Completing a 2 × 2 Block Matrix of Real Quaternions with a Partial Specified Inverse
Abstract
This paper considers a completion problem of a nonsingular 2 × 2 block matrix over the real quaternion algebra ℍ: Let m1, m2, n1, n2 be nonnegative integers, m1 + m2 = n1 + n2 = n > 0, and be given. We determine necessary and sufficient conditions so that there exists a variant block entry matrix such that is nonsingular, and B11 is the upper left block of a partitioning of A−1. The general expression for A11 is also obtained. Finally, a numerical example is presented to verify the theoretical findings.
1. Introduction
Problem 1. Suppose m1, m2, n1, n2 are nonnegative integers, m1 + m2 = n1 + n2 = n > 0, and . Find a matrix such that
Throughout, over the real quaternion algebra ℍ, we denote the identity matrix with the appropriate size by I, the transpose of A by AT, the rank of A by r(A), the conjugate transpose of A by , a reflexive inverse of a matrix A over ℍ by A+ which satisfies simultaneously AA+A = A and A+AA+ = A+. Moreover, LA = I − A+A, RA = I − AA+, where A+ is an arbitrary but fixed reflexive inverse of A. Clearly, LA and RA are idempotent, and each is a reflexive inverse of itself. ℛ(A) denotes the right column space of the matrix A.
The rest of this paper is organized as follows. In Section 2, we establish some necessary and sufficient conditions to solve Problem 1 over ℍ, and the general expression for A11 is also obtained. In Section 3, we present a numerical example to illustrate the developed theory.
2. Main Results
In this section, we begin with the following lemmas.
Lemma 1 (singular-value decomposition [9]). Let A ∈ ℍm×n be of rank r. Then there exist unitary quaternion matrices U ∈ ℍm×m and V ∈ ℍn×n such that
Let denote the collection of column vectors with n components of quaternions and A be an m × n quaternion matrix. Then the solutions of Ax = 0 form a subspace of of dimension n(A). We have the following lemma.
Lemma 2. Let
Proof. It is readily seen that
If n(B22) = 0, necessarily n(A11) = 0 and we are finished. Let n(B22) = c > 0, then there exists a matrix F with c right linearly independent columns, such that B22F = 0. Then, using
From
Thus
Lemma 3 (see [10].)Let A ∈ ℍm×n, B ∈ ℍp×q, D ∈ ℍm×q be known and X ∈ ℍn×p unknown. Then the matrix equation
, , , are unitary quaternion matrices, where , , , and .
Theorem 4. Problem 1 has a solution if and only if the following conditions are satisfied:
- (a)
,
- (b)
n2 − r(A22) = m1 − r(B11), that is n2 − s = m1 − r,
- (c)
ℛ(A21B11) ⊂ ℛ(A22),
- (d)
.
In that case, the general solution has the form of
Proof. If there exists an m1 × n1 matrix A11 such that A is nonsingular and B11 is the corresponding block of A−1, then (a) is satisfied. From AB = BA = I, we have that
By (11), we have
Conversely, from (c), we know that there exists a matrix such that
It follows that
This implies that
Comparing corresponding blocks in (30), we obtain
Let . From (29), (30), we have
In the same way, from (d), we can obtain
From AB = I, we have the following matrix equation:
3. An Example
In this section, we give a numerical example to illustrate the theoretical results.
Example 5. Consider Problem 1 with the parameter matrices as follows:
It is easy to show that (c), (d) are satisfied, and that
By Theorem 4, for an arbitrary matrices Y ∈ ℍ2×2, we have
Acknowledgments
The authors would like to give many thanks to the referees and Professor K. C. Sivakumar for their valuable suggestions and comments, which resulted in a great improvement of the paper. This research was supported by Grants from the Key Project of Scientific Research Innovation Foundation of Shanghai Municipal Education Commission (13ZZ080), the National Natural Science Foundation of China (11171205), the Natural Science Foundation of Shanghai (11ZR1412500), the Discipline Project at the corresponding level of Shanghai (A. 13-0101-12-005), and Shanghai Leading Academic Discipline Project (J50101).