Fixed Points for Weak α-ψ-Contractions in Partial Metric Spaces
Abstract
Recently, Samet et al. (2012) introduced the notion of α-ψ-contractive mappings and established some fixed point results in the setting of complete metric spaces. In this paper, we introduce the notion of weak α-ψ-contractive mappings and give fixed point results for this class of mappings in the setting of partial metric spaces. Also, we deduce fixed point results in ordered partial metric spaces. Our results extend and generalize the results of Samet et al.
1. Introduction
The notion of partial metric is one of the most useful and interesting generalizations of the classical concept of metric. The partial metric spaces were introduced in 1994 by Matthews [1] as a part of the study of denotational semantics of data for networks, showing that the contraction mapping principle can be generalized to the partial metric context for applications in program verification. Later on, many authors studied the existence of several connections between partial metrics and topological aspects of domain theory (see [2–8] and the references therein). On the other hand, some researchers [9, 10] investigated the characterization of partial metric 0-completeness in terms of fixed point theory, extending the characterization of metric completeness [11–14].
Recently, Samet et al. [15] introduced the notion of α-ψ-contractive mappings and established some fixed point results in the setting of complete metric spaces. In this paper, we introduce the notion of weak α-ψ-contractive mappings and give fixed point results for this class of mappings in the setting of partial metric spaces. Also, we deduce fixed point results in ordered partial metric spaces. Our results extend and generalize Theorems 2.1–2.3 of [15] and many others. An application to ordinary differential equations concludes the paper.
2. Preliminaries
-
(p1 x = y⇔p(x, x) = p(x, y) = p(y, y),
-
p2 p(x, x) ≤ p(x, y),
-
p3 p(x, y) = p(y, x),
-
p4 p(x, y) ≤ p(x, z) + p(z, y) − p(z, z).
A partial metric space is a pair (X, p) such that X is a non-empty set and p is a partial metric on X. It is clear that if p(x, y) = 0, then from (p1) and (p2) it follows that x = y. But if x = y, p(x, y) may not be 0. A basic example of a partial metric space is the pair ([0, +∞), p), where p(x, y) = max{x, y} for all x, y ∈ [0, +∞). Other examples of partial metric spaces which are interesting from a computational point of view can be found in [1].
Let (X, p) be a partial metric space. A sequence {xn} in (X, p) converges to a point x ∈ X if and only if p(x, x) = limn→+∞p(x, xn).
A sequence {xn} in (X, p) is called a Cauchy sequence if there exists (and is finite) limn,m→+∞p(xn, xm).
A partial metric space (X, p) is said to be complete if every Cauchy sequence {xn} in X converges, with respect to τp, to a point x ∈ X such that p(x, x) = limn,m→+∞p(xn, xm).
A sequence {xn} in (X, p) is called 0-Cauchy if limn,m→+∞p(xn, xm) = 0. We say that (X, p) is 0-complete if every 0-Cauchy sequence in X converges, with respect to τp, to a point x ∈ X such that p(x, x) = 0.
On the other hand, the partial metric space (ℚ∩[0, +∞), p), where ℚ denotes the set of rational numbers and the partial metric p is given by p(x, y) = max{x, y}, provides an example of a 0-complete partial metric space which is not complete.
It is easy to see that every closed subset of a complete partial metric space is complete.
Lemma 1 (see [1], [16].)Let (X, p) be a partial metric space. Then
- (a)
{xn} is a Cauchy sequence in (X, p) if and only if it is a Cauchy sequence in the metric space (X, ps),
- (b)
a partial metric space (X, p) is complete if and only if the metric space (X, ps) is complete.
Let X be a non-empty set. If (X, p) is a partial metric space and (X, ⪯) is a partially ordered set, then (X, p, ⪯) is called an ordered partial metric space. Then x, y ∈ X are called comparable if x⪯y or y⪯x holds. Let (X, ⪯) be a partially ordered set, and let T : X → X be a mapping. T is a non-decreasing mapping if Tx⪯Ty whenever x⪯y for all x, y ∈ X.
Definition 2 (see [15].)Let T : X → X and α : X × X → [0, +∞). One says that T is α-admissible if
Example 3. Let X = [0, +∞), and define the function α : X × X → [0, +∞) by
3. Main Results
Throughout this paper, the standard notations and terminologies in nonlinear analysis are used. We start the main section by presenting the new notion of weak α-ψ-contractive mappings.
Denote by Ψ the family of non-decreasing functions ψ : [0, +∞)→[0, +∞) such that ψ(t) > 0 and limn→+∞ψn(t) = 0 for each t > 0, where ψn is the nth iterate of ψ.
Remark 4. Notice that the family Ψ used in this paper is larger (less restrictive) than the corresponding family of functions defined in [15], see also next Examples 12–13.
Lemma 5. For every function ψ ∈ Ψ, one has ψ(t) < t for each t > 0.
Definition 6. Let (X, p) be a partial metric space, and let T : X → X be a given mapping. We say that T is a weak α-ψ-contractive mapping if there exist two functions α : X × X → [0, +∞) and ψ ∈ Ψ such that
Remark 7. If T : X → X satisfies the contraction mapping principle, then T is a weak α-ψ-contractive mapping, where α(x, y) = 1 for all x, y ∈ X and ψ(t) = kt for all t ≥ 0 and some k ∈ [0,1).
- (r)
X is α-regular if for each sequence {xn} ⊂ X, such that α(xn, xn+1) ≥ 1 for all n ∈ ℕ and xn → x, we have that α(xn, x) ≥ 1 for all n ∈ ℕ,
- (c)
X has the property (C) with respect to α if for each sequence {xn} ⊂ X, such that α(xn, xn+1) ≥ 1 for all n ∈ ℕ, there exists n0 ∈ ℕ such that α(xm, xn) ≥ 1 for all n > m ≥ n0.
Remark 8. Let X be a non-empty set, and let α : X × X → [0, +∞) be a function. Denote
Obviously, (9) holds if n = m + 1. Assume that (9) holds for some n > m. From (xm, xn), (xn, xn+1) ∈ ℛ, since ℛ is transitive, we get (xm, xn+1) ∈ ℛ. This implies that α(xm, xn+1) ≥ 1, and so α(xm, xn) ≥ 1 for all n > m; that is, X has the property (C) with respect to α.
Remark 9. Let (X, p, ⪯) be an ordered partial metric space, and let α : X × X → [0, +∞) be a function defined by
By Remark 8, X has the property (C) with respect to α. Now, let {xn} be a sequence such that α(xn, xn+1) ≥ 1 for all n ∈ ℕ convergent to some x ∈ X, and then xn⪯xn+1 for all n ∈ ℕ, and hence xn⪯x for all n ∈ ℕ. This implies that α(xn, x) ≥ 1 for all n ∈ ℕ, and so X is α-regular.
Our first result is the following theorem that generalizes Theorem 2.1 of [15].
Theorem 10. Let (X, p) be a complete partial metric space, and let T : X → X be a weak α-ψ-contractive mapping satisfying the following conditions:
- (i)
T is α-admissible,
- (ii)
there exists x0 ∈ X such that α(x0, Tx0) ≥ 1,
- (iii)
X has the property (C) with respect to α,
- (iv)
T is continuous on (X, ps).
Proof. Let x0 ∈ X such that α(x0, Tx0) ≥ 1. Define the sequence {xn} in X by
In the next theorem, which is a proper generalization of Theorem 2.2 in [15], we omit the continuity hypothesis of T. Moreover, we assume 0-completeness of the space.
Theorem 11. Let (X, p) be a 0-complete partial metric space, and let T : X → X be a weak α-ψ-contractive mapping satisfying the following conditions:
- (i)
T is α-admissible,
- (ii)
there exists x0 ∈ X such that α(x0, Tx0) ≥ 1,
- (iii)
X has the property (C) with respect to α,
- (iv)
X is α-regular.
Proof. Let x0 ∈ X such that α(x0, Tx0) ≥ 1. Define the sequence {xn} in X by xn+1 = Txn, for all n ∈ ℕ. Following the proof of Theorem 10, we know that α(xn, xn+1) ≥ 1 for all n ∈ ℕ and that {xn} is a 0-Cauchy sequence in the 0-complete partial metric space (X, p). Consequently, there exists x* ∈ X such that
On the other hand, from α(xn, xn+1) ≥ 1 for all n ∈ ℕ and the hypothesis (iv), we have
Since p(xn, x*), p(xn, xn+1) → 0 as n → +∞, for n great enough, we have
The following example illustrates the usefulness of Theorem 10.
Example 12. Let X = [0, +∞) and p : X × X → [0, +∞) be defined by p(x, y) = max{x, y} for all x, y ∈ X. Clearly, (X, p) is a complete partial metric space. Define the mapping T : X → X by
Now, all the hypotheses of Theorem 10 are satisfied, and so T has a fixed point. Notice that Theorem 10 (also Theorem 11) guarantees only the existence of a fixed point but not the uniqueness. In this example, 0 and 3/2 are two fixed points of T.
Moreover, , and so T is not an α-ψ-contractive mapping in the sense of [15] with respect to the complete metric space (X, ps); that is, Theorem 2.1 of [15] cannot be applied in this case.
Now, we give an example involving a mapping T that is not continuous. Also, this example shows that our Theorem 11 is a proper generalization of Theorem 2.2 in [15].
Example 13. Let X = ℚ∩[0, +∞) and p as in Example 12. Clearly, (X, p) is a 0-complete partial metric space which is not complete. Then, Theorem 10 is not applicable in this case. Define the mapping T : X → X by
Proceeding as in Example 12, the reader can show that all the required hypotheses of Theorem 11 are satisfied, and so T has a fixed point. Here, 0 and 5/2 are two fixed points of T.
Moreover, since (X, ps) is not complete, where ps(x, y) = |x − y| for all x, y ∈ X, we conclude that neither Theorem 2.1 nor Theorem 2.2 of [15] can be applied to cover this case, also because .
- (H)
for all x, y ∈ X with α(x, y) < 1, there exists z ∈ X such that α(x, z) ≥ 1, α(y, z) ≥ 1, and limn→+∞p(Tn−1z, Tnz) = 0.
Theorem 14. Adding condition (H) to the hypotheses of Theorem 10 (resp., Theorem 11), one obtain the uniqueness of the fixed point of T.
Proof. Suppose that x* and y* are two fixed points of T with x* ≠ y*. If α(x*, y*) ≥ 1, using (6), we get
If J is a finite subset of ℕ, then there exists n0 ∈ ℕ such that
This implies that
Then, letting n → +∞, we get
Similarly, using (41) and (6), we get
From Theorems 10 and 11, we obtain the following corollaries.
Corollary 15. Let (X, p) be a complete partial metric space, and let T : X → X be an α-ψ-contractive mapping satisfying the following conditions:
- (i)
T is α-admissible,
- (ii)
there exists x0 ∈ X such that α(x0, Tx0) ≥ 1,
- (iii)
X has the property (C) with respect to α,
- (iv)
T is continuous on (X, ps).
Corollary 16. Let (X, p) be a 0-complete partial metric space, and let T : X → X be an α-ψ-contractive mapping satisfying the following conditions:
- (i)
T is α-admissible,
- (ii)
there exists x0 ∈ X such that α(x0, Tx0) ≥ 1,
- (iii)
X has the property (C) with respect to α,
- (iv)
X is α-regular.
From the proof of Theorem 14, we deduce the following corollaries.
4. Consequences
Now, we show that many existing results in the literature can be deduced easily from our theorems.
4.1. Contraction Mapping Principle
Theorem 18 (Matthews [1]). Let (X, p) be a 0-complete partial metric space, and let T : X → X be a given mapping satisfying
Proof. Let α : X × X → [0, +∞) be defined by α(x, y) = 1, for all x, y ∈ X, and let ψ : [0, +∞)→[0, +∞) be defined by ψ(t) = kt. Then T is an α-ψ-contractive mapping. It is easy to show that all the hypotheses of Corollaries 16 and 17 are satisfied. Consequently, T has a unique fixed point.
4.2. Fixed Point Results in Ordered Metric Spaces
The existence of fixed points in partially ordered sets has been considered in [18]. Later on, some generalizations of [18] are given in [19–24]. Several applications of these results to matrix equations are presented in [18]; some applications to periodic boundary value problems and particular problems are given in [22, 23], respectively.
In this section, we will show that many fixed point results in ordered metric spaces can be deduced easily from our presented theorems.
4.2.1. Ran and Reurings Type Fixed Point Theorem
In 2004, Ran and Reurings proved the following theorem.
Theorem 20 (Ran and Reurings [18]). Let (X, ⪯) be a partially ordered set, and suppose that there exists a metric d in X such that the metric space (X, d) is complete. Let T : X → X be a continuous and non-decreasing mapping with respect to ⪯. Suppose that the following two assertions hold:
- (i)
there exists k ∈ [0,1) such that d(Tx, Ty) ≤ k d(x, y) for all x, y ∈ X with x⪯y,
- (ii)
there exists x0 ∈ X such that x0⪯Tx0,
- (iii)
T is continuous.
From Theorem 10, we deduce the following generalization and extension of the Ran and Reurings theorem in the framework of ordered complete partial metric spaces.
Theorem 21. Let (X, p, ⪯) be an ordered complete partial metric space, and let T : X → X be a non-decreasing mapping with respect to ⪯. Suppose that the following assertions hold:
- (i)
there exists ψ ∈ Ψ such that p(Tx, Ty) ≤ ψ(max{p(x, y), p(x, Tx), p(y, Ty)}) for all x, y ∈ X with x⪯y,
- (ii)
there exists x0 ∈ X such that x0⪯Tx0,
- (iii)
T is continuous on (X, ps).
Proof. Define the function α : X × X → [0, +∞) by
Therefore, all the hypotheses of Theorem 10 are satisfied, and so T has a fixed point.
Example 22. Let X = [0, +∞) and p : X × X → [0, +∞) be defined by p(x, y) = max{x, y} for all x, y ∈ X. Clearly, (X, p) is a complete partial metric space. Define the mapping T : X → X by
4.2.2. Nieto and Rodríguez-López Type Fixed Point Theorem
In 2005, Nieto and Rodríguez-López proved the following theorem.
Theorem 23 (Nieto and Rodríguez-López [22]). Let (X, ⪯) be a partially ordered set, and suppose that there exists a metric d in X such that the metric space (X, d) is complete. Let T : X → X be a non-decreasing mapping with respect to ⪯. Suppose that the following assertions hold:
- (i)
there exists k ∈ [0,1) such that d(Tx, Ty) ≤ k d(x, y) for all x, y ∈ X with x⪯y,
- (ii)
there exists x0 ∈ X such that x0⪯Tx0,
- (iii)
if {xn} is a non-decreasing sequence in X such that xn → x ∈ X as n → +∞, then xn⪯x for all n.
From Theorem 11, we deduce the following generalization and extension of the Nieto and Rodríguez-López theorem in the framework of ordered 0-complete partial metric spaces.
Theorem 24. Let (X, p, ⪯) be an ordered 0-complete partial metric space, and let T : X → X be a non-decreasing mapping with respect to ⪯. Suppose that the following assertions hold:
- (i)
there exists ψ ∈ Ψ such that p(Tx, Ty) ≤ ψ(max{p(x, y), p(x, Tx), p(y, Ty)}) for all x, y ∈ X with x⪯y,
- (ii)
there exists x0 ∈ X such that x0⪯Tx0,
- (iii)
if {xn} is a non-decreasing sequence in X such that xn → x ∈ X as n → +∞, then xn⪯x for all n.
Proof. Define the function α : X × X → [0, +∞) by
Remark 26. To establish the uniqueness of the fixed point, Ran and Reurings, Nieto and Rodríguez-López [18, 22] considered the following hypothesis:
- (u)
for all x, y ∈ X, there exists z ∈ X such that x⪯z and y⪯z.
- (U)
for all x, y ∈ X that are not comparable, there exists z ∈ X such that x⪯z, y⪯z, and limn→+∞p(Tn−1z, Tnz) = 0.
5. Application to Ordinary Differential Equations
In this section, we present a typical application of fixed point results to ordinary differential equations. In fact, in the literature there are many papers focusing on the solution of differential problems approached via fixed point theory (see, e.g., [15, 25, 26] and the references therein). For such a case, even without any additional problem structure, the optimal strategy can be obtained by finding the fixed point of an operator T which satisfies a contractive condition in certain spaces.
- (i)
for all t ∈ I, for all a, b ∈ ℝ with |a | , |b | ≤ 1, we have
()where ψ ∈ Ψ, - (ii)
there exists x0 ∈ C(I) such that ,
- (iii)
for all x ∈ C(I),
()
Theorem 27. Suppose that conditions (i)–(iii) hold. Then (58) has at least one solution x* ∈ C2(I).
Proof. Consider C(I) endowed with the partial metric given by
On the other hand, it is well known that x ∈ C(I), and is a solution of (58), is equivalent to x ∈ C(I) is a solution of the integral equation
Then solving problem (58) is equivalent to finding x* ∈ C(I) that is a fixed point of T. Now, let x, y ∈ C(I) such that ∥x∥∞, ∥y∥∞ ≤ 1. From (i), we have
Note that for all t ∈ I, , which implies that
Then, for all x, y ∈ C(I) such that ∥x∥∞, ∥y∥∞ ≤ 1, we have
Define the function α : C(I) × C(I)→[0, +∞) by
Acknowledgments
This work was supported by the Higher Education Research Promotion and National Research University Project of Thailand, Office of the Higher Education Commission (under Grant no. NRU56000508).