of complex valued metric space was introduced by Azam et al. [1], proving some fixed point results for mappings satisfying a rational inequality in complex valued metric spaces. Since then, several papers have dealt with fixed point theory in complex valued metric spaces (see [210] and references therein). Rao et al. [11] initiated the studying of fixed point results on complex valued b-metric spaces, which was more general than the complex valued metric spaces [1]. Following this paper, a number of authors have proved several fixed point results for various mapping satisfying a rational inequalities in the context of complex valued b-metric spaces (see [1215]) and the related references therein.

Recently, Sintunavarat et al. [8, 9], Sitthikul and Saejung [10], and Singh et al. [7] obtained common fixed point results by replacing the constant of contractive condition to control functions in complex valued metric spaces. In a continuation of [7, 10, 14, 16], in this paper, we establish some common fixed point results for a pair of mappings satisfying more general contractive conditions involving rational expressions having point-dependent control functions as coefficients in complex valued b-metric spaces.

Consistent with Rao et al. [11], the following definitions and results will be needed in the sequel.

Let be the set of complex numbers and . Define a partial order ≾ on as follows:

z1z2 if and only if Re(z1) ≤ Re(z2),   Im(z1) ≤ Im(z2).

Consequently, one can infer that z1z2 if one of the following conditions is satisfied:
  • (i)

    Re(z1) = Re(z2),   Im(z1) < Im(z2).

  • (ii)

    Re(z1) < Re(z2),   Im(z1) = Im(z2).

  • (iii)

    Re(z1) < Re(z2),   Im(z1) < Im(z2).

  • (iv)

    Re(z1) = Re(z2),   Im(z1) = Im(z2).

In particular, we write z1z2 if z1z2 and one of (i), (ii), and (iii) is satisfied and we write z1z2 if only (iii) is satisfied. Notice that
  • (a)

    if 0≾z1z2, then |z1| < |z2|;

  • (b)

    if z1z2 and z2z3, then z1z3;

  • (c)

    if and ab, then azbz for all

The following definition is recently introduced by Rao et al. [11].

Definition 1 (see [11].)Let X be a nonempty set and let s ≥ 1 be a given real number. A function is called a complex valued b-metric on X if for all x, y, zX the following conditions are satisfied:

  • (i)

    0≾d(x, y) and d(x, y) = 0 if and only if x = y.

  • (ii)

    d(x, y) = d(y, x).

  • (iii)

    d(x, y)≾s[d(x, z) + d(z, y)].

The pair (X, d) is called a complex valued b-metric space.

Example 2 (see [11].)If X = [0,1], define a mapping by d(x, y) = |xy|2 + i | xy|2, for all x, yX. Then, (X, d) is complex valued b-metric space with s = 2.

Definition 3 (see [11].)Let (X, d) be a complex valued b-metric space.

  • (i)

    A point xX is called interior point of a set AX whenever there exists such that B(x, r) = {yX : d(x, y)≺r}⊆A.

  • (ii)

    A point xX is called a limit point of a set A whenever for every

  • (iii)

    A subset AX is called an open set whenever each element of A is an interior point of A.

  • (iv)

    A subset AX is called closed set whenever each limit point of A belongs to A.

  • (v)

    The family F = {B(x, r) : xX  and  0≺r} is a subbasis for a Hausdorff topology τ on X.

Definition 4 (see [11].)Let (X, d) be a complex valued b-metric space, and let {xn} be a sequence in X and xX.

  • (i)

    If for every , with 0≺c, there is such that for all n > N,   d(xn, x)≺c, then {xn} is said to be convergent and converges to x. We denote this by limnxn = x or {xn} → x  as  n.

  • (ii)

    If for every , with 0≺c there is such that for all n > N,   d(xn, xn+m)≺c, where , then {xn} is said to be a Cauchy sequence.

  • (iii)

    If every Cauchy sequence in X is convergent in X, then (X, d) is said to be a complete complex valued b-metric space.

Lemma 5 (see [11].)Let (X, d) be a complex valued b-metric space and let {xn} be a sequence in X. Then, {xn} converges to x if and only if |d(xn, x)| → 0 as n.

Lemma 6 (see [11].)Let (X, d) be a complex valued b-metric space and let {xn} be a sequence in X. Then, {xn} is Cauchy sequence if and only if |d(xn, xn+m)| → 0 as n, where .

2. Main Result

Throughout this paper, let (X, d) be a complete complex valued b-metric space and S, T : XX be mappings. In our results, we will use the following family of functions.

Let (X, d) be a complete complex valued b-metric space with the coefficient s ≥ 1 and let S, T : XX be mappings. Let Ψ be the family of all functions ψ : X × X × X → [0,1) such that for all x, yX and for fixed aX,
  • (F1)

    ψ(TSx, y, a) ≤ ψ(x, y, a);

  • (F2)

    ψ(x, STy, a) ≤ ψ(x, y, a).

We start this section with the following observation.

Proposition 7. Let (X, d) be a complex valued b-metric space and let S, T : XX be mappings. Let x0X and define the sequence {xn} by

()
Assume that there exists a mapping αΨ for all x, yX and for a fixed element aX and n = 0,1, 2, …. Then, α(x2n, y, a) ≤ α(x0, y, a) and α(x, x2n+1, a) ≤ α(x, x1, a).

Proof. Let x, yX and n = 0,1, 2, …. Then, we have

()
Similarly, we have
()

Lemma 8 (see [10].)Let {xn} be a sequence in X and h ∈ [0,1). If an = |d(xn, xn+1)| satisfies anhan−1, for all , then {xn} is a Cauchy sequence.

Now, we proceed to establish common fixed point theorems for the general contraction conditions in complex valued b-metric space.

Theorem 9. Let (X, d) be a complete complex valued b-metric space with the coefficient s ≥ 1 and let S, T : XX be mappings. If there exist mappings α, β, γ, δΨ such that for all x, yX and for fixed aX,

()
()
Then, S and T have a unique common fixed point.

Proof. Let x, yX, from (5) we have

()
which implies that
()
Since |1 + d(x, Sx)|≥|d(x, Sx)|,
()
In a similar way, by setting x = Ty in (5), we have
()
Let x0X and the sequence {xn} be defined by (1). We show that {xn} is a Cauchy sequence. From Proposition 7 and for all K = 0,1, 2, …, we obtain
()
which yields that
()
Similarly, one can obtain
()
Let μ = (α(x0, x1, a) + γ(x0, x1, a) + sδ(x0, x1, a))/(1 − β(x0, x1, a) − γ(x0, x1, a) − sδ(x0, x1, a)) < 1.

Since α(x0, x1, a) + β(x0, x1, a) + 2γ(x0, x1, a) + 2sδ(x0, x1, a) < 1, thus we have |d(x2K+2, x2K+1)| ≤ μ | d(x2K, x2K+1)| and |d(x2K+1, x2K)| ≤ μ | d(x2K−1, x2K)|, or in fact

()
Thus, by Lemma 8 we get that this sequence is Cauchy sequence in (X, d). Since X is complete, there exists some uX such that xnu as n. Let, on contrary, uSu; then
()
So by using the triangular inequality and (5), we get
()
This implies that
()
Letting n, it follows that
()
a contradiction, and so |d(u, Su)| = 0; that is, u = Su. It follows similarly that u = Tu. This implies that u is a common fixed point of S and T.

We now prove that this u is unique:

()
Therefore, we have
()
Since α(u, u, a) + 2δ(u, u, a) < 1, we have |d(u, u)| = 0.

Thus, u = u, which proves the uniqueness of common fixed point in X. This concludes the theorem.

Remark 10. If we replace α, β : X × X × X → [0,1) by Λ, E : X → [0,1), with α(x, y, a) = Λ(x)  and  β(x, y, a) = E(x) for all x, yX and so sΛ(x) + E(x) < 1, then we get the result of Theorem 3.1 of Sintunavarat and Kumam [8] (complex valued b-metric space version).

Remark 11. If we set mappings α, β : X × X × X → [0,1) as α(x, y, a) = α and β(x, y, a) = β, where α, β ∈ [0,1) such that sα + β < 1 and for all x, yX, we get Theorem 4 of Azam et al. [1] (complex valued b-metric space version).

Next theorem is presented for single mapping satisfying slightly different conditions.

Theorem 12. Let (X, d) be a complete complex valued b-metric space with the coefficient s ≥ 1 and let T : XX be a mapping. If there exist mappings α, β, γ, δΨ such that for all x, yX and for fixed aX,

()
()
then T has a unique fixed point.

Proof. Let x0X and the sequence {xn} be defined by xn+1 = Txn, where n = 0,1, 2, …. Now we show that {xn} is a Cauchy sequence. From condition (21), we have

()
Therefore,
()
Let μ = (α(x0, x0, a) + γ(x0, x0, a) + sδ(x0, x0, a))/(1 − β(x0, x0, a) − γ(x0, x0, a) − sδ(x0, x0, a)) < 1; then,
()
By Lemma 8, this sequence is Cauchy sequence in (X, d). Since X is complete, there exists some uX such that xnu as n. Next, we show that u is a fixed point of T.

From (21), we have

()
This implies that
()
which on making n reduces to
()
a contradiction, and so |d(u, Tu)| = 0; that is, u = Tu. This implies that u is a fixed point of T.

Uniqueness of fixed point is an easy consequence of condition (22). This completes the proof.

Corollary 13. Let (X, d) be a complete complex valued b-metric space with the coefficient s ≥ 1 and let T : XX be a mapping. If there exist mappings α, β, γ, δΨ such that for all x, yX and for some fixed n,

()
()
then T has a unique fixed point.

Proof. By Theorem 12, there exists vX such that Tnv = v. Then,

()
and so d(Tv, v) = 0. So Tv = v. Therefore, the fixed point of T is unique.

Example 14. Let X = [0,1] and be defined by d(x, y) = i | xy|2 for all x, yX. Then, (X, d) is a complex valued b-metric space with the coefficient s = 2. Now we define self-mappings S, T : XX by S(x) = x/4 and T(y) = y/4. Further, for all x, yX and for fixed a = 1/3 ∈ X, we define the functions α, β, γ, δ : X × X × X → [0,1) by

()
Clearly α(x, y, a) + β(x, y, a) + 2γ(x, y, a) + 2sδ(x, y, a) < 1 for all x, yX and for a fixed a = 1/3 ∈ X.

Now consider
()
That is, α(TSx, y, a) ≤ α(x, y, a) for all x, yX and for a fixed a = 1/3 ∈ X. Now
()
That is, α(x, STy, a) ≤ α(x, y, a) for all x, yX and for a fixed a = 1/3 ∈ X. Similarly, we can show that
()
Now for the verification of inequality (5), it is sufficient to show that (Sx, Ty)≾α(x, y, a)d(x, y).
Consider
()
That is, d(Sx, Ty)≾α(x, y, a)d(x, y) for all x, yX and for fixed a = 1/3 ∈ X. Therefore, all the conditions of Theorem 9 are satisfied, also x = 0 remains fixed under S and T and is indeed unique.

Competing Interests

The authors declare that they have no competing interests.

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