Volume 2012, Issue 1 602513
Research Article
Open Access

General Iterative Methods for Equilibrium Problems and Infinitely Many Strict Pseudocontractions in Hilbert Spaces

Peichao Duan

Corresponding Author

Peichao Duan

College of Science, Civil Aviation University of China, Tianjin 300300, China cauc.edu.cn

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Aihong Wang

Aihong Wang

College of Science, Civil Aviation University of China, Tianjin 300300, China cauc.edu.cn

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First published: 09 May 2012
Citations: 1
Academic Editor: Rudong Chen

Abstract

We propose an implicit iterative scheme and an explicit iterative scheme for finding a common element of the set of fixed point of infinitely many strict pseudocontractive mappings and the set of solutions of an equilibrium problem by the general iterative methods. In the setting of real Hilbert spaces, strong convergence theorems are proved. Our results improve and extend the corresponding results reported by many others.

1. Introduction

Let H be a real Hilbert space and let C be a nonempty closed convex subset of H. Let F be a bifunction from C × C to , where is the set of real numbers.

The equilibrium problem for F : C × C is to find xC such that
(1.1)
for all yC. The set of such solutions is denoted by EP (F).
A mapping S of C is said to be a κ-strict pseudocontraction if there exists a constant κ ∈ [0,1) such that
(1.2)
for all x, yC; see [1]. We denote the set of fixed points of S by F(S) (i.e., F(S) = {xC : Sx = x}).
Note that the class of strict pseudocontractions strictly includes the class of nonexpansive mappings which are mapping S  on  C such that
(1.3)
for all x, yC. That is, S is nonexpansive if and only if S is a 0-strict pseudocontraction.

Numerous problems in physics, optimization, and economics reduce to finding a solution of the equilibrium problem. Some methods have been proposed to solve the equilibrium problem (1.1); see, for instance, [24]. In particular, Combettes and Hirstoaga [5] proposed several methods for solving the equilibrium problem. On the other hand, Mann [6], Shimoji and Takahashi [7] considered iterative schemes for finding a fixed point of a nonexpansive mapping. Further, Acedo and Xu [8] projected new iterative methods for finding a fixed point of strict pseudocontractions.

In 2006, Marino and Xu [3] introduced the general iterative method and proved that the algorithm converged strongly. Recently, Liu [2] considered a general iterative method for equilibrium problems and strict pseudocontractions. Tian [9] proposed a new general iterative algorithm combining an L-Lipschitzian and η-strong monotone operator. Very recently, Wang [10] considered a general composite iterative method for infinite family strict pseudocontractions.

In this paper, motivated by the above facts, we introduce two iterative schemes and obtain strong convergence theorems for finding a common element of the set of fixed points of a infinite family of strict pseudocontractions and the set of solutions of the equilibrium problem (1.1).

2. Preliminaries

Throughout this paper, we always write ⇀ for weak convergence and → for strong convergence. We need some facts and tools in a real Hilbert space H which are listed as below.

Lemma 2.1. Let H be a real Hilbert space. There hold the following identities:

  • (i)

    xy2 = ∥x2 − ∥y2 − 2〈xy, y〉, ∀x, yH;

  • (ii)

    tx+(1−t)y2 = tx2 + (1 − t)∥y2t(1 − t)∥xy2,   t ∈ [0,1],   x, yH.

Lemma 2.2 (see [11].)Assume that {αn} is a sequence of nonnegative real numbers such that

(2.1)
where {γn} is a sequence in (0,1) and {δn} is a sequence such that
  • (i)

  • (ii)

Then, lim nαn = 0.

Recall that given a nonempty closed convex subset C of a real Hilbert space H, for any xH, there exists a unique nearest point in C, denoted by PCx, such that

(2.2)
for all yC. Such a PC is called the metric (or the nearest point) projection of H onto C. As known, y = PCx if and only if there holds the relation:
(2.3)

Lemma 2.3 (see [10].)Let A : HH be a L-Lipschitzian and η-strongly monotone operator on a Hilbert space H with L > 0, η > 0, 0 < μ < 2η/L2, and 0 < t < 1. Then, S = (ItμA) : HH is a contraction with contractive coefficient 1 − tτ and τ = (1/2)μ(2ημL2).

Lemma 2.4 (see [1].)Let S : CC be a κ-strict pseudocontraction. Define T : CC by Tx = λx + (1 − λ)Sx for each xC. Then, as λ ∈ [κ, 1), T is a nonexpansive mapping such that F(T) = F(S).

Lemma 2.5 (see [9].)Let H be a Hilbert space and f : HH be a contraction with coefficient 0 < α < 1, and A : HH an L-Lipschitzian continuous operator and η-strongly monotone with L > 0, η > 0. Then for 0 < γ < μη/α:

(2.4)
That is, μAγf is strongly monotone with coefficient μηγα.

Let {Sn} be a sequence of κn-strict pseudo-contractions. Define . Then, by Lemma 2.4, is nonexpansive. In this paper, consider the mapping Wn defined by

(2.5)
where t1, t2, … are real numbers such that 0 ≤ tn < 1. Such a mapping Wn is called a W-mapping generated by and t1, t2, …. It is easy to see Wn is nonexpansive.

Lemma 2.6 (see [7].)Let C be a nonempty closed convex subset of a strictly convex Banach space E, let be nonexpansive mappings of C into itself such that and let t1, t2, … be real numbers such that 0 < tib < 1, for every i = 1,2, …. Then, for any xC and kN, the limit lim nUn,kx exists.

Using Lemma 2.6, one can define the mapping W of C into itself as follows:

(2.6)

Lemma 2.7 (see [7].)Let C be a nonempty closed convex subset of a strictly convex Banach space E. Let be nonexpansive mappings of C into itself such that and let t1, t2, … be real numbers such that 0 < tib < 1,   for all i ≥ 1. If K is any bounded subset of C, then

(2.7)

Lemma 2.8 (see [12].)Let C be a nonempty closed convex subset of a Hilbert space be a family of infinite nonexpansive mappings with , let t1, t2, … be real numbers such that 0 < tib < 1, for every i = 1,2, …. Then .

For solving the equilibrium problem, assume that the bifunction F satisfies the following conditions:

  • (A1)

    F(x, x) = 0 for all xC;

  • (A2)

    F is monotone, that is, F(x, y) + F(y, x) ≤ 0 for any x, yC;

  • (A3)

    for each x, y, zC,   limsup t→0F(tz + (1 − t)x, y) ≤ F(x, y);

  • (A4)

    F(x, ·) is convex and lower semicontinuous for each xC.

Recall some lemmas which will be needed in the rest of this paper.

Lemma 2.9 (see [13].)Let C be a nonempty closed convex subset of H, let F be bifunction from C × C to satisfying (A1)–(A4), and let r > 0 and xH. Then, there exists zC such that

(2.8)

Lemma 2.10 (see [5].)For r > 0,   xH, define a mapping Tr : HC as follows:

(2.9)
for all xH. Then, the following statements hold:
  • (i)

    Tr is single-valued;

  • (ii)

    Tr is firmly nonexpansive, that is, for any x, yH,

(2.10)
  • (iii)

    F(Tr) = EP(F);

  • (iv)

    EP(F) is closed and convex.

Lemma 2.11 (see [14].)Let {xn} and {zn} be bounded sequences in a Banach space and let {βn} be a sequence of real numbers such that 0 < liminf nβn ≤ limsup nβn < 1 for all n = 0,1, 2, …. Suppose that xn+1 = (1 − βn)zn + βnxn for all n = 0,1, 2, … and limsup nzn+1zn∥−∥xn+1xn∥≤0. Then lim nznxn∥ = 0.

Lemma 2.12 (see [4].)Let C, H, F, and Trx be as in Lemma 2.10. Then, the following holds:

(2.11)
for all s, t > 0 and xH.

Lemma 2.13 (see [10].)Let H be a Hilbert space and let C be a nonempty closed convex subset of H, and T : CC a nonexpansive mapping with F(T) ≠ . If {xn} is a sequence in C weakly converging to x and if {(IT)xn} converges strongly to y, then (IT)x = y.

3. Main Result

Throughout the rest of this paper, we always assume that f is a contraction of H into itself with coefficient α ∈ (0,1), and A is a L-Lipschitzian continuous operator and η-strongly monotone on H with L > 0, η > 0. Assume that 0 < μ < 2η/L2 and 0 < γ < μ(η − (μL2/2))/α = τ/α.

Define a mapping . Since both Wn and are nonexpansive, it is easy to get Vn is also nonexpansive. Consider the following mapping Gn on H defined by
(3.1)
where αn ∈ (0,1). By Lemmas 2.3 and 2.10, we have
(3.2)
Since 0 < 1 − αn(τγα) < 1, it follows that Gn is a contraction. Therefore, by the Banach contraction principle, Gn has a unique fixed pointed such that
(3.3)
For simplicity, we will write xn for provided no confusion occurs. Next we prove the sequences {xn} converges strongly to a which solves the variational inequality:
(3.4)
Equivalently, x* = PΩ(IμA + γf)x*.

Theorem 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H and F a bifunction from C × C to satisfying (A1)–(A4). Let Si : CC be a family κi-strict pseudocontractions for some 0 ≤ κi < 1. Assume the set . Let f be a contraction of H into itself with α ∈ (0,1) and let A be a L-Lipschitzian continuous operator and η-strongly monotone with L > 0,   η > 0,   0 < μ < 2η/L2 and 0 < γ < μ(η − (μL2/2))/α = τ/α. For every n, let Wn be the mapping generated by and ti as in (2.5). Let {xn} and {un} be sequences generated by the following algorithm:

(3.5)
If {αn}, {βn}, and {rn} satisfy the following conditions:
  • (i)

    {αn}⊂(0,1), lim nαn = 0;

  • (ii)

    0 < liminf nβn ≤ limsup nβn < 1;

  • (iii)

    {rn}⊂(0, ), liminf nrn > 0.

Then, {xn} converges strongly to a point x* ∈ Ω, which solves the variational inequality (3.4).

Proof. The proof is divided into several steps.

Step 1. Show first that {xn} is bounded.

Take any p ∈ Ω, by (3.5) and Lemma 2.3, we derive that

(3.6)
It follows that ∥xnp∥≤(∥γf(p) − μAp∥)/(τγα).

Hence, {xn} is bounded, so are {un} and {yn}. It follows from the Lipschitz continuity of A that {Axn} and {Aun} are also bounded. From the nonexpansivity of f and Wn, it follows that {f(xn)} and {Wnxn} are also bounded.

Step 2. Show that

(3.7)
Notice that
(3.8)

By Lemma 2.10, we have

(3.9)
It follows that
(3.10)

Thus, from Lemma 2.1 and (3.10), we get

(3.11)
It follows that
(3.12)
Since αn → 0, we have
(3.13)
From (3.8), it is easy to get
(3.14)

Step 3. Show that

(3.15)
(3.16)
This implies that
(3.17)
From condition (ii), (3.13), and (3.14), we have
(3.18)
Notice that
(3.19)
By Lemma 2.7 and (3.18), we get (3.15).

Since {un} is bounded, so there exists a subsequence which converges weakly to x*.

Step 4. Show that x* ∈ Ω.

Since C is closed and convex, C is weakly closed. So, we have x*C.

From (3.15), we obtain . From Lemmas 2.8, 2.4, and 2.13, we have .

By , for all n ≥ 1, we have

(3.20)
It follows from (A2) that
(3.21)
Hence, we get
(3.22)
It follows from condition (iii), (3.13), and (A4) that
(3.23)
For s with 0 < s ≤ 1 and yC, let ys = sy + (1 − s)x*. Since yC and x*C, we obtain ysC and hence F(ys, x*) ≤ 0. So, we have
(3.24)
Dividing by s, we get
(3.25)
Letting s → 0 and from (A3), we get
(3.26)
for all yC  and  x*EP (F).  Hence  x* ∈ Ω.

Step 5. Show that xnx*, where  x* = PΩ(IμA + γf)x*:

(3.27)
Hence, we obtain
(3.28)
It follows that
(3.29)
This implies that
(3.30)
In particular,
(3.31)

Since , it follows from (3.31) that as j. Next, we show that x* solves the variational inequality (3.4).

By the iterative algorithm (3.5), we have

(3.32)
Therefore, we have
(3.33)
that is,
(3.34)
Hence, for p ∈ Ω,
(3.35)

Since IVn is monotone (i.e., 〈xy, (IVn)x − (IVn)y〉 ≥ 0, for all x, yH). This is due to the nonexpansivity of Vn.

Now replacing n in (3.35) with nj and letting j, we obtain

(3.36)

That is, x* ∈ Ω is a solution of (3.4). To show that the sequence {xn} converges strongly to x*, we assume that . By the same processing as the proof above, we derive . Moreover, it follows from the inequality (3.36) that

(3.37)
Interchanging x* and , we get
(3.38)
By Lemma 2.5, adding up (3.37) and (3.38) yields
(3.39)
Hence and, therefore, xnx* as n,
(3.40)
This is equivalent to the fixed point equation:
(3.41)

Theorem 3.2. Let C be a nonempty closed convex subset of a real Hilbert space H and F a bifunction from C × C to satisfying (A1)–(A4). Let Si : CC be a family κi-strict pseudocontractions for some 0 ≤ κi < 1. Assume the set . Let f be a contraction of H into itself with α ∈ (0,1) and let A be a L-Lipschitzian continuous operator and η-strongly monotone with L > 0, η > 0,0 < μ < 2η/L2, and 0 < γ < μ(η − (μL2/2))/α = τ/α. For every n, let Wn be the mapping generated by and 0 < tib < 1. Given x1H, let {xn} and {un} be sequences generated by the following algorithm:

(3.42)
If {αn}, {βn} and {rn} satisfy the following conditions:
  • (i)

    {αn}⊂(0,1), lim nαn = 0 and ;

  • (ii)

    0 < liminf nβn ≤ limsup nβn < 1;

  • (iii)

    {rn}⊂(0, ), liminf nrn > 0 and lim n | rn+1rn | = 0.

Then, {xn} converges strongly to x* ∈ Ω, which solves the variational inequality (3.4).

Proof. The proof is divided into several steps.

Step 1. Show first that {xn} is bounded.

Taking any p ∈ Ω, we have

(3.43)
By induction, we obtain ∥xnp∥≤max  {∥x1p∥, ∥γf(p) − μAp)∥/(ταγ)},   n ≥ 1.  Hence, {xn} is bounded, so are {un} and {yn}. It follows from the Lipschitz continuity of A that {Axn} and {Aun} are also bounded. From the nonexpansivity of f and Wn, it follows that {f(xn)} and {Wnxn} are also bounded.

Step 2. Show that

(3.44)

Observe that

(3.45)
and from (2.5), we have
(3.46)
where M1 = sup n{∥Un+1,n+1unUn,n+1un∥}.

Suppose xn+1 = βnxn + (1 − βn)zn, then zn = (xn+1βnxn)/(1 − βn) = (αnγf(xn)+(IμαnA)ynβnxn)/(1 − βn).

Hence, we have

(3.47)

It follows from (3.45), (3.46), and the above result that

(3.48)
where M2 = sup n{∥γf(xn)∥ + ∥μAyn∥}. Hence, we get
(3.49)
From condition (i), (iii), 0 < tnb < 1, and Lemma 2.12, we obtain
(3.50)
By Lemma 2.11,we have lim nznxn∥ = 0. Thus,
(3.51)

By Lemma 2.12, (3.45) and (3.44), we obtain

(3.52)

Step 3. Show that

(3.53)
Observe that
(3.54)
From condition (i) and (3.5),we can obtain
(3.55)

By Lemma 2.10, we get

(3.56)
This implies that
(3.57)
By nonexpansivity of Wn, we have
(3.58)
It follows from (3.42) that
(3.59)
This implies that
(3.60)
From condition (i), (ii), and (3.44), we have
(3.61)
Further we have ∥xnWnun∥→0. Thus we get
(3.62)

On the other hand, we have

(3.63)
Combining (3.62), the last inequality, and Lemma 2.7, we obtain (3.53).

Step 4. Show that

(3.64)
where x* = PΩ(IμA + γf)x* is a unique solution of the variational inequality (3.4). Indeed, take a subsequence of {xn} such that
(3.65)

Since is bounded, there exists a subsequence of which converges weakly to q. Without loss of generality, we can assume . From (3.53), we obtain .

By the same argument as in the proof of Theorem 3.1, we have q ∈ Ω. Since x* = PΩ(IμA + γf)x*, it follows that

(3.66)

Step 5. Show that

(3.67)
Since
(3.68)
It follows from (3.44) and (3.66) that
(3.69)
This implies that
(3.70)
where M3 = sup nxnx*2, n ≥ 1. It is easily to see that γn = 2αn(ταγ)/(1 − αnαγ). Hence, by Lemma 2.2, the sequence {xn} converges strongly to x*.

Remark 3.3. If F ≡ 0, then Theorem 3.2 reduces to Theorem 3.1 of Wang [10].

Acknowledgments

The authors would like to thank the referee for valuable suggestions to improve the manuscript NSFC Tianyuan Youth Foundation of Mathematics of China (no. 11126136), and the Fundamental Research Funds for the Central Universities (GRANT: ZXH2011C002).

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