Existence of Multiple Solutions for a Singular Elliptic Problem with Critical Sobolev Exponent
Abstract
We consider the existence of multiple solutions of the singular elliptic problem , u(x) → 0 as |x| → +∞, where x ∈ ℝN, 1 < p < N, a < (N − p)/p, a ≤ b ≤ a + 1, r, s > 1, p* = Np/(N − pd), d = a + 1 − b. By the variational method and the theory of genus, we prove that the above-mentioned problem has infinitely many solutions when some conditions are satisfied.
1. Introduction and Main Results
-
(A1) for 1 < r < p, where ;
-
(A2) for p < r < p*, where .
-
(A3) for p < s < p*, where .
Then, we give some basic definitions.
Definition 1.1. u ∈ X is said to be a weak solution of (1.1) if for any there holds
Our main result in this paper is the following.
Theorem 1.2. Let 1 < p < N, a < (N − p)/p, a ≤ b ≤ a + 1, r > 1, p* = Np/(N − pd), d = a + 1 − b, max {r, p} < s < p*. Assume (A1)–(A3) are fulfilled. Then problem (1.1) has infinitely many solutions in X.
2. Preliminary Results
Our proof is based on variational method. One important aspect of applying this method is to show that the functional I(u) satisfies (PS) c condition which is introduced in the following definition.
Definition 2.1. Let c ∈ R1 and X be a Banach space. The functional I(u) ∈ C1(X, R) satisfies the (PS) c condition if for any {un} ⊂ X such that
The following embedding theorem is an extension of the classical Rellich-Kondrachov compactness theorem, see [14].
Lemma 2.2. Suppose Ω ⊂ ℝN is an open bounded domain with C1 boundary and 0 ∈ Ω. N ≥ 3, a < (N − p)/p. Then the embedding is continuous if 1 ≤ r ≤ Np/(N − p) and 0 ≤ α ≤ (1 + a)r + N(1 − r/p), and is compact if 1 ≤ r < Np/(N − p) and 0 ≤ α < (1 + a)r + N(1 − r/p).
Now we prove an embedding theorem, which is important in our paper.
Lemma 2.3. Assume (A1)-(A2) and 1 < r < p*. Then the embedding X↪Lr(ℝN, f) is compact.
Proof. We split our proof into two cases.
(i) Consider 1 < r < p.
By the Hölder inequality and (1.9) we have that
Let BR be a ball center at origin with the radius R > 0. For the convenience, we denote Lr(ℝN, f) by Z, that is, Z = Lr(ℝN, f). Assume {un} is a bounded sequence in X. Then {un} is bounded in X(BR). We choose α = 0 in Lemma 2.2, then there exist u ∈ Z(BR) and a subsequence, still denoted by {un}, such that as n → ∞. We want to prove that
In the following, we will prove that un → u strongly in Z(RN).
Since X is a reflexive Banach space and {un} is bounded in X. Then we may assume, up to a subsequence, that
(ii) Consider p ≤ r < p*.
It follows from (1.8) and the Hölder inequality that
Similarly, we have the following result of compact embedding.
Lemma 2.4. Assume 1 < p < s < p* and (A3), then the embedding X↪Ls(ℝN, h) is compact.
The following concentration compactness principle is a weighted version of the Concentration Compactness Principle II due to Lions [15–18], see also [19, 20].
Lemma 2.5. Let 1 < p < N, − ∞ < a < (N − p)/p, a ≤ b ≤ a + 1, p* = Np/(N − pd), d = a + 1 − b. Suppose that is a sequence such that
- (1)
There exists some at most countable set J, a family {xj ∈ Ω∣j ∈ J} of distinct points in ℝN, and a family {ηj∣j ∈ J} of positive numbers such that
(2.14)where is the Dirac measure at xj. - (2)
The following equality holds
(2.15)for some family {μj > 0∣j ∈ J} satisfying(2.16) - (3)
There hold
(2.17)where(2.18)
Lemma 2.6. Let 1 < p < r < s < p*. Then I(u) satisfies the (PS) c condition with , where S1 is as in (1.8).
Proof. We will split the proof into three steps.
Step 1. {un} is bounded in X.
Let {un} be a (PS) c sequence of I(u) in X, that is,
Step 2. There exists {un} in X such that un → u in .
The inequality (1.8) shows that {un} is bounded in . Then the above argument and the compactness embedding in Lemma 2.2 mean that the following convergence hold:
For the proof of ηj = 0, we define the functional such that
Similarly, we define the functional as
Step 3. {un} converges strongly in X.
The following inequalities [21] play an important role in our proof:
Then the Hölder inequality together with (1.8) and (2.30) yield that
Similarly, we have the following lemma.
Lemma 2.7. Let 1 < r < p < s < p*. Then I(u) satisfies the (PS) c condition with , where S1, S2 are as in (1.8), and (1.9) respectively.
Proof. Step 1. {un} is bounded in X.
Let {un} be a (PS) c sequence of I(u) in X. Then we have from Lemma 2.3 that
Step 2. There exists {un} in X such that un → u in .
Similar to the proof of Lemma 2.5, we can get that μj = ηj = 0 or by applying the functional ψ. Now we prove that there is no j0 ∈ J such that . Suppose otherwise, then
Step 3. {un} converges strongly in X.
By Lemma 2.4, this result can be similarly obtained by the method in Lemma 2.6, so we omit the proof.
3. Existence of Infinitely Solutions
Proposition 3.1. Let A, B ∈ 𝒜. Then
- (1)
if there exists an odd map g ∈ C(A, B), then γ(A) ≤ γ(B),
- (2)
if A ⊂ B, then γ(A) ≤ γ(B),
- (3)
γ(A⋃ B) ≤ γ(A) + γ(B).
- (4)
if S is a sphere centered at the origin in ℝN, then γ(S) = N,
- (5)
if A is compact, then γ(A) < ∞ and there exists δ > 0 such that Nδ(A) ∈ 𝒜 and γ(Nδ(A)) = γ(A), where Nδ(A) = {x ∈ X : ∥x − A∥≤δ}.
Lemma 3.2. Assume (A1)–(A3). Then for any m ∈ N, there exists ε = ε(m) > 0 such that
Proof. For given m ∈ ℕ+, let Xm be a m-dimensional subspace of X. If p < r < s < p*, then for u ∈ Xm we have
If r < p < s < p*, we have
Therefore, Proposition 3.1 shows that γ(I−ε) ≥ γ(Sσ) = m.
Then, Kc is compact and we have the following important lemma, see [22].
Lemma 3.3. All the cm are critical values of I(u). Moreover, if c = cm = cm+1 = ⋯ = cm+τ, then γ(Kc) ≥ 1 + τ.
Proof of Theorem 1.2. In view of Lemmas 2.6 and 2.7, I(u) satisfies the (PS) c condition in X. Furthermore, as the standard argument of [13, 22, 23], Lemma 3.3 gives that I(u) has infinity many critical points with negative values. Thus, problem (1.1) has infinitely many solutions in X, and we complete the proof.
Acknowledgments
The author would like to express his sincere gratitude to the anonymous reviewers for the valuable comments and suggestions.