On a Singular Second-Order Multipoint Boundary Value Problem at Resonance
Abstract
The aim of this paper is to derive existence results for a second-order singular multipoint boundary value problem at resonance using coincidence degree arguments.
1. Introduction
In [1] Gupta et al. studied the above equation when f and g have no singularity and . They obtained existence of a C1[0,1] solution by utilising the Leray-Schauder continuation principle. In [2] Ma and O’Regan derived existence results for the same equation when f and g have a singularity at t = 1 and . They also utilised the Leray-Schauder continuation method. These results correspond to the nonresonance case. The purpose of this article is therefore to derive existence results for (1) when (the resonance case) and when f and g have a singularity at t = 1. We shall employ coincidence degree arguments in obtaining our results. In this case, the methods used in [1, 2] are not valid.
Research on singular differential equations is important because singular differential equations are useful in the modeling of many problems in the physical and engineering sciences; see [3].
In general singular boundary value problems can be difficult to solve because they may blow up near the singularity. The existence and multiplicity of solutions for second-order nonsingular boundary value problems have been extensively studied by many researchers. However to the best of our knowledge the corresponding problem for second-order differential equations at resonance and with a singularity had not received much attention in the literature. For recent results in these directions see [1, 2, 4–9] and references therein.
-
(A0) For ξi ∈ (0,1), i = 1,2, …, m − 2, 0 < ξ1 < ξ2 < ⋯<ξm−2 < 1 and .
-
(A1) There exist a(t), c(t) ∈ L1[0,1] with (1 − t)a(t), (1 − t)c(t), b(t) ∈ L1[0,1] and |f(t, x, y)| ≤ a(t)|x| + b(t)|y| + c(t), a.e., t ∈ [0,1], .
-
(A2) is such that .
2. Preliminaries
In this section we state some definitions, theorems, and lemmas that will be used in the subsequent section.
Definition 1. Let X and Z be real Banach spaces. One says that the linear operator L : dom L ⊂ X → Z is a Fredholm mapping of index zero if KerL and Z/ImL are of finite dimension, where ImL denotes the image of L.
As a result of Definition 1, we will require the continuous projections P : X → X, Q : Z → Z such that ImP = KerL, KerQ = ImL, X = KerL ⊕ KerP, Z = ImL ⊕ ImQ, and L|dom L∩KerP : dom L∩KerP → ImL is an isomorphism.
Definition 2. Let L be a Fredholm mapping of index zero and Ω a bounded open subset of X such that dom L∩Ω ≠ ϕ. The map N : X → Z is called L-compact on , if the map is bounded and Kp(I − Q) is compact, where one denotes by Kp : ImL → dom L∩KerP the generalised inverse of L. In addition N is L-completely continuous if it is L-compact on every bounded Ω ⊂ X.
Theorem 3 (see [10].)Let L be a Fredholm operator of index zero and let N be L-compact on . Assume that the following conditions are satisfied:
- (i)
Lx ≠ λNx for every (x, λ)∈[(dom L∖KerL)∩∂Ω]×(0,1).
- (ii)
Nx ∉ ImL, for every x ∈ KerL∩∂Ω.
- (iii)
deg(QN|KerL∩∂Ω, Ω∩KerL, 0) ≠ 0,
In what follows, we shall make use of the following classical spaces, C[0,1], C1[0,1], L1[0,1], and L∞[0,1]. Let AC[0,1] denote the space of all absolute continuous functions on [0,1], AC1[0,1] = {x ∈ C1[0,1] : x′(t) ∈ AC[0,1]}, = {x : x|[0,d] ∈ L1[0, d] for every compact interval [0, d]⊆[0,1)}.
ACloc[0,1) = {x : x|[0,d] ∈ AC[0, d]}.
Lemma 4 (see [2].)Let y ∈ Z. Then
- (i)
.
- (ii)
.
Lemma 5. If then
- (i)
;
- (ii)
;
- (iii)
L : dom L ⊂ X → Z is a Fredholm operator of index zero and the continuous operator Q : Z → Z can be defined by
(9)where . - (iv)
The linear operator Kp : ImL : →dom L∩KerP can be defined as
(10) - (v)
for all y ∈ Z.
Proof. (i) It is obvious that
(ii) We show that
(iii) For y ∈ Z, we define the projection Qy as
We show that Q : Z → Z is well defined and bounded.
(iv) We define P : X → X by
This shows that Kp = (L|dom L∩KerP) −1.
(v)
Lemma 6. The operator N : X → Z defined by
Proof. Suppose Ω is an open bounded subset of X. Let R1 = sup{‖x‖X : x ∈ Ω}. From condition (A1) and each xn ∈ Ω we have
By using (31) we derive
Next we show that the sequence {KP,QNxn(t)} is equicontinuous. Let t1, t2 ∈ [0,1], t1 < t2; then
We then conclude that KP,Q is relatively compact and since is bounded we conclude from Definition 2 that N is L-compact on every bounded subset Ω of X and hence N is L-completely continuous.
3. Main Result
In this section we will state and prove the main existence results for problem (1).
Theorem 7. Assume that the following conditions are satisfied:
-
(H1) There exists a positive constant B1 such that, for each x ∈ dom L, if |x(t)| > B1 for all t ∈ [0,1] then
(38) -
(H2) There exists a positive constant B2 such that for and |c| > B2 either (i) QN(c) ≥ 0 or (ii) QN(c) ≤ 0.
To prove Theorem 7, we first establish some lemmas.
Lemma 8. Let Ω1 = {x ∈ dom L∖KerL : Lx = λNx, λ ∈ (0,1)} then Ω1 is bounded in X.
Proof. Let x ∈ Ω1. We let Lx = λNx, 0 < λ < 1. Since λ ≠ 0 it is clear that Nx ∈ ImL = KerQ; hence QNx = 0 for all t ∈ [0,1]. Therefore by assumption (H1) there exist t0 ∈ [0,1] such that |x(t0)| < B1. Now
Lemma 9. The set Ω2 = {x ∈ KerL : Nx ∈ ImL} is a bounded subset of X.
Proof. Let x ∈ Ω2 with x(t) = c, . Then QN(c) = 0 implies N(c) ∈ ImL = KerQ. We therefore derive from (H2) that
Lemma 10. The sets and are bounded in X provided (H2)(i) and (H2)(ii) are satisfied simultaneously.
Proof. If QN(c) ≥ 0 then, for with x(t) = c, , we have
Proof of Theorem 7. We show that the conditions of Theorem 3 are satisfied where Ω is an open and bounded set such that . It is easily seen that conditions (i) and (ii) of Theorem 3 are satisfied by using Lemmas 8 and 9. To verify the third condition we set H(x, λ) = ±λx + (1 − λ)QNx. We choose the isomorphism J : ImQ → KerL defined by J(c) = c, . By Lemma 10, we derive that H(x, λ) ≠ 0 for all (x, λ)∈(KerL∩∂Ω)×[0,1]. Hence
Conflicts of Interest
The authors declare that there are no conflicts of interest regarding the publication of this paper.
Acknowledgments
This work is supported by the Covenant University Centre for Research, Innovation and Discovery (CUCRID).