Numerical Solvability and Solution of an Inverse Problem Related to the Gibbs Phenomenon
Abstract
We report on the inverse problem for the truncated Fourier series representation of f(x) ∈ BV(−L, L) in a form with a quadratic degeneracy, revealing the existence of the Gibbs-Wilbraham phenomenon. A new distribution-theoretic proof is proposed for this phenomenon. The paper studies moreover the iterative numerical solvability and solution of this inverse problem near discontinuities of f(x).
1. Introduction
The Gibbs phenomenon (see, e.g., [3]) is a statement of the fact that the infinite series g(x) tends to overshoot the positive corner of a discontinuity of f(x) by ~9% of the jump size and to undershoot the negative corner by the same amount. An overshoot/undershoot effect that is accompanied with spurious oscillations “ringing” near the discontinuity (as described in the appendix) when the series in (1) is truncated at m = N. However, according to a theorem by Fejer [1], the infinite series g(x) of a BV(−L, L) function converges to f(x) at each point x of continuity of f(x).
This shortcoming in the infinite Fourier series representation of piecewise continuous f(x) was first observed by H. Wilbraham in 1848 and then analyzed in detail [4] by J. W. Gibbs in 1898. The main reasons of the Gibbs-Wilbraham effect are that (i) not all frequencies (only integer ones) are employed in (1), (ii) am and bm happen to decay slowly with increasing m, and (iii) the global nature of the approximation of f(x): the expansion coefficients are obtained, via (2), by integration over the entire period, including the points of discontinuity.
What is unpleasant though, with all of this, is that the Gibbs-Wilbraham effect is generic and is present for any periodic signal f(x) ∈ BV(−L, L) with isolated discontinuities. The presence of this effect can in fact lead to quite negative consequences when single infinite Fourier series, multiple infinite Fourier series, or even infinite wavelet series are employed to approximate signals of various dimensions, in many fields such as radio engineering and signal transmission.
The Gibbs-Wilbraham effect can nevertheless have both positive and negative consequences in different applications. The negative consequences call for Gibbs effect reduction, and this can in principle be achieved with the use [4] of a variety of filters. This effect can also be reduced theoretically and for all purposes. In addition to classical mathematical filters, recently (in 2011) Rim and Yun [5] defined a kind of spectral series to filter off completely the Gibbs effect near a discontinuity. The construction of this series is based on the method of adding the Fourier coefficients of a Heaviside function to the given Fourier partial sums.
This paper is organized as follows. After this introduction, we propose in Section 2 a new distribution-theoretic proof for the Gibbs-Wilbraham effect. In Section 3, we advance the inverse problem of the truncated Fourier series and the new stereographic truncated Fourier series and its relation to resolution of the undershoot/overshoot pair associated to the Gibbs-Wilbraham effect. Here we illustrate how solving the inverse problem for the truncated representation (1) contains a quadratic degeneracy that indicates the existence of the Gibbs phenomenon. Section 4 deals with the numerical iterative solution of the previous inverse problem and its convergence, with a proof and demonstration that stereographic projection does not affect such a numerical solution and its posedness.
2. Distribution-Theoretic Proof for the Gibbs-Wilbraham Effect
Theorem 1. Let a 2L –periodic f(x) ∈ BV(−L, L) be discontinuous at xs. The Fourier series representation g(x) of f(x) converges over (−L, L), as N → ∞ so as,
Proof. According to distribution theory [6] when g(x) coincides a.e. with f(x) over (−L, L), it may always be differentiated; namely,
By a theorem of Fejer [1], g(x) should converge to fc(x) when N → ∞, ∀x ≠ xs on (−L, L). Hence the term Δsu(x − xs) in (8) can have a compact support only on an infinitesimal interval σ = limN→∞σN = 0 to the right of xs, that is, ending at . Hence
Next complete the sweeping by integrating (6) from x to L; namely,
Repeated application of the same arguments employed in the derivation of (9)-(10) to (13) allows for writing it as
It should be pointed out that in the previous proof relations (10) and (15) say nothing specifically about the behavior of g(x) at and , respectively, while asserting the existence of a spiky behavior of g(x) individually at then at . Moreover, the uncertainty ρ had been resolved in the past (by Wilbraham; see also the Appendix) computationally to satisfy ρ = 0.09 and long before the advance of the theory of distributions (generalized functions) by S. L. Sobolev in 1936. The number 0.09 for ρ remains until now, however, a mysterious theoretical puzzle that calls for a rigorous distribution-theoretic justification.
3. The Inverse Problem for Truncated Fourier Series
Definition 2 (the inverse problem for the truncated Fourier series representation). Given a number c = g(x) satisfying (18), what is the corresponding x?
Moreover, the inverse problem of the previous definition has a unique solution that satisfies (19) and is expected to accept a double root when the horizontal line h(x) = c > f(x) intersects with a sharp peak (overshoot) of a truncated g(x). We shall call this feature a duplicated (quadratic) degeneracy of the solution for this inverse problem.
The existence of the Fourier series truncation peak (and the corresponding two roots for x) is not directly evident from the structure of G(γ, x, m), and despite its linearity in the data .
3.1. The Tangent Half-Angle Stereographic Projection
The tangent half-angle substitution (the Euler-Weirstrass substitution [9]) tan(θ/2) is widely used in integral calculus for finding antiderivatives of rational expressions of circular function pairs (cosθ, sinθ). Geometrically the construction goes like this: draw the unit circle, and let P be the point (−1,0). A line through P (except the vertical line) passes through a point (cosθ, sinθ) on the circle and crosses the y-axis at some point y = t. Obviously t determines the slope of this line. Furthermore, each of the lines (except the vertical line) intersects the unit circle in exactly two points, one of which is P. This determines a function from points on the unit circle to points on a straight line. The circular functions determine therefore a map from points (cosθ, sinθ) on the unit circle to slopes t. In fact this is a stereographic projection [9] that expresses these pairs in terms of one variable: tan(θ/2) = t.
Numerical algorithms employing these trigonometric pairs like Fourier series (1) could in principle be influenced by such a projection. In this context, the tangent half-range transformation relates the angle θm = m(π/L)x to the slope tm = tan(θm/2) of a line intersecting the unit circle centered around (0,0).
The rest of this section illustrates how stereographic projection of Fourier series reveals a quadratic degeneracy that indicates the existence of the Gibbs-Wilbraham effect. It also addresses the question of solving the inverse problem for the truncated Fourier series representations. The impact of stereographic projection on the ill-posedness of the numerical solution of this inverse problem is moreover a main question that has been addressed in this paper.
Our analysis starts however by illustrating how the tangent half-angle stereographic projection can provide a new insight into the behavior of truncated Fourier series near a discontinuity of f(x).
Lemma 3. The solution x of the inverse problem for the truncated Fourier series representation satisfies
Proof. By studying solvability for x of (18) Let tm = tanm(π/2L)x, and then , and . Further consideration of these facts in (18) leads to the tangent half-angle stereographically transformed, , form
The harmonic trinomial in the left-hand side of (23) has two harmonic zeros, , for each x; namely,
The quadratic degeneracy of the harmonic zeros of tm can disappear only when σm = 0, for all m. And this happens to be equivalent with
It is interesting to remark that condition (27) is entirely different from
Equation (32) is easily transformable to the required result (23); here the proof completes.
3.2. The Stereographic Fourier Series
Proposition 4. The following:
Proof. Since N is finite, then the proof of implies the correctness of this proposition. So let us differentiate G(x) = G[θm(x)] with respect to x by applying the chain rule; namely,
In addition to the fact that the convergence of g∗(x) can sometimes become worse than convergence of g(x) (see, e.g., [10]) the presence of the m(π/L) factor in (d/dx)g(x) can aggravate the convergence problem of (45) when the coefficients am and bm do not decay fast enough.
Remark 5. Away from points of discontinuity of f(x), the stereographically transformed differentiated Fourier series , which defines , is the same as the derivative , which defines H∗(γ, x, m), of the stereographic Fourier series . Moreover, even at points of discontinuity of .
Theorem 6 (see [1].)Let f(x) be (i) continuous on [−L, L] such that (ii) f(−L) = f(L), and let (iii) f′(x) be piecewise continuous over [−L, L]; then the corresponding Fourier series g(x) of (1) or (47) is differentiable at each point where (iv) f′′(x) exists.
The previous remark can incidentally have useful applications when differentiating certain slowly converging Fourier series, as illustrated by the following example.
Example 7. Consider the 2π-periodic odd signal f(x), defined over one period, by f(x) = x. Its Fourier series is known to be
Differentiating term-by-term, we obtain
Alternatively, by means of (47)
Both G(γ, x, m), of (2), and H(γ, x, m), of (22), equivalent forms are nonlinear trigonometric functions of the x solution. However, while G(γ, x, m) is linear in , thestereographic H(γ, x, m) is nonlinear in this γ. This can raise a question on a possibility for at singular points of f(x). A question that will be answered negatively in the next section. Furthermore, since the data is discrete, then the operators and do not depend continuously on γ, and this is the main reason for ill-posedness of the present inverse problem.
In conclusion, the quadratic degeneracy of the solution of the present inverse problem, explicit when using H(γ, x, m), is a nonlinear indicator of the existence of the peak pertaining to the Gibbs phenomenon. However, the numerical ill-posedness, associated with the relative values of a trial iterative variable in the γ set, happens to remarkably remain invariant under the tangent half-angle stereographic projection.
4. Numerics of Solving the Inverse Problem
The solution of the present inverse problem is in fact a problem of finding the roots of (44) when g(x) is truncated at m = N. For that reason, we shall focus on such roots in the neighborhood of a step-like discontinuity of f(x) at x = xo, say, where f(xo − ε) < f(xo + ε), 0 < ε ≪ 1. The associated with the Gibbs phenomenon overshoot of or over f(xo + ε) and undershoot of this g(x) below f(xo − ε). The intersection of a horizontal line h(x) = c ≥ f(xo + ε), corresponding to φ(x) = 0, can be at two points α1 and α2 on both sides of the peak location α0, representing two distinct roots of φ(x) = 0. It can also be at one point α0, corresponding to the maximum of the truncated g(x); that is, a double root of φ(x) = 0.
4.1. Computation of the Peak Location α0
Proposition 8. The ill-posedness of the inverse problem of the truncated Fourier series is invariant under stereographic projection.
Proof. The tangent half-angle stereographic projection, though not isometric (distance preserving), is nevertheless variability preserving. Indeed, the main ingredients of this inverse problem are, namely, , c, and x0, with . Under this projection θm(x0) transforms to tm(x0) = tan[θm(x0)/2], and G[θm(x0)] transforms to H[tm(x0)]. But according to Proposition 4, . Hence the variation of G(γ, x0, m) with x0 in the Fourier series inverse problem and the variation of H(γ, x0, m) with x0 in the stereographic form are identical.
Equivalently, this makes the ill-posedness of this inverse problem invariant under stereographic projection.
Expected manifestations of the correctness of this proposition are as follows: (i) the results of computations by the (71) and (73) algorithms for α0 with the same x0 must be identical and (ii) the results of computations by the (65) and (67) algorithms for α1 (or α2) with the same x0 and c must also be identical.
4.2. Convergence Analysis
Let us focus first on the convergence of the iterative process (65) or (67). In many situations where term-by-term differentiability does not hold, the Newton-Raphson method can always be replaced by some quasi-Newton method [12, 13], where φ′(xn) or ψ′(xn) in (65) or (67) is replaced by a suitable approximation. For example, in the chord method φ′(xn) is replaced by φ′(x0) for all iterations.
- (i)
φ′(x) ≠ 0, ∀x ∈ I, where I = [α − η, α + η] for some η ≥ |(α − x0)|.
- (ii)
φ′′(x) is finite ∀x ∈ I.
- (iii)
x0 is sufficiently close to α.
- (a)
Taylor approximation is accurate enough such that we can ignore higher order terms.
- (b)
(1/2)|φ′′(xn)/φ′(xn)| < K|φ′′(α)/φ′(α)| for some K < ∞.
- (c)
K|φ′′(α)/φ′(α)|ϵn < 1 for .
- (i)
If a point like α0 is included in I, the method will terminate due to division by zero.
- (ii)
When the initial estimate x0 is poor, the pertaining wrong I can contribute to nonconvergence of the algorithm.
- (i)
φ′′(x) ≠ 0, ∀x ∈ I, where I = [α0 − η, α0 + η] for some η ≥ |(α0 − x0)|.
- (ii)
φ′′′(x) is finite ∀x ∈ I.
- (iii)
x0 is sufficiently close to α0.
- (a)
Taylor approximation is accurate enough such that we can ignore higher order terms;
- (b)
(1/2)|φ′′′(xn)/φ′′(xn)| < K|φ′′′(α0)/φ′′(α0)| for some K < ∞;
- (c)
K|φ′′′(α0)/φ′′(α0)|εn < 1 for .
4.3. Applications
The standard iterative algorithms, (71) or (73), for finding the location of overshoots in of the Gibbs effect employ the fact that the first derivative of a peak, in g(x) or , respectively, has a downward-going-zero-crossing at the peak maximum. But the presence of many neighboring smaller peaks in the ringing close to the overshoot will cause many undesirable zero-crossings to be invoked if the initial trial root x0 is not correctly chosen. This fact makes the numerical problem of peak finding in the Gibbs effect of pathological difficulty. A difficulty that aggravates with the increase in the number N of truncated terms in the employed Fourier series. Indeed, with the increase of N the number of undesirable zero-crossings increases in the neighborhood of α0, as illustrated in Section 1. This can increasingly lead to oscillatory and even unstable values in sequence {xn}, the more the distance |x0 − α0| contains unwanted zero-crossings.
These problems have been resolved in the two examples that follow, which simultaneously illustrate the applicability of Proposition 8.
Example 9. Consider the 2π-periodic odd signal f(x), of Example A.1, defined over one period, by
This signal has a jump discontinuity at x = 0 of magnitude 2. We shall focus our computations on the Gibbs phenomenon overshoot near this discontinuity.
Here is a printout list of results for the parameters of the posing inverse problem, via computations by both the direct and stereographic algorithms.
It is remarkable how results by both algorithms are practically identical and share the same following features that are observed by results of the direct algorithm, discussed below.
Case I (N = 40). The computations of α0 for the previous example, using (71), with x0 = 0.02 lead to x1 = 0.039 109; this varies quickly with n (only beyond the 4th decimal) to stabilize towards x3 = x4 = x5 = ⋯ = 0.039 299 = α0. Here using (1) gives g(α0) = g(0.039 299) = 1.179 030, which is quite close to the theoretically expected value, by (A.7), of ~1.18.
Then using (65) for c = 1.09 and x0 = 0.000381 leads to x1 = 0.021 697; this varies quickly with n (only beyond the 3-d decimal) to stabilize quickly towards x5 = x6 = x7 = ⋯ = 0.028 368 = α1. Also using (65) for c = 1.09 and x0 = 0.04 leads to x1 = 0.067 699; this varies quickly with n (beyond the 2nd decimal) to stabilize quickly towards x5 = x6 = x7 = ⋯ = 0.052 873 = α2.
For both α1 and α2, using (1) yields g(α1) = g(0.028368) = g(α2) = g(0.052873) = 1.09 = c, as expected.
Case II (N = 100). Computations of α0, using (71), with x0 = 0.02 lead to x1 = 0.014 221; this varies quickly with n (only beyond the 4th decimal) to stabilize towards x3 = x4 = x5 = ⋯ = 0.015 708 = α0. Here using (1) gives g(α0) = g(0.015708) = 1.178 990. This result appears to be slightly excessive, perhaps due to increased rounding off errors with increasing N to 100.
Then using (65) for c = 1.09 and x0 = 0.015 237 leads after a negative value to x2 = 0.014 462; this varies with n (beyond the 2nd decimal) to stabilize quickly towards x7 = x8 = x9 = ⋯ = 0.011 3348 = α1. The used value of x0 is apparently not appropriate, and this illustrates the generic ill-posedness of this inverse problem.
The pertaining computations of α2, with x0 = 0.017000, lead to x1 = 0.020 434; this varies with n (beyond the 3-d decimal) to stabilize quickly towards x4 = x5 = x6 = ⋯ = 0.021 149 = α2.
For both α1 and α2, using (1), yields g(α1) = g(0.0113348) = g(α2) = g(0.021149) = 1.09 = c, as expected.
Case III (N = 150). The computations of α0, using (71), with x0 = 0.005 lead to x1 = 0.010 595; this varies insignificantly with n (only beyond the 4th decimal) to stabilize towards x3 = x4 = x5 = ⋯ = 0.010 472 = α0. Here using (1) gives g(α0) = g(0.010472) = 1.178 980, which does not significantly differ from g(α0) when N = 100.
Then using (65) for c = 1.09 and x0 = 0.010 158 leads after a negative value to x2 = 0.009 643; and this varies (beyond the 3-d decimal) to stabilize quickly towards x7 = x8 = x9 = ⋯ = 0.007 565 = α1.
The pertaining computations of α2, with x0 = 0.010 800, lead to x1 = 0.025 998; this varies (beyond the 2nd decimal) to stabilize towards x14 = x15 = x16 = x17 = x18 = ⋯ = 0.014 099 = α2.
For both α1 and α2, using (1) yields g(α1) = g(007 565) = g(α2) = g(0.014 099) = 1.09 = c.
During the previous computations, summarized in Table 1, it has been observed that varying x0 in the present Newton-Raphson process, for all N, can lead to strong oscillations and even completely unstable values for α0, α1, and α2 of the Fourier series inverse problem, which though ill-posed is practically regularizible. Apart from this drawback, the (71) with (65) iterative algorithms (i) converge quickly to the theoretically expected values and are (ii) of demonstrated stability of the iterations, for properly chosen x0 (which act as effective regularizing parameters). Moreover, computations by the stereographic algorithm, invoking (73) and (67), share the same magnitude and convergence rates with results by the direct algorithm. Finally, it is demonstrated that the present signal exhibits an overshoot, when N = 150, of ~9% of a jump discontinuity, of magnitude 2, that is, located at a distance of ~0.0105.
To illustrate robustness of both numerical algorithms and their possible effective regularizibility we shall study also the numerical inverse problem for the Fourier series representation of an arbitrary (nonsymmetric) periodic signal.
N | α1 | α0 | α2 |
---|---|---|---|
40 | 0.028 368 | 0.039 299 | 0.052 873 |
100 | 0.011 335 | 0.015 705 | 0.021 149 |
150 | 0.007 565 | 0.010 472 | 0.014 099 |
Example 10. Consider the 2π-periodic signal f(x), defined over one period, by
This signal has, like the signal of Example 9, a jump discontinuity at x = 0 of magnitude 2. For the sake of comparison, we shall also focus our computations on the Gibbs phenomenon overshoot part of near this discontinuity.
It should be noted here that the results by both algorithms, summarized in Table 2, are also identical, a feature indicating that the degree of ill-posedness of the posing inverse problem is not affected, as predicted by Proposition 8, by the tangent half-angle stereographic projection.
N | α1 | α0 | α2 |
---|---|---|---|
40 | 0.0564765 | 0.0781391 | 0.105155 |
100 | 0.0226546 | 0.0313516 | 0.0422024 |
150 | 0.0151124 | 0.0209153 | 0.028156 |
Case I (N = 40). The computations of α0 for this example, using (71) and (73), with x0 = 0.03 lead to an identical sequence {xn} that converges by both algorithms after the x4 iteration to 0.078 139 with .
Case II (N = 100). The computations of α0, with x0 = 0.01, lead to an identical sequence {xn} that converges by both algorithms after the x5 iteration to 0.031 351 with .
Case III (N = 150). The computations of α0, with x0 = 0.007, lead also to an identical sequence {xn} that converges by both algorithms after the x5 iteration to 0.020 915 with .
Therefore the present signal exhibits an overshoot when N = 150, of ~9% of a jump discontinuity of magnitude 2, that is, located at a distance of ~0.020 9.
Comparison of the computed Gibbs overshoot parameters of the two considered signals with jump discontinuities at the same x = 0 of the same magnitude illustrates that the relative size of the overshoot depends essentially exclusively on the magnitude of the stimulating jump discontinuity. For instance, based on the present numerical results, one can suggest here that nonsymmetric signals have equal overshoots with symmetric signals. Their respective α0’s are however different. Indeed the nonsymmetric signal has a significantly larger α0 (0.020 9) than the α0 (0.0105) of the symmetric signal.
A further analysis has also been performed of Example 10 with N = 100,200,300, to compute the corresponding α0 with α1, α2 that correspond simultaneously to c = 1.08,1.10,1.12 as illustrated in Figure 1. Results of these computations are summarized in Table 3 and then used for the partial plots, of Figure 2, that interpolate α1, α2 (for c = 1.08,1.10,1.12) with α0, for each N = 100,200,300. In this table x∗ stands for the first convergence step of the {xn} sequence of Newton Raphson iterations.
α0 results | ||||
---|---|---|---|---|
N | x0 | x∗ | α0 | g(α0) |
100 | 0.030 | x3 | 0.031 3516 | 1.178 87 |
200 | 0.015 | x3 | 0.015 6919 | 1.178 92 |
300 | 0.008 | x3 | 0.010 4648 | 1.178 94 |
α1 results | ||||
N | x0 | x∗ | α1 | c |
0.025 | x4 | 0.022 2027 | 1.08 | |
100 | 0.025 | x3 | 0.023 1344 | 1.10 |
0.025 | x3 | 0.024 2027 | 1.12 | |
0.010 | x3 | 0.011 1117 | 1.08 | |
200 | 0.010 | x3 | 0.011 5779 | 1.10 |
0.010 | x4 | 0.012 1123 | 1.12 | |
0.008 | x3 | 0.007 410 08 | 1.08 | |
300 | 0.008 | x3 | 0.007 720 95 | 1.10 |
0.008 | x2 | 0.008 077 32 | 1.12 | |
α2 results | ||||
N | x0 | x∗ | α2 | c |
100 | 0.35 | x4 | 0.042 9439 | 1.08 |
0.35 | x4 | 0.041 4445 | 1.10 | |
0.35 | x4 | 0.039 8513 | 1.12 | |
200 | 0.018 | x3 | 0.021 4960 | 1.08 |
0.018 | x3 | 0.020 7456 | 1.10 | |
0.018 | x3 | 0.019 9483 | 1.12 | |
300 | 0.012 | x3 | 0.014 3360 | 1.08 |
0.012 | x3 | 0.013 8356 | 1.10 | |
0.012 | x4 | 0.013 3039 | 1.12 |


These results turn out to be extremely stable against variations of the trial initial root x0. Indeed, in the computationally most difficult situation, namely, when N = 300, a change of x0 from 0.008 to 0.020 leads to a variation of x∗ from x2 to just x6 with the same asymptotic α0 = 0.0104648 and α1 = 0.00807732 (for c = 1.12).
5. Conclusions
- (i)
When converge continuously in x and are nonzero at α1 (or α2), there exists a neighborhood (defined by I) of α such that, for all starting values x0 in the neighborhood, {xn} will converge to α1 (or α2).
- (ii)
When converge continuously in x and are nonzero at α1 and α2 (but not at α0) and if φ(x) has a second derivative, which might be zero, at α1 and α2 (and at α0) then the convergence of {xn} is quadratic or faster. If φ′′(x) ≠ 0 at α1 and α2, then the convergence of {xn} is merely quadratic.
- (iii)
The convergence of the Newton-Raphson iterative process to α0 can also be quadratic, but restrictions on the derivatives of φ(x) have to be observed up to the third order. Otherwise, the convergence of {xn} to α0 can slow down to become only linear [12] with a rate .
- (iv)
The reported computations clearly illustrate that α0 → 0 and |α1 − α2| → 0 when N → ∞; that is, the infinite Fourier series will sum to f(x) in the neighborhood of a discontinuity, except at the discontinuity itself.
Conflict of Interests
The author declares that there is no conflict of interests regarding the publication of this paper.
Acknowledgment
The numerical computations of Examples 9 and 10 have been performed, using Mathematica 8, by Mounir Abou Yassine, of the Department of CCE of AUL.
Appendix
To illustrate the Gibbs-Wilbraham effect we shall use here the same arguments employed by Wilbraham in 1848 in analyzing a similar square wave.
Example A.1. Let f(x) be a square wave periodic signal, which is defined over one period by
Since
It is possible to cancel the previous artificially induced differentiation by integrating the last result as
The form (A.7), distinctively from (A.3), reveals that SN(x) has turning points at the zeros of sin2Nξ. These occur when 2Nξ = rπ; r = 1,2, 3,4, 5, …, that is, at ξ = r(π/2N). Clearly then xr ~ ξr = r(π/2N) are turning points for SN(x). In particular x1 ~ ξ1 = π/2N defines the overshoot peak location α0 and is its magnitude. To evaluate SN(x1) = SN(α0) numerically, let us change the variable of integration; namely, 2Nξ = w, or ξ = w/2N, to rewrite the previous integral as . Clearly when N → ∞, sinw/2N = w/2N, and
As for x2, x3, x4, …, xr, …, limN→∞[SN(xr) − f(x)] decreases as we move away from the discontinuity, but it should be remarked however that the location of the overshoot α0 = x1 = π/2N moves towards the discontinuity according to