Spectral Criteria for Solvability of Boundary Value Problems and Positivity of Solutions of Time-Fractional Differential Equations
Abstract
We investigate mild solutions of the fractional order nonhomogeneous Cauchy problem , where 0 < α < 1. When A is the generator of a C0-semigroup (T(t)) t≥0 on a Banach space X, we obtain an explicit representation of mild solutions of the above problem in terms of the semigroup. We then prove that this problem under the boundary condition u(0) = u(1) admits a unique mild solution for each f ∈ C([0,1]; X) if and only if the operator I − Sα(1) is invertible. Here, we use the representation in which Φα is a Wright type function. For the first order case, that is, α = 1, the corresponding result was proved by Prüss in 1984. In case X is a Banach lattice and the semigroup (T(t)) t≥0 is positive, we obtain existence of solutions of the semilinear problem
1. Introduction
In the integer case α = 1, it is well known that there exists a strong connection between the spectrum of (T(t)) t≥0 and solutions of the inhomogeneous differential equation (1) satisfying the condition u(0) = u(1), where f is a forcing term. A complete characterization of the class of generators A such that for any given f ∈ C([0,1]; X), (1) with the condition u(0) = u(1) has a unique solution which was obtained by Prüss [1] in 1984, extending earlier results by Haraux (see [2]).
Denoting the resolvent set of an operator L by ρ(L), the result of Prüss reads as follows: 1 ∈ ρ(T(1)) if and only if for any f ∈ C([0,1]; X), the equation u′ = Au + f admits exactly one mild solution satisfying u(0) = u(1).
After Prüss theorem, many interesting consequences and related results have appeared. For example, the corresponding connection with the spectrum of strongly continuous sine functions [3], cosine functions [4], and connections with maximal Lp-regularity are discussed in [5–7].
While in the present paper, we concentrate on periodic boundary conditions, we mention the recent papers [11–13] dealing with fractional differential equations. The first two deal with nonlocal Cauchy problems, while the third considers the fractional evolution problem governed by an almost sectional operator and proceeds to construct the corresponding evolution operators by mean of a certain functional calculus.
The paper is organized as follows. In Section 2, we present some preliminaries on the resolvent families needed in the sequel. In Section 3, assuming that A generates a C0-semigroup, we represent the resolvent families of Section 2 using the subordination principle. In Section 4, we study mild solutions in general and in the periodic boundary valued case in particular. Positivity of mild solutions as well as the semilinear equation are considered in Section 5.
2. Preliminaries
The algebra of bounded linear operators on a Banach space X will be denoted by ℬ(X), the resolvent set of a linear operator A by ρ(A), and the spectral radius of a bounded operator S will be denoted by rσ(S). Let τ > 0 be a real number. The space of continuous functions f : [0, τ] → X is denoted by C([0, τ]; X) and its norm by ∥f∥∶ = sup {∥f(t)∥ : t ∈ [0, τ]}. We denote gα(t): = tα−1/Γ(α), α > 0, where Γ is the usual gamma function. It will be convenient to write g0 : = δ0, the Dirac measure concentrated at 0. Note the semigroup property: gα+β = gα*gβ for all α, β > 0.
- (i)
exponential function: E1,1(z) = ez;
- (ii)
cosine functions: E2,1(z2) = cosh (z) and E2,1(−z2) = cos (z);
- (iii)
sine functions: zE2,2(z2) = sinh (z) and zE2,2(−z2) = sin(z).
The following two definitions are taken from [16, 17], respectively.
Definition 1. Let A be a closed and linear operator with domain D(A) defined on a Banach space X and α > 0. We call A the generator of an (α, α)-resolvent family if there exists ω ≥ 0 and a strongly continuous function Pα : [0, ∞) → ℬ(X) (resp., Pα : (0, ∞) → ℬ(X) in case 0 < α < 1) such that {λα : Re(λ) > ω} ⊂ ρ(A) and
Definition 2. Let A be a closed and linear operator with domain D(A) defined on a Banach space X and α > 0. We call A the generator of an (α, 1)-resolvent family if there exists ω ≥ 0 and a strongly continuous function Sα : [0, ∞) → ℬ(X) such that {λα : Re(λ) > ω} ⊂ ρ(A) and
In the above definitions, the integrals involved are taken in the sense of Riemann, more precisely as improper Riemann integrals.
By the uniqueness theorem for the Laplace transform, a (1,1)-resolvent family is the same as a C0-semigroup; a (2,2)-resolvent family corresponds to the concept of sine family, while a (2,1)-resolvent family corresponds to a cosine family. See, for example, [18] and the references therein for an overview on these concepts. A systematic study in the fractional case is carried out in [17].
Some properties of (Pα(t)) and (Sα(t)) are included in the following lemma. Their proof uses techniques from the general theory of (a, k)-regularized resolvent families [19] (see also [16, 17]). It will be of crucial use in the investigation of mild solutions in Section 4.
Lemma 3. The following properties hold.
- (i)
Sα(0) = I.
- (ii)
Sα(t) D(A) ⊂ D(A) and ASα(t)x = Sα(t)Ax for all x ∈ D(A), t ≥ 0.
- (iii)
For all x ∈ D(A):, t ≥ 0.
- (iv)
For all x ∈ X:(gα*Sα)(t)x ∈ D(A) and
() - (v)
Pα(t)D(A) ⊂ D(A) and APα(t)x = Pα(t)Ax for all x ∈ D(A), t > 0.
- (vi)
For all x ∈ D(A):, t > 0.
- (vii)
For all x ∈ X:(gα*Pα)(t)x ∈ D(A) and
() - (viii)
For 0 < α < 1, lim t→0 t1−αPα(t) = (1/Γ(α))I, and P1(0) = I and for α > 1, Pα(0) = 0.
Proof. Let ω be as in Definitions 1 or 2. Let μ, λ > ω and x ∈ D(A). Then, x = (I − μ−αA) −1y for some y ∈ X. Since (I − λ−αA) −1 and (I − μ−αA) −1 are bounded and commute and since the operator A is closed, we obtain from the definition of Pα(t)
On the other hand, from the convolution theorems we obtain, for x ∈ D(A),
We now prove (iv) and (vii). Let x ∈ X and define y = (λ − A) −1x ∈ D(A), where λ ∈ ρ(A) is fixed. Let z = (gα*Sα)(t)x, t ≥ 0. We have to show that z ∈ D(A) and Az = Sα(t)x − x. Indeed, using (ii) and (iii), we obtain that
Let X be a Banach lattice with positive cone X+. We recall that a semigroup (T(t)) t≥0 on X is positive if for any x ∈ X+ and t ≥ 0, T(t)x ≥ 0. Similarly, an operator (A, D(A)) is resolvent positive if there is ω ∈ ℝ such that (ω, ∞) ⊂ ρ(A) and (λ − A) −1x ≥ 0 for all λ > ω and any x ∈ X+.
It is a well-known fact that a strongly continuous semigroup is positive if and only if its generator is resolvent positive. We finally will need the following result due to Zhang [10].
Theorem 4. Let X be a Banach lattice and A : X → X a nonlinear operator. Suppose that there exists a positive linear bounded operator B : X → X with rσ(B) < 1 and
3. Subordination
Concerning (α, α)-resolvent families, we prove the following important theorem, which is the main result of this section.
Theorem 5. Let 0 < α < 1. If A generates a C0-semigroup (T(t)) t≥0, then A generates an (α, α)-resolvent family (Pα(t)) given for every x ∈ X and t > 0 by
Proof. Since A generates a C0-semigroup (T(t)) t≥0, there exists ω > 0 such that {μ : Re(μ) > ω} ⊂ ρ(A) and
We next show that for Re(λ) large enough. In fact, by (32) and Fubini′s theorem, we obtain for every x ∈ X,
On the other hand, from (35) and the fact that A is closed, we obtain for all x ∈ D(A) that Pα(t)x ∈ D(A) and the identity
Remark 6. We observe that the paper [13] uses a different approach for the evolution operators Sα and Pα. More precisely, the authors consider an almost sectorial operator A in a Banach space and give a direct construction using the Mittag-Leffler functions.
4. Boundary Conditions
Note that for α = 1, the representation (46) is nothing else but the well-known variation of constant formula for the abstract Cauchy problem of first order, S1(t) ≡ P1(t) and corresponds exactly to T(t), the C0-semigroup generated by A.
Definition 7. Let A with domain D(A) be a closed linear operator on a Banach space X. Let and 0 < α < 1. Let Iα be the operator defined in (9). A function u ∈ C([0, ∞); X) is called a mild solution of the equation
We have the following representation of mild solutions.
Lemma 8. Suppose that the operator A generates a C0-semigroup (T(t)) t≥0, and let such that the mapping is exponentially bounded. Let u ∈ C([0, ∞); X), 0 < α < 1 and u(0)∶ = x ∈ X. Then, the following assertions are equivalent:
- (i)
Iαu(t) ∈ D(A), t ≥ 0 and u(t) = x + AIαu(t) + Iαf(t), t ≥ 0, that is, u is a mild solution of (49),
- (ii)
for all t > 0.
Note that the mapping is exponentially bounded if, for example, the function f ∈ ∪p≥1Lp((0, ∞); X) or f itself is exponentially bounded.
Proof of Lemma 8. (i) ⇒ (ii): Assume that assertion (i) holds. Then, u(t) − u(0) = AIαu(t) + Iαf(t). Taking the Laplace transform of this equality, we get that, , that is, . Therefore, , and . Hence,
(ii) ⇒ (i): As a consequence of (iv) and (vii) in Lemma 3, we have
Uniqueness of the classical solution follows from the lemma upon observing that any classical solution is necessarily a mild solution.
The following problem was considered by Prüss [1] when α = 1 and A generates a strongly continuous semigroup. If one starts with f ∈ C([0,1]; X) and solves the problem u′(t) = Au(t) + f(t) with the boundary condition u(0) = u(1), then the resulting solution can be extended to a periodic continuous function on ℝ. We observe that Haraux [2] had considered similar problems earlier.
For the fractional differential Equation (44), we obtain a mild solution on [0, ∞). In the next result (Theorem 9), we obtain a necessary and sufficient condition that the mild solution will satisfy the boundary condition u(0) = u(1).
We remark that the concept of periodic boundary valued solutions for fractional differential equations has been introduced in the literature by Belmekki et al. in the paper [9] as described in the introduction. In this line of research, we note that the paper [23] by Kaslik and Sivasundaram considers existence and nonexistence of periodic solutions of fractional differential equations for various definitions of the fractional derivative.
Theorem 9. Let X be a Banach space, and assume that A generates a C0 semigroup (T(t)) t≥0. Let (Sα(t)) be the subordinated (α, 1)-resolvent family. Then, 1 ∈ ρ(Sα(1)) if and only if for any f ∈ C([0,1]; X); (54) admits precisely one mild solution.
Proof. Suppose that 1 ∈ ρ(Sα(1)). Note that if the solution u of the differential equation in (54) satisfies the condition u(0) = u(1), then Lemma 8(ii) implies
Conversely, define Kα : C([0,1]; X) → C([0,1]; X) by means of (Kαf)(t) = u(t), where u(t) denotes the unique mild solution of (54). It is clear that Kα is linear and everywhere defined. Moreover, it is not difficult to show, using the closed graph theorem, that Kα is bounded. Now, for x ∈ X, consider
Remark 10. An alternative proof of the injectivity of (I − Sα(1)) in the preceding proof runs as follows: let x0 ∈ X be such that (I − Sα(1))x0 = 0 and set u(t): = Sα(t)x0. Then, u is a mild solution of (54) with the forcing term f = 0. Since the function u = 0 is also of mild solution of (54) (with the forcing term f = 0), the uniqueness of the solution yields x0 = u(0) = 0, proving that I − Sα(1) is injective.
We remark that the condition 1 ∈ ρ(Sα(1)) is trivially satisfied if ∥Sα(1)∥ < 1.
Corollary 11. Suppose that the operator A generates a C0-semigroup (T(t)) t≥0 satisfying lim t→∞∥T(t)∥ = 0. Then, for f ∈ C([0,1]; X), (54) admits exactly one mild solution.
Proof. First, observe that , x ∈ X and recall that Φα(s) ≥ 0, s ≥ 0, and . Since Φα(z) is a nonzero analytic function, it follows that for each τ > 0, we have . We first assume that (T(t)) t≥0 is contractive, that is, ∥T(t)∥ ≤ 1, t ≥ 0. Then, for x ∈ X,
Note that by [24, Prop. V.1.2 & V.1.7], the assumption on (T(t)) t≥0 is equivalent to the fact that (T(t)) t≥0 is exponentially stable.
In the following examples, the semigroups are exponentially stable.
Example 12. (1) Let Ω ⊂ ℝN be a bounded open set. Define the operator AD on L2(Ω) by
(2) Assume that Ω ⊂ ℝN is a bounded domain with a Lipschitz continuous boundary ∂Ω and let γ ∈ L∞(∂Ω) satisfy γ(x) ≥ γ0 > 0 for some constant γ0. Define the bilinear form aγ on L2(Ω) by
(3) Let Ω and γ be as in part (2). Let A be an elliptic operator in divergence form of the type
5. Positivity of Solutions and the Semilinear Equation
Throughout this section, X will be a real Banach lattice.
We begin with the following maximum principle based only on initial conditions.
Proposition 13. Let α ∈ (0,1) and A be the generator of a positive C0-semigroup (T(t)) t≥0. Assume that u is a mild solution of (49) such that
Proof. Let x ∈ X+. By the subordination formulae (34) and (36) and the fact that Φα is a probability density on [0, ∞), we obtain Sα(t)x ≥ 0 and Pα(t)x ≥ 0, respectively. Using the representation of the solution given in Lemma 8(ii), we see that u(t) ≥ 0 for all t ∈ [0,1].
Proposition 14. Let α ∈ (0,1) and A be the generator of a positive C0-semigroup (T(t)) t≥0. Suppose that (I − Sα(1)) −1x ≥ 0 for all x ∈ X+. Assume that u is a mild solution of (49) and that
Proof. Under the given hypothesis, we have u(0) ≥ 0 by (56). Hence, the result follows from Proposition 13.
We mention that the condition in (73) or in (74) is equivalent to f(t) ≥ 0, since by hypothesis, u is a mild solution of (49).
Note that if the spectral radius of Sα(1), that is, rσ(Sα(1)), is less than 1, then the inverse (I − Sα(1)) −1 is given by the Neumann series , from which it follows that , since Sα(1) ≥ 0.
The following corollary shows that the result obtained by Nieto (mentioned at the beginning of this section) using the Riemann-Liouville fractional derivative also holds for the Caputo fractional derivative.
Corollary 15. Let α ∈ (0,1) and λ ∈ ℝ. Suppose that Eα,1(λ) < 1. Assume that u is a mild solution of (54) with A = λI and satisfies
Proof. By Definition 2 and formula (14), we have Sα(t) = Eα,1(λtα). Moreover, the semigroup generated by A is given by T(t) = eλtI which is positive. The condition Eα,1(λ) < 1 implies that (I − Sα(1)) −1x = (1 − Eα,1(λ)) −1x ≥ 0 for all x ∈ X+. Hence, the result follows from Proposition 14.
Theorem 16. Let A generate a positive C0-semigroup (T(t)) t≥0 on a Banach lattice X. Let τ > 0 be a fixed real number. Suppose that there exist constants M ≥ 0, N ≥ 0 such that for all s ∈ [0, τ] and x1, x2 ∈ X with x1 ≥ x2,
Proof. Define the operator Qα : C([0, τ]; X) → C([0, τ]; X) by
For any u, v ∈ C([0, τ]; X), u ≤ v, and t ∈ [0, τ], we have
Remark 17. The above result remains valid if instead of f(t, u(t)) we consider the more general nonlinearity of [10], namely,
Acknowledgments
The authors are most grateful to the referees for careful reading of the paper and for providing several useful observations that helped to improve the paper. The authors are partially supported by the Project PIA ACT 1112. C. Lizama is also supported by Fondecyt Grant 1110090.