Volume 2011, Issue 1 717501
Research Article
Open Access

On Singular Integrals with Cauchy Kernel on Weight Subspaces: The Basicity Property of Sines and Cosines Systems in Weight Spaces

Tofig Isa Najafov

Corresponding Author

Tofig Isa Najafov

Nakhchivan State University, University Campus, AZ 7000 Nakhchivan, Azerbaijan

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Saeed Farahani

Saeed Farahani

Institute of Mathematics and Mechanics, Azerbaijan National Academy of Sciences, AZ 1141 Baku, Azerbaijan

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First published: 24 May 2011
Academic Editor: Shyam Kalla

Abstract

A singular operator with Cauchy kernel on the subspaces of weight Lebesgue space is considered. A sufficient condition for a bounded action of this operator from a subspace to another subspace of weight Lebesgue space of functions is found. These conditions are not identical with Muckenhoupt conditions. Moreover, the completeness, minimality, and basicity of sines and cosines systems are considered.

1. Introduction

Consider the following singular operator with Cauchy kernel:
(1.1)
where fLp,ρ(−π, π), 1 < p < +, is an appropriate density, ρ(t) is a weight function of the form
(1.2)
(titj for ij), are real numbers.
Under Lp,ρ we understand a Lebesgue weight space with the norm
(1.3)

Bounded action of the operator S in the spaces Lp,ρ plays an important role in many problems of mathematics including the theory of bases. This direction has been well developed and treated in the known monographs. We will need the following.

Statement 1. The operator S is bounded in Lp,ρ if and only if the inequalities

(1.4)
are fulfilled.

Concerning this fact a one can see the monograph [1] and papers [24]. Inequalities (1.4) are Muckenhoupt condition with respect to the weight function ρ(t) with degrees pβk. It is known that the classic system of exponents (Z are integers) forms a basis in Lp,ρ if and only if inequalities (1.4) hold (see, e.g., [3, 4]).

It turns that if you consider the singular operator acting on the subspace of the weighted Lebesgue space, then inequality (1.4) is not necessary for the bounded action. At different points of degeneration the change interval of the corresponding exponent is expanded. This paper is devoted to studying these issues.

2. Some Necessary Facts

Let , ω(t)—a weight function of the form
(2.1)
where 0 = τ0 < τ1 < ⋯<τr = π, .
Denote the space of even (odd) functions in Lp,ρ by (), that is,
(2.2)
We′ll need the following identity:
(2.3)
Indeed, we have
(2.4)
For compactness of the notation, we assume e(x) ≡ 1/(1 − eix). Thus,
(2.5)
From this identity, we can easily get the following relations:
(2.6)
The authors of the papers [47] used these relations earlier while establishing the basicity criterion of the system of sines and cosines with linear phases in Lp. Thus, the following is valid.

Lemma 2.1. The following identities are true:

(2.7)

In the similar way, we obtain
(2.8)
Further, we must take into account the following relation:
(2.9)
As a result, we have
(2.10)
(2.11)
Assume
(2.12)
Thus,
(2.13)
In sequel the following lemma is valid.

Lemma 2.2. The following identities are true:

(2.14)

3. Boundedness of Singular Operators on Subspace of Even Functions

Let . We have
(3.1)
where the kernels Ki(t, s), i = 1,2, are determined by the expressions
(3.2)
Continue the weight ω(t) to the interval (−π, 0) by parity and denote by μ:
(3.3)
It is obvious that are the degeneration points of μ(t). Thus, μ(t) = ω(|t|), t ∈ [−π, π], that is,
(3.4)
Accept the denotation
(3.5)
It is easy to see that the following holds
(3.6)
As a result, for μ, we get the representation
(3.7)
It is obvious that the singular integral S boundedly acts in Lp,μ(−π, π) if and only if it boundedly acts in . Statement 1 is valid also in the case if the Cauchy kernel is replaced by the Hilbert kernel (1/sin((φt)/2)). So, assume that the inequalities −1/p < αk < 1/q, , are fulfilled. Then, from Statement 1, we directly get that S boundedly acts from to and so from to Lp,μ. Assume
(3.8)
and consider the integral operator I±:
(3.9)
with the kernel k±(s, t). We have :
(3.10)
where
(3.11)
Consequently,
(3.12)
It is obvious that
(3.13)
where . So, if the inequalities
(3.14)
hold, then from Statement 1 we obtain
(3.15)
where c is a constant independent from f (different in different places). As a result, we get that if the inequalities (3.14) hold, the operator I boundedly acts from to Lp,μ. The same conclusion is true for the operator I+ as well. As a result, we get that while fulfilling the conditions
(3.16)
the operator S boundedly acts from to Lp,μ. On the other hand, it is easily seen that [Sf]  (−t) = [Sf](t). As a result, we get that the operator S boundedly acts from to .
Now, consider the case when α0 = 1/q and αk, , satisfy conditions (3.16). Let p±ɛ = p ± ɛ and q±ɛ be a number conjugated to p±ɛ. It is obvious that the relations
(3.17)
are fulfilled for sufficiently small ɛ > 0. Then, from the previous reasonings we get that the operator S boundedly acts from to . As a result, it follows from the Riesz-Torin theorem (see, e.g., [7, page 144]) that the operator S boundedly acts from to . We get the following.

Statement 2. Let the inequalities

(3.18)
be fulfilled. Then, the operator S boundedly acts from to .

Now, consider the representation of the operator S by the kernel K1(t, s). Having paid attention to the expression
(3.19)
similar to the previous case we establish that the boundedness of the operator S holds also in the case when the change interval of the exponent αr extends by (−1/p, 2 − 1/p). In the conclusion we get that the following main theorem is valid.

Theorem 3.1. Let the weight function ω be defined by the expression (2.1) and assume that the inequalities

(3.20)
are fulfilled. Then the singular operator S:
(3.21)
with Cauchy kernel k(t, s) = 1/(1 − ei(st)), boundedly acts from to , where μ(t) = ω(|t|), t ∈ (−π, π).

4. Boundedness of Singular Operators on Subspace of Odd Functions

Let the weight function ω(t) be defined by expression (2.1) and assume μ(t) ≡ ω(|t|), t ∈ (−π, π). Denote by K(s; t) the following Cauchy-type kernel
(4.1)
Appropriate integral operator denote by 𝒦:
(4.2)
Let the following inequalities
(4.3)
be fulfilled. We have
(4.4)
From (4.3) it follows that −qαk > −1, , and as a result μq/pL1(−π, π). As a result, from Statement 1 we obtain that the integral operator 𝒦 boundedly acts in Lp,μ, if the inequalities (4.3) hold. In particular, it follows that the operator 𝒦 boundedly acts from to Lp,μ, if the inequalities (4.3) are fulfilled, that is,
(4.5)
where c is a constant independent from f. On the other hand for we have
(4.6)
Pay an attention to the relation (2.13), we obtain that [𝒦f](−t) = −[𝒦f](t), t ∈ (−π, π). Then from (4.5) yields
(4.7)
Now, let
(4.8)
be fulfilled. Assume
(4.9)
Denote the integral operator with kernel K±(s; t) by S±, that is,
(4.10)
Taking into account the relation (2.10), for we have
(4.11)
that is,
(4.12)
Take into account the nonparity [𝒦f](t) on (−π, π) we obtain
(4.13)
Let
(4.14)
Consider the operator S+. We have
(4.15)
Thus
(4.16)
Further, we must take into account the expression sin(t/2) ~ t, t ∈ (−π, π). As a result, from the previous relation we have
(4.17)
where
(4.18)
It is clear that for weight function Muckenhoupt condition is fulfilled and applying Statement 1 to the expression (4.17) we obtain
(4.19)
In the similar way we establish the validity of the inequality
(4.20)
If the inequalities (4.8) hold, as a result, we have
(4.21)
Consider the case
(4.22)
Take sufficiently small ɛ > 0 and determine . Acting similarly to the case (par.3) and accept the Riesz-Torin theorem we obtain boundedly acting of the operator 𝒦 from to (since ). Thus, if the following inequalities
(4.23)
are fulfilled, then the operator 𝒦 boundedly acts from to .

Using the identity (2.11) in the similar way we establish that the same conclusion with respect to the operator 𝒦 is true in the case when the change interval of the exponent αr is expanded on (−1 − 1/p, 1/q). As a result, we obtain the validity of the following theorem.

Theorem 4.1. Let the weight function ω be defined by the expression (2.1) and μ(t) ≡ ω(|t|), t ∈ (−π, π). Assume that the inequalities

(4.24)
are fulfilled. Then the singular operator 𝒦:
(4.25)
with Cauchy-type kernel K(s; t) = (1/(1 − ei(st))) − 1/2, boundedly acts from to .

5. Completeness, Minimality, and Basicity of the System of Sines in Weight Space

Consider the system of sines {sinnt}nN. Let conditions (3.20) be fulfilled. It is easy to see that then the system {sinnt}nN is minimal in . The system , 1/p + 1/q = 1, is a biorthogonal system to it. Indeed, it is obvious that is a space conjugated to , and an arbitrary continuous functional lg on , generated by , realized by the formula
(5.1)
where is a complex conjugation.
Take g(t) = ω−1(t)sinnt, nN. We have
(5.2)
Since sinnt ~ t as t → 0 and sinnt ~ πt as tπ for every fixed nN, then from relation (5.2) follows that , if the inequalities
(5.3)
are fulfilled.
Take g(t) = (2/π)ω−1(t)sinnt and denote by ϑn generated by its functional, that is,
(5.4)
It is clear that ϑn(sinkt) = δnk, ∀n, kN, where δnk is a Kronecker′s symbol. Consider
(5.5)
Thus, {sinnt}nNLp,ω, if α0 > −1/p − 1, αr > −1/p − 1, αk > −1/p, . As a result, we obtain that if the inequalities
(5.6)
hold, then the system {sinnt}nN is minimal in .
Now consider the completeness of the system {sinnt}nN in . Suppose that for some ,
(5.7)
holds. We have
(5.8)
It is easy to see that if the inequalities
(5.9)
are fulfilled, then ωL1. Then from the previous relation we get . Since, the system {sinnt}nN is complete in space of continuous on [0, π] functions with sup-norm, which vanishes at the ends of the segment [0, π], then from (5.7) it follows that g(t) = 0 a.e. on (0, π). Consequently, the system {sinnt}nN is complete in . So, the following statement is true.

Statement 3. Let the weight function ω(t) be defined by expression (2.1). The system of sines {sinnt}nN is minimal in , if the inequalities (5.6) are fulfilled. It is complete in , if the inequalities (5.9) are fulfilled. Moreover, it forms a basis in , if the inequalities

(5.10)
hold.

The basicity of system of sines in , when the inequalities (5.10) hold, follows from the basicity of system of exponent in Lp,μ, where μ(t) = ω(|t|), t ∈ (−π, π). The basicity of these systems earlier considered in papers [3, 4, 8, 9].

In the similar way we prove the following statement.

Statement 4. Let the weight function ω(t) defined by expression (2.1). The system of cosines 1 ∪ {cos nt}nN is minimal (forms a basis) in , if the inequalities (5.10) are fulfilled. It is complete in , if the inequalities (5.9) holds.

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