A Reaction-Diffusion System with Nonlinear Nonlocal Boundary Conditions
Abstract
We consider initial boundary value problem for a reaction-diffusion system with nonlinear and nonlocal boundary conditions and nonnegative initial data. We prove local existence, uniqueness, and nonuniqueness of solutions.
1. Introduction
In the past several decades, many physical phenomena have been formulated into nonlocal mathematical models. Initial boundary value problem for semilinear reaction-diffusion equations and systems with nonlocal boundary conditions has been analyzed by many authors (see, e.g., [1–12] and the references therein). Local and global existence, comparison principle, and various qualitative properties have been discussed.
We note that for max(p, q, m, n) < 1 the nonlinearities in (1) are non-Lipschitzian. The problem of uniqueness and nonuniqueness for different nonlinear parabolic equations and systems with non-Lipschitzian data has been addressed by several authors. See, for example, [13–16] for equations and [17–21] for systems. In particular, the authors of [16] have investigated the uniqueness of solution for a problem (1) with a single equation.
In [7] the authors have considered a problem (1) with ci(x, t) = 1 and ki(x, y, t) = ki(x, y), i = 1,2. They have proved a comparison principal and investigated the blowup properties of the positive solutions. The aim of this paper is to study the uniqueness of the nonnegative solution of the problem (1) for any p, q, m, n > 0.
The plan of this paper is as follows. In the next section we prove a comparison principle; an existence theorem of a local solution is given in Section 3; uniqueness of solutions with nontrivial initial data, uniqueness of solution with trivial initial datum for min(p, q, m, n) ≥ 1; nonuniqueness of solution with trivial initial datum for min(pq, m, n) < 1 are proved in Section 4.
2. Comparison Principle
Let us introduce the definitions of a subsolution and a supersolution. For the remainder of this paper we denote QT = Ω × (0, T), ST = ∂Ω × (0, T).
Definition 1. A pair of nonnegative functions is called a subsolution of problem (1) in QT if
Definition 2. A pair of functions (u, v) is called a solution of (1) in QT if it is both a subsolution and a supersolution of problem (1) in QT.
Definition 3. We say that solution (u, v) of (1) is positive in QT if u > 0 and v > 0 in QT.
To establish the uniqueness results we need a comparison principle. We prove it in a different way, not as in the work of [7].
Theorem 4. Let and be a nonnegative supersolution and a nonnegative subsolution of problem (1) in QT, respectively. Suppose that and or and in if min(p, q, m, n) < 1. If and for , then and in .
Proof. Let be a nonnegative function such that . Then , where ν is the unit outward normal to the lateral boundary of QT. By the definition of a subsolution we have
On the other hand, the supersolution satisfies (4) with reversed inequality. Set . Then we have
Obviously there exists a positive constant M1 such that in . Since c1(x, t), k1(x, y, t) are nonnegative and continuous functions, then there exists a constant M2 > 0 such that 0 ≤ c1(x, t) ≤ M2, 0 ≤ k1(x, y, t) ≤ M2 in and , respectively.
Consider the following backward problem in Qt:
Let s+ = max(s, 0). Then from (5), we get
Applying now Gronwall′s inequality, we conclude that
3. Local Existence
Let {εl} be decreasing to 0 sequence such that 0 < εl < 1. For ɛ = εl let u0ɛ(x), v0ɛ(x) be the functions with the following properties: ; for i < j; u0ɛ(x) → u0(x), v0ɛ(x) → v0(x) as ɛ → 0; for x ∈ ∂Ω.
Theorem 5. For small values of T, (14) has a unique solution in QT.
Proof. We start the proof with the construction of a supersolution of (14). Let max(supΩu0ɛ(x), supΩv0ɛ(x)) ≤ C, C > 0. Denote . Introduce an auxiliary function φ(x) with the following properties:
Consider the following problem:
Let G(x, y; t) denote the Green′s function for the heat equation given by
We claim that A is continuous. In fact, let {(s1k, s2k)} be a sequence in B converging to (s1, s2) ∈ B in . Denote (uk, vk) = A(s1k, s2k). Then we see that
Using Theorem 5, we can prove the following local existence theorem of a solution of problem (1).
Theorem 6. For small values of T (1) has a maximal solution in QT.
Proof. Let ε2 > ε1. It is easy to show that is a supersolution of the problem (14) with ε = ε1. Then , . Using these inequalities and the continuation principle of solutions we deduce that the existence time of (uɛ(x, t), vɛ(x, t)) does not decrease as ε → 0. Let ε → 0, then
Moreover, by dominated convergence theorem, (umax(x, t), vmax(x, t)) satisfies the following equations:
To prove the positiveness of nontrivial solutions we need the following definition.
Definition 7. We say that a function g(x, t) has the property (N) if there exist xk ∈ Ω and tk > 0, k ∈ ℕ such that g(xk, tk) > 0, k ∈ ℕ, and tk → 0 as k → ∞.
Remark 8. Note that if a nonnegative function g(x, t) has no the property (N) then g(x, t) ≡ 0 in Qτ for some τ > 0.
Theorem 9. Let either u0(x) or v0(x) be a nontrivial function in Ω. Supposing that k1(x, ·, t) and k2(x, ·, t) are nontrivial functions for any x ∈ ∂Ω and t ∈ (0, T), c1(x, t) has the property (N) if u0(x) ≡ 0, and c2(x, t) has the property (N) if v0(x) ≡ 0. Let (u(x, t), v(x, t)) be a supersolution of (1) in QT. Then (u(x, t), v(x, t)) is positive in for 0 < t < T.
Proof. Suppose for definiteness that u0(x) is a nontrivial function. We show at first that u(x, t) > 0 in for 0 < t < T. We have
Now we show the positiveness of v(x, t). If v0(x) is a nontrivial function, then v(x, t) > 0 in for 0 < t < T by previous arguments. If v0(x) ≡ 0 we suppose that there exists a constant τ > 0 such that v(x, t) ≡ 0 in Qτ since otherwise we can use the arguments from the beginning of the proof again. But this is a contradiction with the second equation in (1) since u(x, t) > 0 in Qτ and c2(x, t) has the property (N). Hence, we conclude that v(x, t) > 0 in for 0 < t < T.
4. Uniqueness and Nonuniqueness
As a simple consequence of Theorem 4 and Theorem 9 we get the first uniqueness result for problem (1).
Theorem 10. Let problem (1) have a solution in QT with nonnegative initial datum for min(p, q, m, n) ≥ 1 and with positive initial datum under conditions min(p, q, m, n) < 1 and k1(x, ·, t), k2(x, ·, t) are nontrivial functions for any x ∈ ∂Ω and t ∈ (0, T). Then solution of (1) is unique in QT.
Now we show nonuniqueness of solutions of problem (1) with trivial initial datum for min(pq, m, n) < 1.
Theorem 11. Let min(pq, m, n) < 1, u0(x) = v0(x) ≡ 0. Suppose that the maximal solution of problem (1) exists in QT. Assume that at least one of the following conditions is fulfilled:
Proof. In the local existence theorem we constructed a maximal solution (umax(x, t), vmax(x, t)) of (1) in the following way: umax(x, t) = limε→0uε(x, t), vmax(x, t) = limε→0vε(x, t), where (uε(x, t), vε(x, t)) is some positive supersolution of (1). To prove the theorem we construct a nontrivial nonnegative subsolution of some problem with trivial initial datum. By the comparison principle we conclude that , and therefore maximal solution is a nontrivial solution.
Consider at first the case when pq < 1 and c1(x0, t0) > 0, c2(x0, t0) > 0 for some x0 ∈ Ω and 0 ≤ t0 < T. Then there exists a neighborhood U(x0) of x0 in Ω and such that c1(x, t) ≥ c0, c2(x, t) ≥ c0, c0 > 0 for .
Consider the following problem:
Let α = (1 + p)/(1 − pq) > 1, β = (1 + q)(1 − pq) > 1. Denote that
Now consider the case when m < 1 and k1(x, y1, t1) > 0 for any x ∈ ∂Ω and some y1 ∈ ∂Ω, 0 ≤ t1 < T. We will consider the following problem:
Under the made assumption there exists such that k1(x, y, t)>0 for , where V(y1) is some neighborhood of y1 in . Let α > 1/(2(1 − m)) and assume that 0 < ξ0 ≤ 1 and . For points in ∂Ω × [0, δ]×(t1, T0] of coordinates define
By comparison principle for (39) we conclude that , and, respectively, , for (x, t) ∈ Ω × (t1, T0).
The proof in the case n < 1 and k2(x, y2, t2) > 0 for any x ∈ ∂Ω and some y2 ∈ ∂Ω, 0 ≤ t2 < T is similar.
It is easy to get from Theorem 9 and the proof of Theorem 11 the following statement.
Corollary 12. Let the conditions of Theorem 11 hold with ti = 0, i = 0,1, 2. Suppose also that k1(x, ·, t) and k2(x, ·, t) are nontrivial functions for any x ∈ ∂Ω and t ∈ (0, T), c2(x, t) has the property (N) if (32) is realized, and c1(x, t) has the property (N) if (33) is realized. Then maximal solution is positive in for 0 < t < T.
Under the conditions of Corollary 12 for some class of the coefficients ci(x, t) and ki(x, y, t), i = 1,2, we can prove the uniqueness of solution for (1) with trivial initial datum which is positive for all positive times as long as it exists.
Theorem 13. Let the conditions of Corollary 12 hold. Suppose also that there exists t0 > 0 such that for 0 ≤ t ≤ t0 the functions c1(x, t), c2(x, t), k1(x, y, t), and k2(x, y, t) are nondecreasing with respect to t.
Then there exists exactly one solution of problem (1) which is positive in for 0 < t < T.
Proof. Suppose that there exists different from (umax(x, t), vmax(x, t)) solution (u(x, t), v(x, t)) of (1) with trivial initial datum which is a positive in for 0 < t < T. Denote t* = min(t0, T). Due to the conditions of the theorem it is easy to see that u(x, t + τ), v(x, t + τ) is positive supersolution of (1) with trivial initial datum in for any τ ∈ (0, t*). By Theorem 4 we have umax(x, t) ≤ u(x, t + τ), vmax(x, t) ≤ v(x, t + τ) for every 0 ≤ t ≤ t* − τ. Passing to the limit as τ → 0 we get umax(x, t) ≤ u(x, t), vmax(x, t) ≤ v(x, t) for 0 ≤ t ≤ t*. Hence umax(x, t) = u(x, t), vmax(x, t) = v(x, t) in QT.
Note that by Theorem 10, the solution (u(x, t), v(x, t)) of (1) is unique if min(p, q, m, n) ≥ 1. Now we specify our uniqueness result in the case min(pq, m, n) < 1.
Theorem 14. Let the conditions of Corollary 12 fulfill only u0(x)≢0 or v0(x)≢0. Then the solution of (1) is unique.
Proof. To prove the uniqueness of the solution if min(pq, m, n) < 1, it suffices to show that if (u(x, t), v(x, t)) is any solution of (1), then
First, consider the case when 0 < p < 1, 0 < q ≤ 1, 0 < m < 1, and 0 < n ≤ 1. Let
If k1(x, y0, 0) > 0 for any x ∈ ∂Ω and some y0 ∈ ∂Ω we can obtain a contradiction by another way. Indeed,
Since a1 > 0, a2 > 0 in by comparison principle with arguments of Theorems 13 and 4 we conclude that a1 ≥ h1, a2 ≥ h2 in . This implies (46) and completes the proof for the first case.
Now suppose that max(p, q, m, n) > 1. Assume, for example, that 0 < p ≤ 1, q > 1, 0 < m < 1, n > 1. Then, as in the first case, we introduce the functions w1(x, t), w2(x, t). We use the following relations:
Further develop the arguments, as in the first case, only for q = 1, n = 1. Using the linearization of terms with powers greater than 1 in the equations and boundary conditions of (1) as above we can prove the theorem for the remaining cases in a similar way.
Conflict of Interests
The authors declare that there is no conflict of interests regarding the publication of this paper.
Acknowledgments
The authors would like to thank the referees for their valuable comments and suggestions regarding the original paper.