Volume 2014, Issue 1 640931
Research Article
Open Access

Existence of the Mild Solution for Impulsive Semilinear Differential Equation

Alka Chadha

Corresponding Author

Alka Chadha

Department of Mathematics, Indian Institute of Technology Roorkee, Roorkee, Uttarakhand 247667, India iitr.ac.in

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Dwijendra N. Pandey

Dwijendra N. Pandey

Department of Mathematics, Indian Institute of Technology Roorkee, Roorkee, Uttarakhand 247667, India iitr.ac.in

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First published: 18 May 2014
Citations: 3
Academic Editor: Yuri N. Skiba

Abstract

We study the existence of solutions of impulsive semilinear differential equation in a Banach space X in which impulsive condition is not instantaneous. We establish the existence of a mild solution by using the Hausdorff measure of noncompactness and a fixed point theorem for the convex power condensing operator.

1. Introduction

In a few decades, impulsive differential equations have received much attention of researchers mainly due to its demonstrated applications in widespread fields of science and engineering such as biology, physics, control theory, population dynamics, medicine and so on. The real world processes and phenomena which are subjected during their development to short-term external inuences can be modeled as impulsive differential equation. Their duration is negligible compared to the total duration of the entire process or phenomena. Impulsive differential equations are an appropriate model to hereditary phenomena for which a delay argument arises in the modelling equations. To further study on impulsive differential equations, we refer to books [1, 2] and papers [311].

In this paper, our purpose is to establish the existence of a solution to the following differential equations with non instantaneous impulses
()
()
()
where −A : D(A) ⊂ XX is a closed and bounded linear operator with dense domain D(A) ⊂ X. We assume that −A is the infinitesimal generator of a strongly continuous semigroup in a Banach space (X, ∥·∥). Here, x0X, 0 = t0 = s0 < t1s1t2 < ⋯<tδsδ < tδ+1 = T0 and F : [0, T0] × XX, Gi : (ti, si] × XX for all i = 1, …, δ are suitable functions to be specified later.

In [4], authors have introduced a new class of abstract impulsive differential equations in which impulses are not instantaneous and established the existence of solutions to the problem (1)–(3) with the assumption that operator A generates a C0-semigroup of bounded linear operators. In this system of (1)–(3), the impulses begin all of a sudden at the points ti and their proceeding continues on a finite time interval [ti, si] [5]. To concern the hemodynamical harmony of an individual we think about the following simplified situation. One can recommend a few intravenous sedates (insulin) on account of a decompensation (e.g., high or low level of glucose). Since the presentation of the medications in the bloodstream and the ensuing retention for the form are progressive and continuous processes, we can depict this circumstance as an impulsive activity which begins abruptly and stays animated on a finite time interval.

In [12], the generalization of the condensing operator as convex-power condensing operator has been introduced by Sun and Zhang and a new fixed point theorem for convex-power condensing operator has been established. The new fixed point theorem for convex-power condensing operator, defined by Sun and Zhang, is the generalization of the famous Schauder’s fixed point theorem and Sadovskii’s fixed point theorem. Sun and Zhang [12] have considered the following problem:
()
in a Banach space and established existence theorems for positive mild solutions and global mild solutions to the problem (4) with noncompact semigroup. The nonlinear function f fulfills the suitable conditions on the measure of noncompactness as for any bounded set BX, where α is the Kuratowski measure of noncompactness and is a positive constant. For more details about measure of noncompactness, we refer to [1220].

In the present work, our aim is to obtain results concerning the existence of mild solutions to problem (1)–(3) by using convex-power condensing operator and fixed point theorem for convex-power condensing operator Sun and Zhang [12].

The organization of the paper is as follows. We provide some basic definitions, Lemmas and theorems in Section 2 as “preliminaries.” We prove the existence of a mild solution for system (1) in Section 3 as “existence of mild solution.” In the last section, we present an example to illustrate the application of the abstract results.

2. Preliminaries

In this section, we give some definitions, notations, theorems, and lemmas which will be used in later sections.

Let (X, ∥·∥) be a real Banach space. The symbol C([0, T0]; X) stands for the Banach space of all the continuous functions from [0, T0] into X equipped with the norm ∥z∥ = sup⁡{∥z(s)∥, s ∈ [0, T0]} and L1([0, T0], X) stands for the space of X-valued Bochner integrable functions on [0, T0] endowed with the norm , fL1([0, T0], X).

The operator −A : D(A) ⊂ XX is the infinitesimal generator of a uniformly continuous semigroup and D(A) denotes the domain of A, which is densely defined, endowed with the graph norm. A semigroup is said to be equicontinuous if is equicontinuous at arbitrary t, 0 < t < , for any bounded subset KX. Throughout the paper we assume that
  • (H1)

    the operator −A generates the equicontinuous semigroup and there exists a positive number M such that .

For the study of impulsive differential equation, we define the space which contains all the functions y : [0, T0] → X such that y(·) is continuous at ttj, and exists for all j = 1,2, …, δ. Clearly, is a Banach space endowed with norm . For a function and i ∈ {0,1, …, δ}, we define the function such that
()
For , we have and we have following Accoli-Arzelà type criteria.

Lemma 1 (see [4].)A set is relatively compact in if and only if each set   (j = 0,1, …, δ) is relatively compact in C([tj, tj+1], X)  (j = 0,1, …, δ).

Now we present the following definition of mild solution.

Definition 2. A piecewise continuous function is said to be a mild solution of the (1)–(3) if u(0) = x0, u(t) = Gi(t, u(t)), for all t ∈ (ti, si], i = 1, …, δ, and

()
for all t ∈ [0, t1], and
()
for all t ∈ [si, ti+1] and every i = 1, …, δ.

Next, we give the definition of the Hausdorff measure of noncompactness (MNC).

Definition 3 (see [14].)The Hausdorff measure of noncompactness β of the set E in Banach space X is the greatest lower bound of those ε > 0 for which the set E has in the space X a finite ε-net; that is,

()
for every bounded subset E in a Banach space X.

Definition 4 (see [14].)The Kuratowski measure of noncompactness α defined on each bounded subset E of X as

()

The relation between Kuratowski measure of noncompactness α and the Hausdorff measure of noncompactness β is given by
()
To set the structure for our primary existence results, we review some essential properties about the Kuratowski and Hausdorff measure of noncompactness.

Lemma 5. For any bounded set U, VY, where Y is a Banach space. Then, we have following results:

  • (i)

    β(U) = 0 if and only if  U is precompact;

  • (ii)

    , where conv U and denote the convex hull and closure of  U, respectively;

  • (iii)

    β(U) ⊂ β(V), when UV;

  • (iv)

    β(U + V) ≤ β(U) + β(V), where U + V = {u + v : uU, vV};

  • (v)

    β(UV) ≤ max⁡{β(U), β(V)};

  • (vi)

    β(λU) = λ · β(U), for any ;

  • (vii)

    If the map is continuous and satisfies the Lipschitsz condition with constant κ, then, we have that for any bounded subset , where Y and are Banach space.

Definition 6. A continuous and bounded map is called β-condensing if, for any noncompact bounded subset ED,

()
where X is a Banach space.

To avoid confusion, we denote by β(·) the Hausdorff measure of noncompactness on set X, C([0, T0]; X) and .

Lemma 7 (see [14], Darbo-Sadovskii.)Let DX be bounded, closed, and convex. If the continuous map is a β-contraction, then the map has a fixed point in D.

In [12], authors have presented the generalization of the condensing operator and suggested a new fixed point theorem for such operators. Firstly, we present some recognition. Let DX be a bounded, closed, and convex set and let be a continuous map from D into itself with u0D. For every ED, we set
()

Definition 8 (see [12].)Let DX be bounded, closed, and convex. A bounded and continuous operator is called a convex-power condensing operator if for any bounded nonprecompact subset ED, there exist x0D and an integer n0 > 0 such that

()

A β-convex-power condensing operator is β-condensing for n0 = 1. Therefore, it is clear that convex-power condensing operator is a generalization of the condensing operator.

Lemma 9 (see [12].)Let DX be bounded, closed, and convex set. If the continuous map is β-convex-power condensing, then there exists a fixed point of map in D.

Lemma 10 (see [11], [14].)If EC([0, T0]; X) is bounded, then β(E(t)) ≤ β(E), ∀t ∈ [0, T0], where E(t) = {u(t); uE}⊆X. In addition, if E is equicontinuous on [0, T0], then β(E(t)) is continuous on [0, T0] and

()

Lemma 11 (see [11].)If is bounded, then β(E(t)) ≤ β(E), ∀t ∈ [0, T0]. Besides, suppose the following conditions are satisfied:

  • (1)

    E is equicontinuous on [0, t1] and each (ti, si], [si, ti+1], i = 1, …, δ,

  • (2)

    E is equicontinuous at , i = 1, …, δ.

Then, we have .

Lemma 12 (see [14].)If EC([0, T0]; X) is bounded and equicontinuous, then β(E(t)) is continuous and

()
where .

Lemma 13. Let be a sequence of functions in . Suppose that there exist satisfying ∥un(t)∥ ≤ γ(t) for almost all t ∈ [0, T0] and every n ≥ 1. Then, we have

()

Lemma 14. We assume that (H1) holds. Then the set , ∥u(ζ)∥ ≤ η(ζ) for a.e. ζ ∈ [0, T0]} is equicontinuous for all t ∈ [0, T0].

Proof. Let h be a positive constant such that 0 ≤ t < t + hT0. For , we have

()
It is obvious for t = 0. Let ϵ > 0 be arbitary integer with 0 < ϵ < t. For t > 0, we have
()
Since , t > 0 is equicontinuous; therefore,
()
as h → 0, uniformly for u. Second and third terms of (18) tend to zero when ϵ → 0 since ϵ is arbitrary small.

Then from (17), (18), and (19) and the absolute continuity of integrals, we obtain that , ∥u(ζ)∥ ≤ η(ζ) for a.e. ζ ∈ [0, T0]} is equicontinuous for all t ∈ [0, T0].

3. Main Results

In this section, the existence of the mild solution of (1)–(3) under some specified conditions on Gi is established by using the measure of noncompactness and fixed point theorem for convex-power condensing operator.

Now, we made the following hypothesis which will be useful for proving our results.
  • (HG)

    The functions Gi  (i = 1, …, δ) are compact and continuous.

  • (HF)

    F : [0, T] × XX is a nonlinear function such that F satisfies the Carathèodary condition; that is, we have the following.

    • (i)

      F(τ, ·) : XX is continuous for a.e. τ ∈ [0, T0].

    • (ii)

      For each xX, F(·, x):[0, T0] → X is strongly measurable. For any k > 0, there exists a function such that for uX

      ()

    • (iii)

      There exists a constant such that for any bounded set BX,

      ()

  • (HG1)

    The functions Gi are continuous and there exist positive constants such that

    ()

  • for all x, yX, τ ∈ (ti, si], (i = 1, …, δ).

  • (Hk)

    ()

  • (H)

    .

Theorem 15. Suppose that (H1), (HG), (HF), and (Hk) are satisfied. Then, there exists at least one mild solution on [0, T0] for the problem (1)–(3).

Proof. We define the operator as , , for all t ∈ (ti, si] and

()
for i = 0,1, …, δ and for t ∈ [si, ti+1], where i = 1, …, δ,
()
To prove the result, we show that the operator has a fixed point. Firstly, we show that the is continuous on . Let be a sequence in such that lim⁡nun = u in . For t ∈ [si, ti+1], we have
()
By the continuity of F and Gi  (i = 1 … , δ), we have
()
()
Therefore from (26), (27), (28), and Lebesgue dominated convergence theorem, we get
()
which implies that is continuous on [si, ti+1]. For t ∈ [0, t1], we get
()
From the (27), we get
()
thus, is continuous on [0, t1]. Hence, we conclude that is continuous on [0, T0].

Secondly, we claim that , where . For each and t ∈ [0, t1], we get

()
For t ∈ (si, ti+1], (i = 1, …, δ), we have
()
which implies that , for all i = 1, …, δ. On the other hand, by the property of Gi(·), we get
()
for t ∈ (ti, si].   By the assumption (Hk), we have .

Therefore, we conclude that ; that is, has values in Bk.

Now we show the equicontinuity of on [0, T0]. Since Gi(·) is compact, therefore it is obvious that is equicontinuous on (ti, si]. Assume t ∈ [0, t1]. Let h > 0 be a constant such that 0 < t < t + ht1 < T0. For uBk, we get

()
Using the semigroup property, we have
()
By the strong continuity of and Lemma 14, we conclude that is equicontinuous on [0, t1].

For t ∈ [si, ti+1] we have

()
Since we have
()
Gi(·) is compact and is strongly continuous, which implies that is equicontinuous on [si, ti+1]. Hence, is equicontinuous on each [0, T0].

Set , where conv and denote the convex hull and closure of the convex hull, respectively. It can be shown easily that maps B into itself and B is equicontinuous on each [0, t1], (ti, si], [si, ti+1], i = 1,2, …, δ. Next we prove that is a convex-power condensing operator. We take u0B and show that there exists a positive integer n0 such that

()
for every nonprecompact bounded subset HB. From (6), (15), and compactness of Gi, for t ∈ [si, ti+1], where i = 1, …, δ, we have
()
and similarly for t ∈ [0, t1], we have
()
For t ∈ [ti, si], we get by the fact that Gi(·) are compact.

Further for t ∈ [si, ti+1], we have

()
Proceeding with this iterative method, we get
()
for t ∈ [si, ti+1] and similarly for t ∈ [0, t1], we get . Thus, we obtain
()
for all t ∈ [0, T0].

We have that is equicontinuous on [0, T0] by Lemma 14. Therefore, from Lemma 11, we get

()
since we have that as n, which infers that there exists a substantial enough positive integer n0 such that
()
which means that is a convex-power condensing operator. Therefore, from Lemma 10, we get that has at least one fixed point in B which is just a mild solution to the problem (1)–(3). This completes the proof of the theorem.

In the next result, the existence of the solution for problem (1)–(3) under Lipschitz conditions of Gi is established by using Darbo-Sadovskii’s fixed point theorem.

Theorem 16. Suppose that assumptions (H1), (HF), (HG1), and (H) hold. Then, the impulsive problem (1)–(3) has at least one mild solution on [0, T0].

Proof. Firstly, we decompose the map such that , where , i = 0,1, 2, …, δ, j = 1,2, are defined as

()
()
For t ∈ (ti, si] and u, vBk, we have
()
and for t ∈ (si, ti+1]
()
therefore, for all t ∈ [0, T0] we conclude that
()
Since . By Lemma 5 (vii), we have that for any bounded set
()
For operator , we have
()
From (51)–(53), we have
()
From the assumption (H), we get that , which implies that map is β-condensing in Bk. Therefore, by Darbo-Sadovskii’s fixed point theorem, the solution map Q has a fixed point in Bk which is a mild solution of the nonlocal problem (1)–(3). This completes the proof of the theorem.

4. Example

Let us consider the following impulsive problem:
()
where 0 = t0 = s0 < t1s1 < ⋯<tNsN < tN+1 = T0 are fixed numbers, zX, , and , for all i = 1, …, N.
To convert problem (55) into the abstract form (1)–(3), where u(t) = w(t, ·), that is, u(t)x = w(t, x), we introduced the functions F : [0, T0] × XX and Gi : (ti, si] × XX such that F(t, u(t))(x) = f(t, w(t, x)) and Gi(t, u(t))(x) = gi(t, w(t, x)). We consider X = L2[0, π] and the operator A defined as −Au = u′′ with the the domain
()
It is well known (Pazy [21]) that −A is the infinitesimal generator of an analytic semigroup , t ≥ 0 and every analytic semigroup is equicontinuous. This means that A satisfies the assumption (H1).

Next we have that is a mild solution of the problem (55).

Case 1. We take

()
and here are continuous functions and . Now, we show that F satisfies the assumption (HF). Now, we have that for uX
()
and for u1, u2X
()
Therefore, for any bounded sets D1X, we obtain
()
where . For uX, we have
()
Clearly, Gi, i = 1, …, δ are compact and satisfy the assumption (HG). Then by Theorem 15, problem (55) has at least a mild solution.

Case 2. Take f(t, w(t, x)) = f1(t)w(t, x) and gi(t, w(t, x)) = (1/(5 + αit3))[|w(t, x)|/(1+|w(t, x)|)], ; here, is a bounded and continuous function and αi > 0.

For t ∈ (si, ti+1], i = 1, …, δ and , we have

()
where mk(t) = |f1(t)|. For any bounded set D1X, we have
()
where . Thus, (HF) holds. For , we have
()

Thus, (HG1) holds. Then by Theorem 16, problem (55) has at least a mild solution.

Conflict of Interests

The authors declare that there is no conflict of interests regarding the publication of this paper.

Acknowledgments

The authors would like to thank the referee for valuable comments and suggestions. The work of the first author is supported by the University Grants Commission (UGC), Government of India, New Delhi.

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