Uniqueness Results for Higher Order Elliptic Equations in Weighted Sobolev Spaces
Abstract
We prove some uniqueness results for the solution of two kinds of Dirichlet boundary value problems for second- and fourth-order linear elliptic differential equations with discontinuous coefficients in polyhedral angles, in weighted Sobolev spaces.
1. Introduction
The Dirichlet problem for polyharmonic equations in bounded domains of has been studied, among the first, by Sobolev in [1].
The problem was developed in various directions. For instance, Vekua in [2, 3] considers different boundary value problems in not necessarily bounded domains for harmonic, biharmonic, and metaharmonic functions. Successively, analogous problems in more general cases, for what concerns domains and operators, have been studied with different methods by many authors (see, e.g., [4–7]).
In particular, in [7], the author obtains a uniqueness result for the Dirichlet problem for polyharmonic operators of order 2m in polyhedral angles of . This result has been later on generalized, in [5], to the case of operators in divergence form of order 2m with discontinuous bounded measurable elliptic coefficients.
In [6] the authors study a boundary value problem for biharmonic functions in presence of nonregular points on the boundary of the domain. It is well known that in the neighborhood of these singular points (corners or edges) the solution of the problem presents a singularity that can be characterized by the presence of a suitable weight.
Uniqueness results for different Dirichlet problems in weighted Sobolev spaces for different classes of weights can be found in [8–12]. Studies of Dirichlet problems in the framework of weighted Sobolev spaces and in the case of unbounded domains can be found in [13–22].
In this paper, we extend the results of [5, 7] to the case of weighted Sobolev spaces. More precisely, we prove some uniqueness results for the solution of two kinds of Dirichlet boundary value problems for second- and fourth-order linear elliptic differential equations with discontinuous coefficients in the polyhedral angle , 0 ≤ l ≤ n − 1, n ≥ 2, in weighted Sobolev spaces.
The main tool in our analysis is a generalization of the Hardy’s inequality proved by Kondrat’ev and Olènik in [23].
2. Preliminary Results
Proposition 1. If G is a bounded open subset in with 0 ∈ ∂G, then
- (i)
is a cone with vertex in the origin of coordinates;
- (ii)
BR, R > 0, is the open ball of center in the origin and radius R;
- (iii)
VR = V∩BR;
- (iv)
for every l ∈ {0, …, n − 1},
(6) -
is the “polyhedral angle” with vertex in the origin;
- (v)
is the half-space;
- (vi)
.
To prove our main results, consisting in two uniqueness theorems, we will use the following inequality. We observe that this is a slightly modified version of a generalized Hardy’s inequality that was proved by Kondrat’ev and Olènik in [23], adapted to our needs (see also [5]).
Lemma 2 (generalized Hardy’s inequality). Let p > 1 and be such that r + n − p ≠ 0. Assume that for a sufficiently smooth function g the following condition is fulfilled:
3. Dirichlet Problem for Second-Order Elliptic Equations
Definition 4. We say that a function u is a generalized solution of problem (11) if it satisfies the integral identity
Now we prove our first uniqueness result.
Theorem 5. Let be a generalized solution of problem (11), with f = 0. Then there exists ϵ0 > 0 such that if s ≤ ϵ0/2 and s ≠ (2 − n)/2 one has u ≡ 0 in .
Proof. Let Θ(t) be an auxiliary function in defined by
Let be a generalized solution of problem (11), with f = 0. We put
Thus, using vR as test function in (12), we get
By applying Young’s inequality one gets that for any ϵ > 0
Thus for any P > 0 and for any R > P we obtain
4. Dirichlet Problem for 4th-Order Elliptic Equations
Definition 6. We say that a function u is a generalized solution of problem (29) if it satisfies the integral identity
The result is the following.
Theorem 7. Let be a generalized solution of problem (29), with f = 0. Then there exists ϵ0 > 0 such that if s ≤ ϵ0/2 and s ≠ (2 − n)/2, (4 − n)/2 one has u ≡ 0 in .
Proof. We shall rely on the methods developed in [5, 7]. We consider the function ΘR(x) defined in (13) and satisfying (14). Furthermore, we assume that there exists a positive constant K1 such that
Note that the function ΘR is such that, for any i, j = 1, …, n, one has (16) and
Again we put
Observe that the definition of ΘR together with the boundary condition satisfied by u gives that . Hence, by the symmetry of aij, if we take vR as test function in (30) we get
Thus for any P > 0 and for any R > P we obtain
In view of Proposition 1 we obtain that if the solution with s ≤ 0, then u ∈ W2,2(QP), for any P > 0, while if s > 0 for any q ∈ [1,2[ there exists ϵ0 = ϵ0(q) > 0 such that if 0 < s ≤ ϵ0/2, then u ∈ W2,q(QP) for any P > 0. Thus, by (41) the function ux is constant a.e. in QP, and since one concludes that ux = 0 a.e. in QP, for any P > 0. The thesis follows then as the one of Theorem 5.
Conflicts of Interest
The authors declare that they have no conflicts of interest.