Volume 2014, Issue 1 190821
Research Article
Open Access

The Hierarchical Minimax Inequalities for Set-Valued Mappings

Yen-Cherng Lin

Yen-Cherng Lin

Department of Occupational Safety and Health, College of Public Health, China Medical University, Taichung 40421, Taiwan cmu.edu.tw

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Chin-Tzong Pang

Corresponding Author

Chin-Tzong Pang

Department of Information Management, and Innovation Center for Big Data and Digital Convergence, Yuan Ze University, Chung-Li 32003, Taiwan yzu.edu.tw

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First published: 10 April 2014
Citations: 1
Academic Editor: Ngai-Ching Wong

Abstract

We study the minimax inequalities for set-valued mappings with hierarchical process and propose two versions of minimax inequalities in topological vector spaces settings. As applications, we discuss the existent results of solutions for set equilibrium problems. Some examples are given to illustrate the established results.

1. Introduction and Preliminaries

Let X be a nonempty set in a Hausdorff topological vector space, Z a Hausdorff topological vector space, and CZ a closed convex and pointed cone with apex at the origin with int⁡C; that is, C is properly closed with int⁡C and satisfies λCC, for all λ > 0; C + CC; and C∩(−C) = {0}. The scalar hierarchical minimax inequalities are stated as follows: for given mappings F, G : X × X, under some suitable conditions, the following inequality holds:
For given mappings F, G : X × XZ, the first version of hierarchical minimax theorems states that under some suitable conditions, the following inequality holds:
The second version of hierarchical minimax theorems states that under some suitable conditions, the following inequality holds:

These versions, (Hi-1) and (Hi-2), arise naturally from some minimax theorems in the vector or real-valued settings. We refer to [14] and the references therein.

The notations we use in the above relations are as follows.

Definition 1 (see [1], [3].)Let A be a nonempty subset of Z. A point zA is called a

  • (a)

    minimal point of A if A∩(zC) = {z}; MinA denotes the set of all minimal points of A;

  • (b)

    maximal point of A if A∩(z + C) = {z}; MaxA denotes the set of all maximal points of A;

  • (c)

    weakly minimal point of A if A∩(z − int⁡C) = ; MinwA denotes the set of all weakly minimal points of A;

  • (d)

    weakly maximal point of A if A∩(z + int⁡C) = ; MaxwA denotes the set of all weakly maximal points of A.

We note that, for a nonempty compact set A, both sets MaxA and MinA are nonempty. Furthermore, MinA ⊂ MinwA, MaxA ⊂ MaxwA, AMinA + C, and AMaxAC. Following [3], we denote both Max⁡ and Maxw by max (both Min and Minw by min) in since both Max and Maxw (both Min and Minw) are the same in .

We present some fundamental concepts which will be used in the following.

Definition 2 (see [5], [6].)Let U, V be Hausdorff topological spaces. A set-valued map F : UV with nonempty values is said to be

  • (a)

    upper semicontinuous at x0U if for every x0U and for every open set N containing F(x0) there exists a neighborhood M of x0 such that F(M) ⊂ N;

  • (b)

    lower semicontinuous at x0U if for any net {xν} ⊂ U, xνx0, y0T(x0) implies that there exists net yνT(xν) such that yνy0;

  • (c)

    continuous at x0U if F is upper semicontinuous as well as lower semicontinuous at x0.

We note that if T is upper semicontinuous at x0 and T(x0) is compact, then for any net {xν} ⊂ U, xνx0, and for any net yνT(xν) for each ν there exists y0T(x0) and a subnet such that . We refer to [5, 6] for more details.

Definition 3 (see [3], [7].)Let k ∈ int⁡C and vZ. The Gerstewitz function ξkv : Z is defined by

(1)

Some fundamental properties for the Gerstewitz function are as follows.

Proposition 4 (see [3], [7].)Let k ∈ int⁡C and vZ. The Gerstewitz function ξkv : Z has the following properties:

  • (a)

    ξkv(u) > ruv + rkC;

  • (b)

    ξkv(u) ≥ ruv + rk − int⁡C;

  • (c)

    ξkv(·) is a convex, continuous, and increasing function.

We also need the following different kinds of cone-convexities for set-valued mappings.

Definition 5 (see [1].)Let X be a nonempty convex subset of a topological vector space. A set-valued mapping F : XZ is said to be

  • (a)

    above-C-convex (resp., above-C-concave) on X if, for all x1, x2X and all λ ∈ [0,1],

    (2)

  • (b)

    above-naturally C-quasiconvex on X if, for all x1, x2X and all λ ∈ [0,1],

    (3)
    where co⁡A denotes the convex hull of a set A;

  • (c)

    above-C-convex-like (resp., above-C-concave-like) on X (X is not necessary convex) if, for all x1, x2X and all λ ∈ [0,1], there is an xX such that

    (4)

We note that whenever F is a scalar function and C = +, the mappings in Definition 5 reduce to the classical ones. The following theorem is a special case of the scalar hierarchical minimax theorem by Lin [8].

Theorem 6. Let X be a nonempty compact convex subset of real Hausdorff topological vector space. Let the set-valued mappings F, G, H : X × X such that F(x, y) ⊂ G(x, y) ⊂ H(x, y) for all (x, y) ∈ X × X; ⋃yXF(x, y) and ⋃xXH(x, y) are compact for each xX and for each yX and satisfy the following conditions:

  • (i)

    xF(x, y) is lower semicontinuous on X for each yX and yF(x, y) is above-+-concave on X for each xX;

  • (ii)

    xG(x, y) is above-naturally +-quasiconvex for each yX, and yG(x, y) is lower semicontinuous on X for each xX;

  • (iii)

    xH(x, y) is lower semicontinuous on X for each yX, yH(x, y) is above-+-concave on X for each xX, and yH(x, y) is lower semicontinuous for each xX.

Then one has
(5)

Lemma 7. Let F : X be such that max⁡⋃xXF(x), max⁡⋃xX max⁡F(x), and max⁡F(x) exist for all xX. Then

(6)

Proof. By using the similar technique of Lemma 3.3 [9], we can show that the conclusion is valid.

2. Scalar Hierarchical Minimax Inequalities

We first state the following scalar hierarchical minimax inequalities.

Theorem 8. Let X be a nonempty compact (not necessarily convex) subset of a real Hausdorff topological space. Let the set-valued mappings F, S, T, G : X × X with nonempty compact values such that

  • (i)

    (x, y) ↦ F(x, y) and (x, y) ↦ G(x, y) are upper semicontinuous on X × X;

  • (ii)

    x ↦ max⁡S(x, y) is convex-like for each yX, and y ↦ max⁡T(x, y) is concave-like on Y for each xX;

  • (iii)

    for all (x, y) ∈ X × X, max⁡F(x, y) ≤ max⁡S(x, y) ≤ max⁡T(x, y) ≤ max⁡G(x, y).

Then the relation (s-Hi) holds.

Proof. From (i), we know that both sides of (s-Hi) exist. For any r,

(7)
Define M : XX by
(8)
for all xX. By (i), the set M(x) is closed for all xX. We claim that the whole intersection
(9)
is empty. Indeed, if not, there exists y0 ∈ ⋂xXM(x) such that, for all xX, max⁡F(x, y0) ≥ r. In particular, we choose x = y0; then max⁡F(y0, y0) ≥ r which, with the aid of condition (iii), contradicts the choice of r. Hence, by the compactness of X, there exist x1, x2, …, xmX such that
(10)
Let
(11)
for all xX. Then, by (iii), we have
(12)
This implies that, for each yX, there is such that
(13)
Define two sets as follows:
(14)
By the concave-like property of T, we can see that these two sets are disjoint. For each yX, by the separation theorem, there exists nonzero vector (τ1, τ2, …, τm) ∈ m such that
(15)
for all (z1, z2, …, zm) ∈ L2. Then, and τi > 0 for all i = 1,2, …, m. Let for all i = 1,2, …, m. Then we have
(16)
For each i = 1,2, …, m, by taking zi = r and noting max⁡S(xi, y) ≤ max⁡T(xi, y), we have
(17)
for all yX. Since the mapping x ↦ max⁡S(x, y) is convex-like for each yY, there is x0X such that
(18)
Since max⁡F(x, y) ≤ max⁡S(x, y) for all (x, y) ∈ X × X, we have
(19)
for all yX. By Lemma 7, we know that
(20)
Therefore, the relation (s-Hi) holds.

Theorem 9. Let X be a nonempty compact convex subset of a real Hausdorff topological vector space. Let the set-valued mappings F, G : X × X with nonempty compact values such that

  • (i)

    (x, y) ↦ F(x, y) and (x, y) ↦ G(x, y) are upper semicontinuous on X × X;

  • (ii)

    y ↦ max⁡F(x, y) is quasiconcave for each xX; that is, for each xX, the set {yX : max⁡F(x, y) ≥ r} is convex in X;

  • (iii)

    for all (x, y) ∈ X × X, max⁡F(x, y) ≤ max⁡G(x, y).

Then the relation (s-Hi) holds.

Proof. By (i), we know that both sides of (s-Hi) exist. Choose any r satisfies

(21)
Define W : XX by
(22)
for all xX. By (ii), the set W(x) is convex for all xX. By (iii), we have
(23)
Hence,
(24)
for all xX. By the upper semicontinuity of F, we know that the mapping x ↦ max⁡F(x, y) is upper semicontinuous for each xX. Thus, for each xX, W(x) is closed; hence it is compact. In order to claim that the mapping xW(x) is upper semicontinuous on X, we only need to show that the mapping xW(x) has a closed graph. Since, for any net {(xα, yα)} ⊂ Graph⁡(W) we have the net {(xα, yα)}. converges to some point (x0, y0). Then, for each α, max⁡F(xα, yα) ≥ r. Since the mapping (x, y) ↦ max⁡F(x, y) is upper semicontinuous, we have
(25)
Thus, (x0, y0) ∈ Graph⁡(W). Suppose that W(x) ≠ for all xX. Then, by Kakutani fixed point theorem, the mapping W has a fixed point which is a contradiction to (24). Hence, there is an x0X such that W(x0) = . From this, we know that
(26)
This implies that the relation (s-Hi) holds.

The following examples illustrate Theorems 8 and 9.

Example 10. Let X = {0}∪{1/n : n} and f(x) = x2, g(y) = 1 − y2 for all x, yX. Define F, S, T, G : X × X by F(x, y) = [0, f(x)g(y)], S(x, y) = [−1, f(x)g(y) + 1], T(x, y) = [2, f(x)g(y) + 2], and G(x, y) = [3, f(x)g(y) + 3]. Obviously, all conditions of Theorem 8 hold. Hence the relation (s-Hi) holds. Indeed, by simple calculation, we can see that

(27)

Example 11. Let X = [0,1]. The mappings f, g, F, and G are the same as in Example 10. Then, all conditions of Theorem 9 hold. We can see that both values of min⁡⋃xX max⁡⋃yXF(x, y) and max⁡⋃xXG(x, x) are the same as those in Example 10. Hence the relation (s-Hi) holds.

3. Hierarchical Minimax Inequalities

In this section, we will present two versions of hierarchical minimax inequalities. The following theorem is the first result satisfies the relation (Hi-1).

Theorem 12. Let X be a nonempty compact convex subset of a real Hausdorff topological vector space. Let the set-valued mappings F, G, H : X × XZ with nonempty compact values such that F(x, y) ⊂ G(x, y) ⊂ H(x, y) for all (x, y) ∈ X × Y satisfy the following conditions:

  • (i)

    (x, y) ↦ F(x, y) is upper semicontinuous, yF(x, y) is above-C-concave on Y for each xX, and xF(x, y) is lower semicontinuous on X for each yY;

  • (ii)

    xG(x, y) is above-naturally C-quasiconvex for each yY, and yG(x, y) is lower semicontinuous on Y for each xX;

  • (iii)

    yH(x, y) is lower semicontinuous and above-C-concave on Y for each xX, and xH(x, y) is lower semicontinuous on X for each yY;

  • (iv)

    for each yY,

    (28)

Then the relation (Hi-1) is valid.

Proof. Let Γ(x): = MaxwyYF(x, y) for all xX. From Lemma 2.4 and Proposition  3.5 in [1], the mapping xΓ(x) is upper semicontinuous with nonempty compact values on X. Hence ⋃xXΓ(x) is compact and so is co⁡(⋃xXΓ(x)). Then co⁡(⋃xXΓ(x)) + C is a closed convex set with nonempty interior. Suppose that v ∉ co⁡(⋃xXΓ(x)) + C. By separation theorem, there is a k, ϵ > 0, and a nonzero continuous linear functional ξ : Z such that

(29)
for all uco(⋃xXΓ(x)) and cC. From this we can see that ξC, where C = {g : Z : g(c) ≥ 0  ∀ cC}, and ξ(v) < ξ(u) for all u ∈ co⁡(⋃xXΓ(x)). By Proposition 3.14 of [1], for any xX, there is a and with such that
(30)
Let us choose c = 0 and in (29); we have
(31)
for all xX. Therefore,
(32)
From conditions (i)–(iii), by applying Proposition 3.9 and Proposition  3.13 in [1], all conditions of Theorem 6 hold. Hence, we have
(33)
Since Y is compact, there is yY such that
(34)
Thus,
(35)
and, hence,
(36)
Therefore,
(37)
By taking into account condition (iv), we know that
(38)
Hence, the relation (Hi-1) is valid.

The following example illustrates that Theorem 12 is valid.

Example 13. Let X = [0,1], , and f : X define

(39)
and F, G, H : X × X2define
(40)
for all (x, y) ∈ X × X.

We can easily see that F(x, y) ⊂ G(x, y) ⊂ H(x, y) for all (x, y) ∈ X × Y and conditions (i)–(iii) of Theorem 12 are valid. Now we claim that condition (iv) holds. Indeed,
(41)

Hence, MaxwxXF(x, x) = {0}×[0,1].

On the other hand, ⋃xXH(x, y) = [0,1]×[y2 − 1,0]. Hence,
(42)
Thus, condition (iv) of Theorem 12 holds. By Theorem 12, the relation (Hi-1) is valid. Indeed,
(43)
Hence,
(44)
Thus,
(45)
and hence the conclusion of Theorem 12 is valid.

Theorem 14. Let X be a nonempty compact convex subset of real Hausdorff topological vector space. Let the set-valued mappings F, G, H : X × XZ such that F(x, y) ⊂ G(x, y) ⊂ H(x, y) for all (x, y) ∈ X × X and satisfy the following conditions:

  • (i)

    (x, y) ↦ F(x, y) is continuous with nonempty compact values, and yξkvF(x, y) is above-+-concave on X for each xX and any Gerstewitz function ξkv;

  • (ii)

    xG(x, y) is above-naturally C-quasiconvex for each yX, and yG(x, y) is lower semicontinuous on X for each xX;

  • (iii)

    (x, y) ↦ H(x, y) is upper semicontinuous with nonempty compact values, yξkvH(x, y) is above-+-concave on X for each xX, and xH(x, y) is lower semicontinuous on X for each yX and any Gerstewitz function ξkv;

  • (iv)

    for each yY,

    (46)

Then the relation (Hi-2) is valid.

Proof. Let Γ(x) be defined the same as that in Theorem 12 for all xX. From the process in the proof of Theorem 12, we know that the set ⋃xXΓ(x) is nonempty compact. Suppose that v ∉ ⋃xXΓ(x) + C. For any k ∈ int⁡C, there is a Gerstewitz function ξkv : Z such that

(47)
for all u ∈ ⋃xXΓ(x). Then, for each xX, there is and with such that
(48)
Choosing in (47), we have
(49)
for all xX. Therefore,
(50)

By conditions (i)–(iii), we know that all conditions of Theorem 6 hold for the mappings ξkvF(x, y), ξkvG(x, y), and ξkvH(x, y), and, hence, we have

(51)
Since X is compact, there is a yX such that
(52)
Thus,
(53)
and, hence,
(54)
If vMax⁡⋃yX MinwxXF(x, y), then, by (iv), we have
(55)
which contradicts (54). From this, we can deduce that the relation (Hi-2) is valid.

4. Strong and Weak Solutions for SEP

In our previous work [10], we establish existence of solutions for set equilibrium problems (SEP, for short). Let Y be a Hausdorff topological vector space, and let K be a nonempty compact convex subset of a Hausdorff topological vector space. For a given mapping T : KY and a trimapping F : TK × K × KZ, a weak solution for (SEP) F is a point such that
(56)
for all yK and for some . A strong solution for (SEP) F is a point with some such that
(57)
for all yK. A strong solution is obviously a weak solution for (SEP) for the same mapping.

We recall that a set-valued mapping Ω : XZ is called a KKM mapping if for each finite subset {x1, …, xn} ⊂ X.

Fan Lemma (see [11]). Let Ω : XZ be a KKM mapping with nonempty closed values. If there exists an x0X such that Ω(x0) is a compact set of Z, thenxXΩ(x) ≠ .

We first state that the existent result of weak solution for (SEP) is as follows.

Theorem 15. Let Z be a finite dimensional space and the set-valued mappings F and T are two upper semicontinuous mappings with nonempty compact values such that,

  • (i)

    for each xK, there is sT(x) such that F(s, x, x)⊄− int C;

  • (ii)

    for each xK, the sets {(s, y) ∈ TK × K : F(s, x, y)⊂− int C} and T(x) are convex.

Then (SEP)F has a weak solution.

Proof. Define Ω : KK by

(58)
for all yK. By (i), yΩ(y) for all yK. Hence the set Ω(y) is nonempty for all yK. Next, we claim that the set Ω(y) is closed for all yK. Let a net {xα} ⊂ Ω converge to some point x0. Then there are sαTxα and zαF(xα, xα, y) such that zαZ∖(−int⁡C). By the upper semicontinuities of F and T, the sets TK and F(TK × K × K) are compact. Hence, there is a convergent subnet of {zα} that converges to some point z0. Furthermore, the net has a convergent subnet which converges to some point s0. Again, by the upper semicontinuities of F and T, we have z0T(x0) and z0F(s0, z0, y). Since the set Z∖(−int⁡C) is closed, z0Z∖(−int⁡C). Hence, x0Ω(y), and, thus, Ω(y) is closed for all yK. We next claim that the mapping Ω : KK is a KKM mapping. Indeed, if not, there exist x1, x2, …, xnK and x0 such that
(59)
Then there is where and λi ≥ 0 for all i = 1,2, …, n.

Since , for all i ∈ {1,2, …, n}, choose any siT(x0); we have

(60)
By (ii),
(61)
This implies that
(62)
which contradicts (i). Thus, the mapping Ω : KK is a KKM mapping. By the Fan lemma, the whole intersection
(63)
is nonempty. Any point in the whole intersection is a weak solution for (SEP) F.

For the existence of strong solution for (SEP), we propose the following results.

Theorem 16. Under the framework of Theorem 15, in addition, the mappings A, B, G : TK × K × KZ with nonempty compact values such that

  • (i)

    the mapping sG(s, x, y) is upper semicontinuous mappings for each x, yK;

  • (ii)

    both sets ⋃sT(x)F(s, x, y) and ⋃yKG(s, x, y) are compact for x, yK, sT(x);

  • (iii)

    the mapping s ↦ max⁡B(s, x, y) is concave-like for each x, yK, and the mapping y ↦ max⁡A(s, x, y) is convex-like for each x, yK, sT(x);

  • (iv)

    for each x, yK, sT(x),   max⁡F(s, x, y) ≤ max⁡A(s, x, y) ≤ max⁡B(s, x, y) ≤ max⁡G(s, x, y);

  • (v)

    for each yK, there is an with such that

    (64)

Then (SEP)G has a strong solution.

Proof. According to Theorem 15, we know that (SEP)F has a weak solution. That is, there is an such that

(65)
for all xK and for some . For any k ∈ int⁡C, from Proposition 4, the Gerstewitz function ξk0 satisfies
(66)
Hence, there is such that, for each xK,
(67)
Thus, we have
(68)
By conditions (i)–(v), all conditions of Theorem 6 hold; hence we have
(69)
Since is compact, there is such that
(70)
This implies that
(71)
or
(72)
for all xK. Therefore, (SEP) G has a strong solution.

Finally, we give the following example to illustrate that Theorems 15 and 16 are valid.

Example 17. Let K = [1,2], C = +, Z = , and T : K be defined by T(x) = [0,2x] for all xK. Then we define F, A, B, G : TK × K × K which are defined by

(73)
for all (x, y) ∈ K × K.

Then, the set-valued mappings F and T are two upper semicontinuous mappings with nonempty compact. We can easily see that F(s, x, x)⊄−int⁡C for all xK and if we choose any sT(x)∩[0,1]. So, condition (i) of Theorem 15 holds. It is obvious that condition (ii) of Theorem 15 holds since the mapping
(74)
is linear. Hence (SEP) F has a weak solution by Theorem 15. Indeed, is a weak solution for (SEP) F where we can choose .
Next, we claim that (SEP) G has a strong solution. We can easily deduce that conditions (i), (iii), and (iv) hold. The condition (ii) is valid since
(75)
is compact for x, yK and so is
(76)
for xK, sT(x). Finally, condition (v) of Theorem 16 is valid, since, for each yK, we can choose an with and such that
(77)
Indeed, with is a strong solution for (SEP) G.

Conflict of Interests

The authors declare that there is no conflict of interests regarding the publication of this paper.

Acknowledgments

In this research, the first author was supported by Grant no. NSC102-2115-M-039-001- of the National Science Council of Taiwan (Taiwan). The second author was supported partly by National Science Council of the Republic of China.

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