Volume 2013, Issue 1 364743
Research Article
Open Access

Sequence Spaces Defined by Musielak-Orlicz Function over n-Normed Spaces

M. Mursaleen

M. Mursaleen

Department of Mathematics, Aligarh Muslim University, Aligarh 202002, India amu.ac.in

Search for more papers by this author
Sunil K. Sharma

Sunil K. Sharma

Department of Mathematics, Model Institute of Engineering & Technology, Kot Bhalwal 181122, Jammu and Kashmir, India mietjammu.in

Search for more papers by this author
A. Kılıçman

Corresponding Author

A. Kılıçman

Department of Mathematics and Institute for Mathematical Research, Universiti Putra Malaysia, 43400 Serdang, Selangor, Malaysia upm.edu.my

Search for more papers by this author
First published: 06 November 2013
Citations: 9
Academic Editor: Abdullah Alotaibi

Abstract

In the present paper we introduce some sequence spaces over n-normed spaces defined by a Musielak-Orlicz function = (Mk). We also study some topological properties and prove some inclusion relations between these spaces.

1. Introduction and Preliminaries

An Orlicz function M is a function, which is continuous, nondecreasing, and convex with M(0) = 0, M(x) > 0 for x > 0 and M(x) → as x.

Lindenstrauss and Tzafriri [1] used the idea of Orlicz function to define the following sequence space. Let w be the space of all real or complex sequences x = (xk); then
()
which is called as an Orlicz sequence space. The space M is a Banach space with the norm
()
It is shown in [1] that every Orlicz sequence space M contains a subspace isomorphic to p  (p ≥ 1). The Δ2-condition is equivalent to M(Lx) ≤ kLM(x) for all values of x ≥ 0 and for L > 1. A sequence = (Mk) of Orlicz functions is called a Musielak-Orlicz function (see [2, 3]). A sequence 𝒩 = (Nk) defined by
()
is called the complementary function of a Musielak-Orlicz function . For a given Musielak-Orlicz function , the Musielak-Orlicz sequence space t and its subspace h are defined as follows:
()
where I is a convex modular defined by
()
We consider t equipped with the Luxemburg norm
()
or equipped with the Orlicz norm
()
Let X be a linear metric space. A function p : X is called paranorm if
  • (1)

    p(x) ≥ 0 for all xX,

  • (2)

    p(−x) = p(x) for all xX,

  • (3)

    p(x + y) ≤ p(x) + p(y) for all x, yX,

  • (4)

    (λn) is a sequence of scalars with λnλ      as      n and (xn) is a sequence of vectors with p(xnx) → 0      as      n; then p(λnxnλx) → 0          as      n.

A paranorm p for which p(x) = 0 implies x = 0 is called total paranorm and the pair (X, p) is called a total paranormed space. It is well known that the metric of any linear metric space is given by some total paranorm (see [4], Theorem 10.4.2, pp. 183). For more details about sequence spaces, see [512] and references therein.

A sequence of positive integers θ = (kr) is called lacunary if k0 = 0, 0 < kr < kr+1 and hr = krkr−1 as r. The intervals determined by θ will be denoted by Ir = (kr−1, kr) and qr = kr/kr−1. The space of lacunary strongly convergent sequences Nθ was defined by Freedman et al. [13] as
()

Strongly almost convergent sequence was introduced and studied by Maddox [14] and Freedman et al. [13]. Parashar and Choudhary [15] have introduced and examined some properties of four sequence spaces defined by using an Orlicz function M, which generalized the well-known Orlicz sequence spaces [C, 1, p], [C, 1, p] 0, and [C, 1, p] . It may be noted here that the space of strongly summable sequences was discussed by Maddox [16] and recently in [17].

Mursaleen and Noman [18] introduced the notion of λ-convergent and λ-bounded sequences as follows.

Let be a strictly increasing sequence of positive real numbers tending to infinity; that is,
()
and it is said that a sequence x = (xk) ∈ w is λ-convergent to the number L, called the λ-limit of x if Λm(x) → L as m, where
()
The sequence x = (xk) ∈ w is λ-bounded if sup m | Λm(x)| < . It is well known [18] that if lim mxm = a in the ordinary sense of convergence, then
()
This implies that
()
which yields that lim m Λm  (x) = a and hence x = (xk) ∈ w is λ-convergent to a.
The concept of 2-normed spaces was initially developed by Gähler [19] in the mid 1960s, while for that of n-normed spaces one can see Misiak [20]. Since then, many others have studied this concept and obtained various results; see Gunawan ([21, 22]) and Gunawan and Mashadi [23]. Let n and let X be a linear space over the field 𝕂, where 𝕂 is the field of real or complex numbers of dimension d, where dn ≥ 2. A real valued function ∥·, …, ·∥ on Xn satisfying the following four conditions
  • (1)

    x1, x2, …, xn∥ = 0 if and only if x1, x2, …, xn are linearly dependent in X;

  • (2)

    x1, x2, …, xn∥ is invariant under permutation;

  • (3)

    αx1, x2, …, xn∥ = |α |         x1, x2, …, xn∥ for any α𝕂;

  • (4)

    x + x, x2, …, xn∥ ≤ ∥x, x2, …, xn∥ + ∥x, x2, …, xn

is called an n-norm on X, and the pair (X, ∥·, …, ·∥) is called an n-normed space over the field 𝕂.
For example, if we may take X = n being equipped with the n-norm = the volume of the n-dimensional parallelepiped spanned by the vectors x1, x2, …, xn which may be given explicitly by the formula
()
where xi = (xi1, xi2, …, xin) ∈ n for each i = 1,2, …, n, leting (X, ∥·, …, ·∥) be an n-normed space of dimension dn ≥ 2 and {a1, a2, …, an} be linearly independent set in X, then the following function ∥·,…,·∥ on Xn−1 defined by
()
defines an (n − 1)-norm on X with respect to {a1, a2, …, an}.
A sequence (xk) in an n-normed space (X, ∥·, …, ·∥) is said to converge to some LX if
()
A sequence (xk) in an n-normed space (X, ∥·, …, ·∥) is said to be Cauchy if
()

If every Cauchy sequence in X converges to some LX, then X is said to be complete with respect to the n-norm. Any complete n-normed space is said to be n-Banach space.

Let = (Mk) be a Musielak-Orlicz function, and let p = (pk) be a bounded sequence of positive real numbers. We define the following sequence spaces in the present paper:
()
If we take (x) = x, we get
()
If we take p = (pk) = 1 for all k, we have
()
The following inequality will be used throughout the paper. If 0 ≤ pk ≤ sup pk = H, K = max (1, 2H−1), then
()
for all k and ak, bk. Also for all a.

In this paper, we introduce sequence spaces defined by a Musielak-Orlicz function over n-normed spaces. We study some topological properties and prove some inclusion relations between these spaces.

2. Main Results

Theorem 1. Let = (Mk) be a Musielak-Orlicz function, and let p = (pk) be a bounded sequence of positive real numbers, then the spaces , and are linear spaces over the field of complex number .

Proof. Let , and let α, β. In order to prove the result, we need to find some ρ3 such that

()

Since , there exist positive numbers ρ1, ρ2 > 0 such that

()
Define ρ3 = max (2 | α | ρ1, 2 | β | ρ2). Since (Mk) is nondecreasing, convex function and by using inequality (20), we have
()
Thus, we have . Hence, is a linear space. Similarly, we can prove that wθ(, Λ, p, s, ∥·, …, ·∥) and are linear spaces.

Theorem 2. Let = (Mk) be a Musielak-Orlicz function, and let p = (pk) be a bounded sequence of positive real numbers. Then is a topological linear space paranormed by

()
where H = max (1, sup kpk) < .

Proof. Clearly g(x) ≥ 0 for . Since Mk(0) = 0, we get g(0) = 0. Again if g(x) = 0, then

()
This implies that for a given ϵ > 0, there exist some ρϵ(0 < ρϵ < ϵ) such that
()
Thus,
()
Suppose that (xk) ≠ 0 for each k. This implies that Λk(x) ≠ 0 for each k. Let ϵ → 0, then
()
It follows that
()
which is a contradiction. Therefore, Λk(x) = 0 for each k, and thus (xk) = 0 for each k. Let ρ1 > 0 and ρ2 > 0 be the case such that
()
Let ρ = ρ1 + ρ2; then, by using Minkowski′s inequality, we have
()
Since ρ,   ρ1, and ρ2 are nonnegative, we have
()
Therefore, g(x + y) ≤ g(x) + g(y). Finally we prove that the scalar multiplication is continuous. Let μ be any complex number. By definition,
()
Thus,
()
where 1/t = ρ/|μ|. Since , we have
()
So the fact that scalar multiplication is continuous follows from the above inequality. This completes the proof of the theorem.

Theorem 3. Let = (Mk) be a Musielak-Orlicz function. If for all fixed x > 0, then .

Proof. Let ; then there exists positive number ρ1 such that

()
Define ρ = 2ρ1. Since (Mk) is nondecreasing and convex and by using inequality (20), we have
()
Hence, .

Theorem 4. Let 0 < inf pk = hpk ≤ sup pk = H < and let be Musielak-Orlicz functions satisfying Δ2-condition, then one has

  • (i)

    ;

  • (ii)

    wθ(, Λ, p, s, ∥·, …, ·∥) ⊂ wθ(, Λ, p, s, ∥·, …, ·∥);

  • (iii)

    .

Proof. Let , then we have

()

Let ϵ > 0 and choose δ with 0 < δ < 1 such that Mk(t) < ϵ for 0 ≤ tδ. Let for all k. We can write

()
So, we have
()
For yk > δ,   yk < yk/δ < 1 + yk/δ. Since are nondecreasing and convex, it follows that
()
Since = (Mk) satisfies Δ2-condition, we can write
()
Hence,
()
From (40) and (43), we have . This completes the proof of (i). Similarly we can prove that
()

Theorem 5. Let 0 < h = inf pk = pk < sup pk = H < . Then for a Musielak-Orlicz function = (Mk) which satisfies Δ2-condition, one has

  • (i)

    ;

  • (ii)

    wθ(Λ, p, s, ∥·, …, ·∥) ⊂ wθ(, Λ, p, s, ∥·, …, ·∥);

  • (iii)

    .

Proof. It is easy to prove, so we omit the details.

Theorem 6. Let = (Mk) be a Musielak-Orlicz function and let 0 < h = inf pk. Then if and only if

()
for some t > 0.

Proof. Let . Suppose that (45) does not hold. Therefore, there are subinterval Ir(j) of the set of interval Ir and a number t0 > 0, where

()
such that
()
Let us define x = (xk) as follows:
()
Thus, by (47),. But . Hence, (45) must hold.

Conversely, suppose that (45) holds and let . Then for each r,

()
Suppose that . Then for some number ϵ > 0, there is a number k0 such that for a subinterval Ir(j), of the set of interval Ir,
()
From properties of sequence of Orlicz functions, we obtain
()
which contradicts (45), by using (49). Hence, we get
()

This completes the proof.

Theorem 7. Let = (Mk) be a Musielak-Orlicz function. Then the following statements are equivalent:

  • (i)

    ;

  • (ii)

    ;

  • (iii)

    .

Proof. (i) ⇒ (ii). Let (i) hold. To verify (ii), it is enough to prove

()
Let . Then for ϵ > 0, there exists r ≥ 0, such that
()
Hence, there exists K > 0 such that
()
So, we get .

(ii) ⇒ (iii). Let (ii) hold. Suppose (iii) does not hold. Then for some t > 0

()
and therefore we can find a subinterval Ir(j), of the set of interval Ir, such that
()
Let us define x = (xk) as follows:
()

Then . But by (57), , which contradicts (ii). Hence, (iii) must holds.

(iii) ⇒ (i). Let (iii) hold and suppose that . Suppose that ; then

()
Let t = ∥Λk  (x)/ρ, z1, z2, …, zn−1∥ for each k; then by (59),
()
which contradicts (iii). Hence, (i) must hold.

Theorem 8. Let = (Mk) be a Musielak-Orlicz function. Then the following statements are equivalent:

  • (i)

    ;

  • (ii)

    ;

  • (iii)

    .

Proof. (i) ⇒ (ii). It is obvious.

(ii) ⇒ (iii). Let (ii) hold. Suppose that (iii) does not hold. Then

()
and we can find a subinterval Ir(j), of the set of interval Ir, such that
()
Let us define x = (xk) as follows:
()

Thus, by (62), , but , which contradicts (ii). Hence, (iii) must hold.

(iii) ⇒ (i). Let (iii) hold. Suppose that . Then

()
Again suppose that ; for some number ϵ > 0 and a subinterval Ir(j), of the set of interval Ir, we have
()
Then from properties of the Orlicz function, we can write
()
Consequently, by (64), we have
()
which contradicts (iii). Hence, (i) must hold.

Theorem 9. Let 0 ≤ pkqk for all k and let (qk/pk) be bounded. Then

()

Proof. Let x = (xk) ∈ wθ(, Λ, q, s, ∥·, …, ·∥); write

()
and μk = pk/qk for all k. Then 0 < μk ≤ 1 for all k. Take 0 < μμk for k. Define sequences (uk) and (vk) as follows.

For tk ≥ 1, let uk = tk and vk = 0, and for tk < 1, let uk = 0 and vk = tk. Then clearly for all k, we have

()
Now it follows that and . Therefore,
()
Now for each k,
()
and so
()
Hence, x = (xk) ∈ wθ(, Λ, p, s, ∥·, …, ·∥). This completes the proof of the theorem.

Theorem 10. ( i) If 0 < inf pkpk ≤ 1 for all k, then

()

( ii) If 1 ≤ pk ≤ sup pk = H < , for all k, then

()

Proof. (i) Let x = (xk) ∈ wθ(, Λ, p, s, ∥·, …, ·∥); then

()
Since 0 < inf pkpk ≤ 1, this implies that
()
therefore,
()
Hence,
()
(ii) Let pk ≥ 1 for each k and sup pk < . Let x = (xk) ∈ wθ(, Λ, s, ∥·, …, ·∥); then for each ρ > 0, we have
()
Since 1 ≤ pk ≤ sup pk < , we have
()
Therefore, x = (xk) ∈ wθ(, Λ, p, s, ∥·, …, ·∥), for each ρ > 0. Hence,
()

This completes the proof of the theorem.

Theorem 11. If 0 < inf pkpk ≤ sup pk = H < , for all k, then

()

Proof. It is easy to prove so we omit the details.

Acknowledgment

The authors are very grateful to the referees for their valuable suggestions and comments. The third author also acknowledges the partial support by University Putra Malaysia under the project ERGS 1-2013/5527179.

      The full text of this article hosted at iucr.org is unavailable due to technical difficulties.