Fractional Version of Hermite-Hadamard and Fejér Type Inequalities for a Generalized Class of Convex Functions
Abstract
In the present paper, we deal with some fractional integral inequalities for strongly reciprocally (p, h)-convex functions. We established fractional version of Hermite-Hadamard and Fejér type inequalities for strongly reciprocally (p, h)-convex functions. Our results extend and generalize many exiting results of literate.
1. Introduction
The convex functions nowadays are widely used in many branches of mathematics like optimization theory, functional analysis, and modeling theory [1, 2]. The interesting geometry of convex functions makes its study distinct from other functions. From geometric point of view, a function ψ(x) is convex provided that the line segment connecting any two points of its graph lies on or above the graph of function. The new inequalities in analysis are always appreciable [3, 4].
Since the classical convexity is not enough to attain certain goals in applied mathematics, so the classical convexity has been generalized in many directions. For recent generalizations, one can see [5, 6].
For the class of convex functions, various inequalities have been developed [7, 8], but the most famous inequality is Hermite-Hadamard’s inequality. It is stated as follows:
In [9], Fejér gave the weighted version of Hermite-Hadamard inequality (1) as follows:
The aim of present paper is to establish fractional version of Hermite-Hadamard and Fejér type inequalities for a more generalized class of functions. The present paper is organized as follows: The §2 is concerned with some preliminary material. In Section 3, we give some basic results for strongly reciprocally (p,h)-convex functions, and in Sections 4 and 5, we develop Hermite-Hadamard and Fejér type inequalities, respectively, for strongly reciprocally (p,h)-convex function. Moreover, the last section is devoted for fractional integral inequalities.
2. Preliminaries
In this section, we give a brief review of some preliminaries.
Definition 1 (p-convex set see [10, 11]). A set M = [d1, d2]⊆ℝ\{0} is p -convex set, if
Definition 2 (p-convex function see [10]). Let M = [d1, d2]⊆ℝ\{0} be a p -convex set. A function ψ : M = [d1, d2]⟶ℝ is called p-convex function, if
holds for all x, y ∈ M and j ∈ [0, 1].
Definition 3 (Strongly convex function see [4]). A function ψ : M = [d1, d2]⟶ℝ is called strongly convex function with modulus μ on M, where μ ≥ 0, if
Definition 4 (Strongly p-convex function see [12]). A function ψ : M = [d1, d2]⟶ℝ is called strongly p-convex function, if
holds for all x, y ∈ M and j ∈ [0, 1].
Definition 5 (Harmonic convex set see [11, 13]). A set M = [d1, d2]⊆ℝ\{0} is said to be harmonic convex set, if
for all x, y ∈ M and j ∈ [0, 1].
Definition 6 (Harmonic convex function see [11, 14]). Let M = [d1, d2]⊆ℝ\{0} be the harmonic convex set. A function ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ is harmonic convex function, if
holds for all x, y ∈ M and j ∈ [0, 1].
Definition 7 (p-harmonic convex set see [11, 15]). A set M = [d1, d2]⊆ℝ\{0} is p -harmonic convex set, if
for all x, y ∈ M and j ∈ [0, 1].
Definition 8 (p-harmonic convex function see [11, 15]). Let M = [d1, d2]⊆ℝ\{0} be p-harmonic convex set. A function ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ is p-harmonic convex, if
holds for all x, y ∈ M and j ∈ [0, 1].
Definition 9 (Strongly reciprocally convex function see [16]). Let M be an interval and let μ ∈ (0, ∞). A function ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ is said to be strongly reciprocally convex function with modulus μ on M, if
Definition 10 (Strongly reciprocally p-convex function see [17]). Let M be a p -harmonic convex set and let μ ∈ (0, ∞). A function ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ is said to be strongly reciprocally p-convex function with modulus μ on M, if
Definition 11 (h-convex function see [18]). Choose the functions ψ, h : M = [d1, d2]⟶ℝ that are non-negative; then, ψ is called h-convex function, if
Now, we are ready to introduce a new class of convex functions by generalizing the concept of strongly reciprocally p-convex functions, which we will call strongly reciprocally (p,h)-convex functions.
Definition 12 (Strongly reciprocally (p, h)-convex function). Let M be a p-harmonic convex set and let μ ∈ (0, ∞). A function ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ is said to be strongly reciprocally (p, h)-convex function with modulus μ on M, if
Throughout the paper, for convenience, we represent the class of strongly reciprocally (p, h) convex functions by SR(p, h).
3. Basic Results
This section collects some basic and straight forward facts based on algebraic operations.
The following proposition is concerned about the addition of two functions from SR(p, h).
Proposition 14. Let ψ, σ : M⟶ℝ be two strongly reciprocally (p,h)-convex functions with modulus μ on M; then, ψ + σ : M⟶ℝ is also strongly reciprocally (p,h)-convex function with modulus μ∗ on M, where μ∗ = 2μ.
Proof. We will start by definition of strongly reciprocally (p,h)-convexity of ψ and σ:
which in turns implies that
where μ∗ = 2μ and μ ≥ 0. This completes the proof.
Our next result is concerned with the scalar multiplication of strongly reciprocally (p,h)-convex function.
Proposition 15. Let ψ : M⟶ℝ be a strongly reciprocally (p,h)-convex function; then, for any λ ≥ 0, λψ : M⟶ℝ is also strongly reciprocally (p,h)-convex function with modulus ν∗ on M, where ν∗ = λμ.
Proof. Let λ ≥ 0, ψ ∈ SR(p, h), we obtain
where ν∗ = λμ and μ ≥ 0. This completes the proof.
Proposition 16. Let ψi : M⟶ℝ, where 1 ≤ i ≤ n be in SR(p, h) with modulus μ; then, for λi ≥ 0 where 1 ≤ i ≤ n, the function ψ : M⟶ℝ, where is also in SR(p, h) with modulus γ ≥ 0, where .
Proof. Let M is a p-harmonic convex set. Then, ∀x, y ∈ M and j ∈ [0, 1], we have
where . This completes the proof.
Proposition 17. Let ψi : M⟶ℝ, where 1 ≤ i ≤ n be strongly reciprocally (p,h)-convex functions with modulus μ; then ψ = max{ψi, i = 1, 2, ⋯, n}, is also strongly reciprocally (p,h)-convex functions with modulus μ.
Proof. Let M is p-harmonic convex set. Then ∀x, y ∈ M and j ∈ [0, 1], we have
This completes the proof.
Our next intension is to develop Hermite-Hadamard’s inequality for this generalization.
4. Hermite-Hadamard Type Inequality
Theorem 18. Let M ⊂ ℝ\{0} be an interval. If ψ : M⟶ℝ be a strongly reciprocally (p,h)-convex function with modulus μ ≥ 0 and ψ ∈ L[d1, d2], then for h(1/2) ≠ 0, we have
Proof. Since, ψ ∈ SR(p, h), and allowing j = 1/2 yields
Let and and integrating (21) w.r.t j over [0, 1], we obtain
and
which gives one side of (20).
For the right side of (20), since ψ ∈ SR(p, h), so by setting x = d1 and y = d2, we obtain the following result:
Integrating (24) w.r.t j over [0, 1], we obtain
and
which is right side of (20), which completes the proof.
Remark 19.
- (1)
Inserting h(j) = j and p = 1 in Theorem 18, we obtained Hermite-Hadamard inequality for strongly reciprocally convex function [16] (Theorem 3.1)
- (2)
Insertion h(j) = j, p = 1, and μ = 0 in Theorem 18 yields Hermite-Hadamard inequality for harmonic convex functions [14] (Theorem 2.4)
Now, we develop Fejér type inequality for this new class of convex functions.
5. Fejér Type Inequality
Theorem 20. Let M ⊂ ℝ\{0} be an interval. If ψ : M⟶ℝ be a strongly reciprocally (p,h)-convex function with modulus μ ≥ 0, then for h(1/2) ≠ 0, we have
holds for d1, d2 ∈ M with d1 ≤ d2 and ψ ∈ L[d1, d2], where w : M⟶ℝ is a non-negative integrable function that satisfies
Proof. Since ψ ∈ SR(p, h), and allowing j = 1/2 yields
Inserting and in (29), we obtain
Since, w is a non-negative symmetric and integrable function, so
Integrating inequality (31) w.r.t j over [0, 1], we obtain
and
so,
which is left side of (27).
which is the right side of inequality (27); this completes the proof.
6. Fractional Integral Inequalities
Fractional integral inequalities are important to study means [19–22]. This section is devoted for some fractional integral inequalities for functions whose derivatives are in SR(p, h). A source for results of the desired type is the following lemma.
Lemma 22 see ([23], Lemma 2.1). Let ψ : M = [d1, d2]⊆ℝ is differentiable defined on the interior M of M. If ψ′ ∈ L[d1, d2] and λ ∈ [0, 1], then
As a first application of Lemma 22, we prove the following result.
Theorem 23. Let M = [d1, d2] ⊂ ℝ\{0} be a p -harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If M′ ∈ L[d1, d2] and is strongly reciprocally (p,h)-convex function on M, q ≥ 1, and λ ∈ [0, 1], then
where
Proof. Using Lemma 22 and power mean inequality, we have
Since , so
This completes the proof.
Remark 24. Inserting μ = 0 and h(j) = j in Theorem 23, we obtained [23] Theorem 2.2.
For q = 1, Theorem 23 reduces to the following result.
Corollary 25. Let M = [d1, d2] ⊂ ℝ\{0} be a p -harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If ψ′ ∈ L[d1, d2] and is in SR(p, h) on M and λ ∈ [0, 1], then
where k15, k16, k17, k18, k7, and k8 are given by (43) to (48).
Remark 26. Inserting h(j) = j and μ = 0 in Corollary 25, we obtained [23] Corollary 2.3.
Using Lemma 22, we can prove the following result.
Theorem 27. Let M = [d1, d2] ⊂ ℝ\{0} be a p -harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If M′ ∈ L[d1, d2] and is in SR(p, h) on M, r, q > 1, (1/r) + (1/q) = 1 and λ ∈ [0, 1], then
where
Proof. Using Lemma 22, we have
Applying Holder’s integral inequality,
Since , so
Which is the required result.
Remark 28. Inserting h(j) = j and μ = 0 in Theorem 27, we obtained [23] Theorem 2.5.
For λ = 0, Theorem 27 reduces to the following result.
Corollary 29. Let M = [d1, d2] ⊂ ℝ\{0} be a p-harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If ψ′ ∈ L[d1, d2] and is in SR(p, h) on M, r, q > 1, (1/r) + (1/q) = 1 and λ ∈ [0, 1], then
where k19, k20, k21, k22, k13, and k14 are given by (53)-(58).
Remark 30. Inserting h(j) = j and μ = 0 in Corollary 29, we obtained [23] Corollary 3.5.
For λ = 1, Theorem 27 reduces to the following result.
Corollary 31. Let M = [d1, d2] ⊂ ℝ\{0} be a p -harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If M′ ∈ L[a1, b1] and is in SR(p, h) on M, r, q > 1, (1/r) + (1/q) = 1 and λ ∈ [0, 1] then,
where k19, k20, k21, k22, k13, and k14 are given by (53)-(58).
Remark 32. Inserting h(j) = j and μ = 0 in Corollary 31, we obtained [23] Corollary 3.6.
For λ = 1/3, Theorem 27 reduces to the following result.
Corollary 33. Let M = [d1, d2] ⊂ ℝ\{0} be a p-harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If ψ′ ∈ L[d1, d2] and is in SR(p, h) on M, r, q > 1, (1/r) + (1/q) = 1 and λ ∈ [0, 1] then,
where k19, k20, k21, k22, k13, and k14 are given by (53)-(58).
Remark 34. Inserting h(j) = j and μ = 0 in Corollary 33, we obtained [23] Corollary 3.7.
For λ = 1/2, Theorem 27) reduces to the following result.
Corollary 35. Let M = [d1, d2] ⊂ ℝ\{0} be a p-harmonic convex set, and let ψ : M = [d1, d2]⊆ℝ\{0}⟶ℝ be differentiable defined on the interior M of M. If ψ′ ∈ L[d1, d2] and is in SR(p, h) on M, r, q > 1, (1/r) + (1/q) = 1 and λ ∈ [0, 1] then,
where k19, k20, k21, k22, k13, and k14 are given by (53)–(58).
7. Conclusion
Convexity plays very important role in pure and applied mathematics. In many problems, the classical definition of convexity is not enough, so the definition of convex functions is generalized in various directions. In this paper, we developed a new generalization called strongly reciprocally (p,h)-convex function. We have also developed Hermite-Hadamard and Fejér type inequality for this generalization. Moreover, we conclude that the results proved in this article are the generalization of results in [14, 16, 17, 23].
Conflicts of Interest
The authors have no conflict of interests.
Authors’ Contributions
The authors contributed equally in this paper.
Acknowledgments
This research is supported by Department of Mathematics, University of Okara, Okara Pakistan.
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