Erratum to “The Partial Inner Product Space Method: A Quick Overview”
The definition of homomorphism given in Section 5.2.2 is incorrect. Here is the exact definition. The rest of the discussion is correct.
- (i)
for every r ∈ I, there exists u ∈ K such that both Aur and exist;
- (ii)
for every u ∈ K, there exists r ∈ I such that both Aur and exist.
Equivalently, for every r ∈ I, there exists u ∈ K such that (r, u) ∈ j(A) and , and for every u ∈ K, there exists r ∈ I with the same property.
Contrary to what is stated in [1, Definition 3.3.4], the condition (1), which is the correct one, does not imply and .
We denote by Hom(VI, YK) the set of all homomorphisms from VI into YK. The following property is easy to prove:
Let A ∈ Hom(VI, YK). Then, f#Ig implies Af#KAg.