Perturbed Keplerian Hamiltonian Systems
Abstract
This paper deals with a class of perturbation planar Keplerian Hamiltonian systems, by exploiting the nondegeneracy properties of the circular solutions of the planar Keplerian Hamiltonian systems, and by applying the implicit function theorem, we show that noncollision periodic solutions of such perturbed system bifurcate from the manifold of circular solutions for the Keplerian Hamiltonian system.
1. Introduction
The essential difficulty in studying this problem is the free action of the S1-group acting on equation (2) (if q is a solution of (2), then qs = q(.+s) is also a solution of (2), for all s ∈ S1). To overcome this difficulty, we seek solutions of equation (2) near the circular orbits of the Keplerian system (3). These circular orbits are the more stable solutions and by exploiting their nondegeneracy property, we neutralize the free action of the S1-group ([9, 10]). The degenerate solutions of the Keplerian problem are the least stable solutions (KAM theory [11]); we cannot dominate the invariance of the problem under the action of the group S1 in the neighborhood of these solutions.
For all, q ∈ Ω, ε ∈ ℝ.
By a noncollision orbit of (6), we mean a solution of (6) such that q(t) = 0 for all t. We will say that q ∈ H1(ℝ/Tℤ, ℝ2) is skew-T/2 periodic if q(t + T/2) = −q(t) for every t. The following result holds.
Theorem 1 (see [7], [8], [12].)There exists ε0 > 0 such that ∀|ε| < ε0, the perturbed system (6), has at least one noncollision symmetric (skew-T/2 periodic) orbit near the circular orbit of (6).
1.1. Bifurcation in the Nondegenerate Case
Lemma 1. The functions Φ belongs to and for all h, k ∈ E1, we have
Proof. The proof is left to the reader.
We now show the following lemma.
Lemma 2. The following statements are equivalent:
- (i)
- (ii)
q(t) = Tu(tT−1) is a noncollision skew − T/2 periodic solution of (6)
Proof. We prove the lemma in two steps:
Step 1. q ∈ C2(ST, ℝ2). The equation, , means for every h ∈ E1,
Therefore,
Let
Hence,
It is clear that
Therefore,
This implies q ∈ H2(sT, ℝ2) and q ∈ C2(ST, ℝ2).
Step 2. q is a noncollision skew −1/2 periodic solution. Since u ∈ Λ1, it is skew-T/2 periodic.
Denote by the orthogonal subspace in to E1 and
From (13), it follows that
Using (V2), one finds that
Hence,
Then,
By substituting in ϕ = 0, we obtain
Moreover,
This completes the proof.
1.2. Finding Critical Points for ϕ(·, ε, T)
We wish to investigate the situation around (q0, 0, T0), q0 ∈ ℤ0 by applying the inverse function theorem. For this, we need to know more about the derivative of and .
Lemma 3. is the Fredholm operator of index zero, .
Proof. Letting , for all h and k in E1, we have
Then,
Hence,
It is easy to verify that ℑ is a compact operator. is the Fredholm operator of index zero.
Thus, the proof is complete.
The preceding lemma implies
We deduce that, cannot be an onto function. The ultimate reason for this lies in the fact that the function ϕ is invariant by the S1− action which sends u(t) into u(t + θ) ∈ S1 and this induces degeneracy in the derivatives. We can estimate by relating to the linearized equation (32) around u. This is done as in the following lemma.
Lemma 4. Let . The following two conditions are equivalent:
- (a)
.
- (b)
h(t) = T0k(tT−1) is a skew −T0/2 periodic solution of
Proof. Let k ∈ E1, such that . By reasoning as in the proof of Lemma 2, we obtain
Set
By substituting (42) in (41), we obtain,
This completes the proof.
More precisely, we have the following lemma.
Lemma 5.
Proof. According to the above lemma, the dimension of is equal to that of the set of the solutions for equation (38). Let h be the solution of (38), and by using the fact that ‖q0‖ = r, equation (38) reduces to
Set
It is easy to see that conditions (a) − (c) define the tangent manifold to . According to the definition of a nondegenerate critical manifold, this means that ℤ0 is a nondegenerate critical:
Therefore,
This completes the proof.
We denote
This is a fact that gives us a considerable simplification.
Lemma 6. For (u, ε, T) close to (u0, 0, T0), the following statements are equivalent:
Proof. is spanned by . The equation ,
Multiplying both sides by and integrating, we get
and if we integrate the first and second terms on the left by parts, we get zero. In the last term, we recognize the time derivative of V(ε, Tu), which integrates away to zero. Finally, we get,
If u is close to u0, in E1, the integral is strictly positive, and, hence, α must be zero.
We now state our main result.
Theorem 2. Let q0 ∈ ℤ0. If
Proof. Set . It is known that ϕuu(u0, 0, T0) is a Fredholm map of index zero. Split E1 into ; then, is an isomorphism of onto itself. By the implicit function theorem, the equation
By Lemma 6, this means that the equation can be solved in E1 as follows in neighborhood of (u0, 0, T0),
We now replace α by more convenient variables.
For any s ∈ S1, set us(t) = u(t + s). If , we also have . We, thus, have an S1-action which leaves our equations invariants, and we wish to find a coordinate system adapted to this group-invariance. For u near u0 ∈ E1, the complex number,
I now claim that we can use (θ, ε, T) as a local coordinate system for near (uo, 0, To). Computing the Jacobian at this point gives
Since
Using Lemma 4 to translate in terms of q and q0, we get the desired result. v is at least a C2 map from into the space C2(S1, ℝ2); it will then have a Taylor expansion.
2. Conclusion
Our goal was to search for noncollision periodic solutions of (2), and we wish to relate them to circular solutions for the nonperturbed system (3). These kinds of systems were restless focus of a number of authors and the references therein [1–5]. We mention in particular, the work of Poincaré, on the three-body problem (these orbitals are called “first-view sort solutions”).
In an effort to organize another piece of work into a paper, we determine the coefficients of the Taylor expansion up to the second order of the noncollision periodic solutions for the perturbed planar Keplerian Hamiltonian system, which is connected to Kepler Hamiltonian systems by a perturbation parameter. This Taylor expansion is made with respect to a perturbation term ε and the period T of the solution.
Conflicts of Interest
The authors declare that they have no conflicts of interest.
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