Fixed Points of Meromorphic Solutions for Some Difference Equations
Abstract
We investigate fixed points of meromorphic solutions y(z) for the Pielou logistic equation and obtain some estimates of exponents of convergence of fixed points of y(z) and its shifts y(z + n), differences Δy(z) = y(z + 1) − y(z), and divided differences Δy(z)/y(z).
1. Introduction and Results
Recently, a number of papers (including [4–17]) focus on complex difference equations and difference analogues of Nevanlinna’s theory.
Chen [7] obtained the following theorem.
Theorem A. Let P(z), Q(z), and R(z) be polynomials with P(z)Q(z)R(z)≢0 and let y(z) be a finite order transcendental meromorphic solution of (2). Then
Example 1. The function y(z) = z2z/(2z − 1) satisfies the Pielou logistic equation
One of the main purposes in this paper is to study fixed points of meromorphic solutions of the Pielou logistic equation (2).
The problem of fixed points of meromorphic functions is an important one in the theory of meromorphic functions. Many papers and books (including [18–20]) investigate fixed points of meromorphic functions.
Now we consider fixed points of meromorphic functions and their shifts, differences, and divided differences. We see that there are many examples to show that either f(z) may have no fixed point, for example, f1(z) = ez + z or the shift f(z + c) of f(z), or the difference Δcf(z) = f(z + c) − f(z) of f(z) may have only finitely many fixed points; for example, for the function f2(z) = ez + z − 1, its shift f2(z + 1) = eez + z, and its difference Δ2πif2(z) = f2(z + 2πi) − f2(z) = 2πi have only finitely many fixed points. Even if for a meromorphic function of small growth, Chen and Shon show that there exists a meromorphic function f0 such that σ(f0) < 1 and Δcf0(z) = f0(z + c) − f0(z) has only finitely many fixed points (see Theorem 6 of [9]).
A divided difference (f(z + c) − f(z))/f(z) may also have only finitely many fixed points; for example, the function f(z) = zez satisfies that its divided difference (f(z + 1) − f(z))/f(z) = ((z + 1)e − z)/z has only finitely many fixed points. Chen and Shon obtained Theorem B.
Theorem B (see [9].)Let c ∈ ℂ∖{0} be a constant and let f be a transcendental meromorphic function of order of growth σ(f) = σ < 1 or of the form f(z) = h(z)eaz, where a ≠ 0 is a constant and h(z) is a transcendental meromorphic function with σ(h) < 1. Suppose that p(z) is a nonconstant polynomial. Then
From Theorem B, we easily see that under conditions of Theorem B, the divided difference G1(z) = (f(z + c) − f(z))/f(z) has infinitely many fixed points. The previous example f(z) = zez shows that result of Theorem B is sharp.
However, we discover that the properties on fixed points of meromorphic solutions of (2) are very good. We prove the following theorem.
Theorem 2. Let P(z), Q(z), and R(z) be nonzero polynomials such that
- (i)
τ(y(z + n)) = σ(y(z)) ≥ 1 (n = 0,1, …);
- (ii)
if R(z)−(z + 1)Q(z)≢0, then τ(Δy(z)/y(z)) = σ(y(z));
- (iii)
if there is a polynomial h(z) satisfying
()
Remark 3. Generally, τ(f(z)) ≠ τ(f(z + c)) for a meromorphic function f(z) of finite order. For example, the function f1(z) = ez + z satisfies
2. Proof of Theorem 2
We need the following lemmas for the proof of Theorem 2.
Lemma 4 (see [12], [17].)Let w(z) be a nonconstant finite order meromorphic solution of
Remark 5. Using the same method as in the proof of Lemma 4 (see [12]), we can prove that in Lemma 4, if all coefficients bλ(z) of P(z, w) satisfy σ(bλ(z)) = σ1 < σ(w(z)) = σ and if P(z, a)≢0 for a meromorphic function a(z) satisfying T(r, a) = S(r, w), then for a given ε (0 < ε < σ − σ1),
Lemma 6. Suppose that R(z), Q(z), and P(z) satisfy the condition (8) in Theorem 2 and that y(z) is a nonconstant meromorphic function. Then
Proof. Suppose that z0 is a common zero of f1(z) and f2(z). Then f2(z0) = P(z0)y(z0) + Q(z0) = 0. Thus, y(z0) = −Q(z0)/P(z0). Substituting y(z0) = −Q(z0)/P(z0) into f1(z), we obtain
Lemma 7 (see [14].)Let f(z) be a nonconstant finite order meromorphic function. Then
Lemma 8. Let f(z) be a nonconstant finite order meromorphic function. Then
Using the same method as in the proof of Lemma 6, we can prove Lemmas 9 and 10.
Lemma 9. Suppose that R(z), Q(z), and P(z) satisfy the condition (8) in Theorem 2 and that y(z) is a nonconstant meromorphic function. Then
Lemma 10. Suppose that R(z), Q(z), and P(z) satisfy the condition (8) in Theorem 2 and y(z) is a nonconstant meromorphic function. Then
Proof of Theorem 2. (i) We prove that τ(y(z + n)) = σ(y(z)) ≥ 1 (n = 0,1, …). Suppose that n = 0. Set y(z) − z = g(z). So, g(z) is transcendental, T(r, g(z)) = T(r, y(z)) + O(log r), and S(r, g) = S(r, y). Substituting y(z) = g(z) + z into (2), we obtain
Now suppose that n = 1. By (2), we obtain
On the other hand, by f(z) = 1/H(z) and the fact that H(z) is an entire function, we see that
Now suppose that n = 2. By (2), we obtain
(ii) Suppose that R(z)−(z + 1)Q(z)≢0. We prove that τ(Δy(z)/y(z)) = σ(y(z)). By (2), we obtain
Set
(iii) Suppose that there is a polynomial h(z) satisfying
Now we prove that τ(Δy(z)) = σ(y(z)). By (2), we obtain
Now we prove that (53) holds. Suppose that
Using the same method as in the proof of (i), we see that (53) holds.
Thus, Theorem 2 is proved.
Acknowledgments
The first author was supported by the National Natural Science Foundation of China (no. 11171119). The second author was supported by Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Education, Science and Technology (2010-0009646).