1. Introduction and Preliminaries
Recently, the oscillation, nonoscillation, asymptotic behavior, and existence of solutions of different classes of linear and nonlinear second-order difference equations have been studied by many authors; see, for example, [
1–
26] and the references cited therein. Using the Banach fixed point theorem, Jinfa [
5] discussed the existence of a bounded nonoscillatory solution for the second-order neutral delay difference equation with positive and negative coefficients:
(1)
under the condition
p ≠ −1. Luo and Bainov [
13] and M. Migda and J. Migda [
16] considered the asymptotic behaviors of nonoscillatory solutions for the second-order neutral difference equation with maxima:
(2)
and the second-order neutral difference equation:
(3)
respectively. Meng and Yan [
15] studied the existence of bounded nonoscillatory solutions for the second-order nonlinear nonautonomous neutral delay difference equation:
(4)
Applying the cone compression and expansion theorem in Fréchet spaces, Tian and Ge [
21] established the existence of multiple positive solutions of the second-order discrete equation on the half-line:
(5)
with certain boundary value conditions. But to the best of our knowledge, results on multiplicity of unbounded solutions for neutral delay difference equations are very scarce in the literature. Nothing has been done with the existence of uncountably many unbounded positive solutions for (
1)~(
5) and any other second-order neutral delay difference equations:
Inspired and motivated by the results in [
1–
26], in this paper we introduce and study the second-order nonlinear neutral delay difference equation:
(6)
where
τ,
k,
n0 ∈
ℕ,
,
,
, and
(7)
By means of the Banach fixed point theorem and some new techniques, we establish sufficient conditions for the existence of uncountably many unbounded positive solutions of (
6), suggest a few Mann iterative schemes with errors for approximating these unbounded positive solutions, and prove their convergence and the error estimates. The results obtained in this paper extend the result in [
5]. Four nontrivial examples are interested in the text to illustrate the importance of our results.
Throughout this paper, we assume that Δ is the forward difference operator defined by Δ
xn =
xn+1 −
xn,
ℝ = (−
∞, +
∞),
ℝ+ = [0, +
∞),
ℤ,
ℕ0, and
ℕ denote the sets of all integers, nonnegative integers, and positive integers, respectively,
(8)
represents the Banach space of all real sequences on
ℕβ with norm
(9)
It is clear that
A(
N,
M) is a closed and convex subset of
. By a solution of (
6), we mean a sequence
with a positive integer
T ≥
n0 +
τ +
β such that (
6) holds for all
n ≥
T.
The following lemmas play important roles in this paper.
Lemma 1 (see [27].)Let ,, and be four nonnegative sequences satisfying the inequality
(10)
where
,
, lim
n→∞βn = 0, and
. Then lim
n→∞αn = 0.
Lemma 2 (see [11].)Let τ, n0 ∈ ℕ and be a nonnegative sequence. Then
2. Existence of Uncountably Many Unbounded Positive Solutions
Using the Banach fixed point theorem and the Mann iterative schemes with errors, we next discuss the existence of uncountably many unbounded positive solutions of (6), prove that the Mann iterative schemes with errors converge to these unbounded positive solutions, and compute the error estimates between the Mann iterative schemes with errors and the unbounded positive solutions.
Theorem 3. Assume that there exist two constants M and N with M > N > 0 and four nonnegative sequences , and satisfying
(11)
(12)
(13)
(14)
(15)
Then
(a) for any L ∈ (N, M), there exist θ ∈ (0,1) and T ≥ n0 + τ + β such that for each , the Mann iterative sequence with errors generated by the scheme
(16)
converges to an unbounded positive solution
x ∈
A(
N,
M) of (
6) and has the following error estimate:
(17)
where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] such that
(18)
Proof. First of all we show that (a) holds. Set L ∈ (N, M). It follows from (13), (14), and (15) that there exist θ ∈ (0,1) and T ≥ n0 + τ + β satisfying
(19)
(20)
(21)
Define a mapping
by
(22)
for each
. In view of (
11), (
12), (
19), (
20), and (
22), we deduce that for each
and for all
n ≥
T
(23)
which yield that
(24)
which means that
SL is a contraction in
A(
N,
M). It follows from the Banach fixed point theorem that
SL has a unique fixed point
, that is,
(25)
which imply that
(26)
which yields that
(27)
which together with (
21) gives that
is an unbounded positive solution of (
6) in
A(
N,
M). It follows from (
16), (
19), (
21), (
22), and (
24) that for any
m ∈
ℕ0 and
n ≥
T
(28)
which implies that
(29)
That is, (
17) holds. Thus, Lemma
1 and (
17) and (
18) guarantee that lim
m→∞xm =
x.
Next we show that (b) holds. Let L1, L2 ∈ (N, M) and L1 ≠ L2. As in the proof of (a), we deduce similarly that for each c ∈ {1,2} there exist constants θc ∈ (0,1), Tc ≥ n0 + τ + β, and a mapping satisfying (19)~(24), where θ, L, and T are replaced by θc, Lc and Tc, respectively, and the mapping has a fixed point , which is an unbounded positive solution of (6) in A(N, M), that is,
(30)
which together with (
11) and (
17) implies that for
n ≥ max {
T1,
T2}
(31)
which yields that
(32)
that is,
z1 ≠
z2. This completes the proof.
Theorem 4. Assume that there exist two constants M and N with M > N > 0 and four nonnegative sequences , , , and satisfying (11), (12),
(33)
(34)
(35)
Then
(a) for any L ∈ (N, M), there exist θ ∈ (0,1) and T ≥ n0 + τ + β such that for each , the Mann iterative sequence with errors generated by the scheme
(36)
converges to an unbounded positive solution
x ∈
A(
N,
M) of (
6) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M), and
and
are any sequences in [0,1] satisfying (
18);
(b) equation (6) possesses uncountably many unbounded positive solutions in A(N, M).
Proof. Let L ∈ (N, M). It follows from (33)~(35) that there exist θ ∈ (0,1) and T ≥ n0 + τ + β satisfying
(37)
(38)
(39)
Define a mapping
by
(40)
for each
. Using (
11), (
12), (
37), (
38), and (
40), we get that for each
and
n ≥
T
(41)
which imply (
24). Consequently, (
24) means that
SL is a contraction in
A(
N,
M) and has a unique fixed point
, which is also an unbounded positive solution of (
6) in
A(
N,
M). The rest of the proof is similar to the proof of Theorem
3 and is omitted. This completes the proof.
Theorem 5. Assume that there exist three constants a, M, and N with (1 − a)M > N > 0 and four nonnegative sequences , , , and satisfying (11), (12), (33), (34) and
(42)
Then
(a) for any L ∈ (aM + N, M), there exist θ ∈ (0,1) and T ≥ n0 + τ + β such that for any , the Mann iterative sequence with errors generated by the scheme
(43)
converges to an unbounded positive solution
x ∈
A(
N,
M) of (
6) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] satisfying (
18);
(b) equation (6) possesses uncountably many unbounded positive solutions in A(N, M).
Proof. Put L ∈ (aM + N, M). It follows from (33), (34), and (42) that there exist θ ∈ (0,1) and T ≥ n0 + τ + β satisfying
(44)
Define a mapping
by
(45)
for each
. In view of (
11), (
12), and (
44) and (
45), we obtain that for each
and
n ≥
T,
(46)
which give (
24), in turn, which implies that
SL is a contraction in
A(
N,
M) and possesses a unique fixed point
, which is an unbounded positive solution of (
6) in
A(
N,
M). The rest of the proof is similar to that of Theorem
3 and is omitted. This completes the proof.
Theorem 6. Assume that there exist constants a, M, and N with (1 + a)M > N > 0 and four nonnegative sequences , , , and satisfying (11), (12), (33), (34), and
(47)
Then
(a) for any L ∈ (N, (1 + a)M), there exist θ ∈ (0,1) and T ≥ n0 + τ + β such that for any and the Mann iterative sequence with errors generated by (43) converges to an unbounded positive solution x ∈ A(N, M) of (6) and has the error estimate (17), where is an arbitrary sequence in A(N, M), and are any sequences in [0,1] satisfying (18);
(b) equation (6) possesses uncountably many unbounded positive solutions in A(N, M).
Proof. Put L ∈ (N, (1 + a)M). It follows from (33), (34), and (47) that there exist θ ∈ (0,1) and T ≥ n0 + τ + β satisfying
(48)
(49)
(50)
Define a mapping
by (
45). By virtue of (
12), (
45), (
48), and (
50), we easily verify that
(51)
which yield that
SL(
A(
N,
M))⊆
A(
N,
M). The rest of the proof is similar to that of Theorem
5 and is omitted. This completes the proof.
Remark 7. Theorems 3~6 extend and improve Theorem 1 in [5].
3. Examples
In this section we suggest four examples to explain the results presented in Section 2. Note that Theorem 1 in [5] is useless for all these examples.
Example 8. Consider the second-order nonlinear neutral delay difference equation:
(52)
where
τ ∈
ℕ is fixed. Let
n0 = 3,
k = 1,
β = min {3 −
τ, 1},
M and
N two positive constants with
M >
N and
(53)
It is easy to see that (
11), (
12), and (
15) are satisfied. Note that
(54)
(55)
which together with Lemma
2 yield that (
13) and (
14) hold. It follows from Theorem
3 that (
52) possesses uncountably many unbounded positive solutions in
A(
N,
M). On the other hand, for any
L ∈ (
N,
M), there exist
θ ∈ (0,1) and
T ≥
n0 +
τ +
β such that for each
, the Mann iterative sequence with errors
generated by (
16) converges to an unbounded positive solution
x ∈
A(
N,
M) of (
52) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] satisfying (
18).
Example 9. Consider the second-order nonlinear neutral delay difference equation:
(56)
where
τ ∈
ℕ is fixed. Let
n0 = 5,
k = 2,
β = 5 −
τ,
M and
N two positive constants with
M >
N and
(57)
It is clear that (
11), (
12), and (
35) are fulfilled. Note that
(58)
which yields that
(59)
Thus, Theorem
4 guarantees that (
56) possesses uncountably unbounded positive solutions in
A(
N,
M). On the other hand, for any
L ∈ (
N,
M), there exist
θ ∈ (0,1) and
T ≥
τ +
n0 +
β such that the Mann iterative sequence with error
generated by (
36) converges to an unbounded positive solution
x ∈
A(
N,
M) of (
56) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] satisfying (
18).
Example 10. Consider the second-order nonlinear neutral delay difference equation:
(60)
where
τ ∈
ℕ is fixed. Let
n0 = 7,
k = 2,
a = 3/4,
β = min {7 −
τ, 5},
M and
N two positive constants with
M > 4
N and
(61)
It is not difficult to verify that (
11), (
12), and (
42) are fulfilled. Note that
(62)
That is, (
33) and (
34) are satisfied. Consequently Theorem
5 implies that (
60) possesses uncountably many unbounded positive solutions in
A(
N,
M). On the other hand, for any
L ∈ ((3/4)
M +
N,
M), there exist
θ ∈ (0,1) and
T ≥
n0 +
τ +
β such that the Mann iterative sequence with error
generated by (
43) converges to an unbounded positive solution
x ∈
A(
N,
M) of (
60) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] satisfying (
18).
Example 11. Consider the second-order nonlinear neutral delay difference equation:
(63)
where
τ ∈
ℕ is fixed. Let
n0 = 11,
k = 1,
a = −4/5,
β = min {11 −
τ, 7},
M and
N two positive constants with
M > 5
N and
(64)
Obviously, (
11), (
12), and (
50) are satisfied. Note that
(65)
which gives that
(66)
That is, (
33) and (
34) hold. Thus, Theorem
6 shows that (
63) possesses uncountably many unbounded positive solutions in
A(
N,
M). On the other hand, for any
L ∈ (
N,
M/5), there exist
θ ∈ (0,1) and
T ≥
n0 +
τ +
β such that the Mann iterative sequence with error
generated by (
43) converges to an unbounded positive solution
x ∈
A(
N,
M) of (
63) and has the error estimate (
17), where
is an arbitrary sequence in
A(
N,
M) and
and
are any sequences in [0,1] satisfying (
18).
Acknowledgments
This research was supported by the Science Research Foundation of Educational Department of Liaoning Province (L2012380) and Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Education, Science and Technology (2012R1A1A2002165).