1. Introduction
Inverse spectral analysis involves the problem of restoring a linear operator from some of its spectral parameters. Currently, inverse problems are being studied for certain special classes of ordinary differential operators. The simplest of these is the Sturm-Liouville operator Ly = −y′′ + q(x)y. For the case where it is considered on the whole line or half line, the Sturm-Liouville operator together with the function q(x) has been called a potential. In this direction, Borg [1] gave important results. He showed that, in general, one spectrum does not determine a Sturm-Liouville operator, so the result of Ambarzumyan [2] is an exception to the general rule. In the same paper, Borg showed that two spectra of a Sturm-Liouville operator determine it uniquely. Later, Levinson [3], Levitan [4], and Hochstadt [5] showed that when the boundary condition and one possible reduced spectrum are given, then the potential is uniquely determined. Using spectral data, that is, the spectral function, spectrum, and norming constant, different methods have been proposed for obtaining the potential function in a Sturm-Liouville problem. Such problems were subsequently investigated by other authors [4–6]. On the other hand, inverse problems for regular and singular Sturm-Liouville operators have been extensively studied by [7–15].
The inverse problem for interior spectral data of the differential operator consists in reconstruction of this operator from the known eigenvalues and some information on eigenfunctions at some internal point. Similar problems for the Sturm-Liouville operator and discontinuous Sturm-Liouville problem were formulated and studied in [16, 17].
The main goal of the present work is to study the inverse problem of reconstructing the singular Sturm-Liouville operator on the basis of spectral data of a kind: one spectrum and some information on eigenfunctions at the internal point.
Consider the following singular Sturm-Liouville operator
L satisfying (
1)–(
3):
()
with boundary conditions,
()
()
where
q(
x) is a real-valued function and
q ∈
L2(0,1),
λ spectral parameter,
ℓ ∈
ℕ0,
H ∈
ℝ. The operator
L is self adjoint on the
L2(0,1) and has a discrete spectrum {
λn}.
Let us introduce the second singular Sturm-Liouville operator
satisfying
()
subject to the same boundary conditions (
2), (
3), where
is a real-valued function and
. The operator
is self adjoint on the
L2(0,1) and has a discrete spectrum
.
2. Main Results
Before giving some results concerning the Bessel equation, we should give its physical properties. The total energy of the particle is given by
E =
p2/2
M =
ℏ2k2/2
M =
k2, where
p is its initial or final momentum, and
k the corresponding wave number,
ℏ planck constant,
M particle′s mass, and
E energy. The reduced radial Schrödinger equation for the partial wave of angular momentum
ℓ then reads [
18]
()
When
V = 0, the above equation reduces to the classical Bessel equation in the form
()
This equation has the solution
Jℓ(
r), called the Bessel function.
Eigenvalues of the problem (
1)–(
3) are the roots of (
3). This spectral characteristic satisfies the following asymptotic expression [
19,
20]:
()
where the series
. Next, we present the main results in this paper. When
b = 1/2, we get the following uniqueness Theorem
1.
Theorem 1. If for every n ∈ ℕ one has
()
then
()
In the case b ≠ 1/2, the uniqueness of q(x) can be proved if we require the knowledge of a part of the second spectrum.
Let {
m(
n)}
n∈ℕ be a sequence of natural numbers with a property
()
Lemma 2. Let {m(n)}n∈ℕ be a sequence of natural numbers satisfying (10) and b ∈ (0, 1/2) are so chosen that σ > 2b. If for any n ∈ ℕ
()
then
()
Let {
l(
n)}
n∈ℕ and {
r(
n)}
n∈ℕ be a sequence of natural numbers such that
()
()
and let
μn be the eigenvalues of (
1), (
2), and (
15) and
be the eigenvalues of (
4), (
2), and (
15)
()
Using Mochizuki and Trooshin′s method from Lemma
2 and Theorem
1, we will prove that the following Theorem
3 holds.
Theorem 3. Let {l(n)}n∈ℕ and {r(n)}n∈ℕ be a sequence of natural numbers satisfying (13) and (14), and 1/2 < b < 1 are so chosen that σ1 > 2b − 1, σ2 > 2 − 2b. If for any n ∈ ℕ one has
()
then
()
3. Proof of the Main Results
In this section, we present the proofs of main results in this paper.
Proof of Theorem 1. Before proving Theorem 1, we will mention some results, which will be needed later. We get the initial value problems
()
()
()
()
As known from [
18], Bessel′s functions of the first kind of order
v =
ℓ − 1/2 are
()
and asymptotic formulas for large argument
()
It can be shown [19] that there exists a kernel continuous in the triangle 0 ≤ t ≤ x ≤ 1 such that by using the transformation operator every solution of (18), (19) and (20), (21) can be expressed in the form [8, 21],
()
()
respectively, where the kernel
H(
x,
t)
is the solution of the equation
()
subject to the boundary conditions
()
After the transformations
()
we obtain the following problem:
()
This problem can be solved by using the Riemann method [21].
Multiplying (18) by and (20) by y(x, λ), subtracting and integrating from 0 to 1/2, we obtain
()
The functions
y(
x,
λ) and
satisfy the same initial conditions (
19) and (
21), that is,
()
Let
()
()
If the properties of
y(
x,
λ) and
are considered, the function
K(
λ) is an entire function.
Therefore the condition of Theorem 1 implies
()
and hence
()
In addition, using (24) and (33) for 0 < x < 1,
()
where
M is constant.
Introduce the function
()
By using the asymptotic forms of
y and
y′, we obtain
()
The zeros of
W(
λ) are the eigenvalues of
L and hence it has only simple zeros
λn because of the seperated boundary conditions. From (
38),
W(
λ) is an entire function of order 1/2 of
λ. Since the set of zeros of the entire function
W(
λ) is contained in the set of zeros of
K(
λ), we see that the function
()
is an entire function on the parameter
λ. From (
36), (
38), and (
39), we get
()
So, for all
λ, from the Liouville theorem,
()
or
()
It was proved in [19] that there exists absolutely continuous function such that we have
()
where
()
We are now going to show that
Q(
x) = 0 a.e. on (0, 1/2]. From (
33), (
43) we have
()
This can be written as
()
Let
λ →
∞ along the real axis, by the Riemann-Lebesgue lemma, one should have
()
Thus from the completeness of the functions cos , it follows that
()
But this equation is a homogeneous Volterra integral equation and has only the zero solution. Thus we have obtained
()
or
()
almost everywhere on (0, 1/2]. Therefore Theorem
1 is proved.
Theorem 4. To prove that q(x) = 0 on [1/2, 1) almost everywhere, we should repeat the above arguments for the supplementary problem
()
subject to the boundary conditions
()
Next, we show that Lemma 2 holds.
Proof of Lemma 2. As in the proof of Theorem 1 we can show that
()
where
and
. From the assumption
()
together with the initial condition at 0 it follows that,
()
Next, we will show that
G(
ρ) = 0 on the whole
ρ plane. The asymptotics (
23) imply that the entire function
G(
ρ) is a function of exponential type ≤2
b.
Define the indicator of function G(ρ) by
()
Since
,
from (
23) it follows that
()
Let us denote by
n(
r) the number of zeros of
G(
ρ) in the disk {|
ρ| ≤
r}. According to [
22] set of zeros of every entire function of the exponential type, not identically zero, satisfies the inequality
()
where
n(
r) is the number of zeros of
G(
ρ) in the disk |
ρ| ≤
r. By (
58),
()
From the assumption and the known asymptotic expression (
7) of the eigenvalues
we obtain
()
For the case σ > 2b,
()
The inequalities (
59) and (
62) imply that
G(
ρ) = 0 on the whole
ρ plane.
Similar to the proof of Theorem 1, we have
()
This completes the proof of Lemma
2.
Now we prove that Theorem 3 is valid.
Proof of Theorem 3. From
()
where {
r(
n)}
n∈ℕ satisfies (
14) and
σ2 > 2 − 2
b. Similar to the proof of Lemma
2, we get
()
Thus, it needs to be proved that
a.e on (0,
b]. The eigenfunctions
yn(
x,
λn) and
satisfy the same boundary condition at 1. It means that
()
on [
b, 1] for any
n ∈
ℕ where
ξn are constants.
Let , . From (54) and (66) we obtain
()
We are going to show that inequality (59) fails and consequently, the entire function of exponential type G(ρ) vanishes on the whole ρ-plane. The ρn and sn have the same asymptotics (7). Counting the number of ρn and sn located inside the disc of radius r, we have
()
of
ρn′s and
()
of
sn′s.
This means that
()
Repeating the last part of the proof of Lemma
2, and considering the condition
σ1 > 2
b − 1, we can show that
G(
ρ) = 0 identically on the whole
ρ-plane which implies that
()
and consequently
()
Hence the proof of Theorem 3 is completed.
Acknowledgment
The authors would like to thank the referees for valuable comments in improving the original paper.