Volume 2011, Issue 1 801313
Research Article
Open Access

Almost α-Hyponormal Operators with Weyl Spectrum of Area Zero

Vasile Lauric

Corresponding Author

Vasile Lauric

Department of Mathematics, Florida A&M University, Tallahassee, FL 32307, USA famu.edu

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First published: 22 May 2011
Academic Editor: Raül Curto

Abstract

We define the class of almost α-hyponormal operators and prove that for an operator T in this class, is trace-class and its trace is zero when α ∈ (0, 1] and the area of the Weyl spectrum is zero.

This note is dedicated to Professor Carl M. Pearcy with the occasion of his 75th birthday.

Let be a complex, separable, infinite-dimensional Hilbert space, and let L() denote the algebra of all linear bounded operators on , and for 1 ≤ p < , let 𝒞p() denote the p-Schatten class on . For K𝒞p(), the expression , where μ1(K) ≥ μ2(K) ≥ ⋯ are the singular values of K, is a norm for p ≥ 1, and is only a quasinorm for 0 < p < 1 (it does not satisfy the triangle inequality). Nevertheless, the latter case will be used in what follows.

For TL(),  σ(T) and σw(T) will denote the spectrum and the Weyl spectrum, respectively. Recall that Weyl spectrum is the union of the essential spectrum, σe(T), and all bounded components of σe(T) associated with nonzero Fredholm index. An operator TL() is called (𝒞p, α)-normal (notation: ) if belongs to 𝒞p(), and T is called (𝒞p, α)-hyponormal (notation: ) if is the sum of a positive definite operator and an operator in 𝒞p(), or equivalently, (the negative part of ) belongs to 𝒞p(), where α is a positive number. This note will be concerned with the particular class , which by some parallelism with some terminology used in [1], would be appropriate to be referred as almost α-hyponormal operators.

Voiculescu′s [1] generalization of Berger-Shaw inequality gives an estimate for the trace of . The result was extended in [2]. The combination of these results will be stated after recalling some terminology and notation. The rational cyclic multiplicity of an operator T in L(), denoted by m(T), is the smallest cardinal number m with the property that there are m vectors x1, …, xm in such that
(1)
where Rat(σ(T)) is the algebra of complex-valued rational functions with poles off σ(T).

For a Borel subset E and α > 0, denote μα(E) = (α/2)∬Eρα−1  dρdθ. In particular, μ2 is the planar Lebesgue measure.

Theorem A (see [1], [2].)Suppose . If there exists K𝒞2() such that either m(T + K) < or μ2(σ(T + K)) = 0, then . Moreover, when m(T + K) < ,

(2)
and when μ2(σ(T + K)) = 0,,   and consequently, .

In fact, it was observed in [2] that the inequality can be improved by replacing m(T + K) with τ(T + K), where
(3)
and the liminf  is taken over all sequences of finite-rank orthogonal projections such that PI in the strong operator topology.

Corollary B (see [2].)Let such that μ2(σw(T)) = 0. Then and .

On the other hand, Berger-Shaw inequality was extended to operators in using similar circle of ideas used in [1]. This was done in [3] for the case α ∈ [(1/2), 1] and later on in [4] for the case α ∈ (0, (1/2)].

Theorem C (see [3], [4].)Let 0 < α ≤ 1, and let and K𝒞2α() with m(T + K) < . Then and

(4)

The case in which m(T + K) = and μ2α(σ(T + K)) = 0 was not discussed in [4] or [3]. It is the goal of this note to make some progress towards this case. We have the following.

Theorem 1. Let α ∈ (0,1) and let and K𝒞α() with μ2α(σ(T + K)) = 0. Then and .

Remark. It would have been desirable that Theorem 1 be proved with the hypothesis that K𝒞2α().

Before we prove Theorem 1, we extract a similar consequence to Corollary B.

Corollary 2. Let α ∈ (0,1] and let such that μ2(σw(T)) = 0. Then and .

Proof. If α = 1, then conclusion holds according to Corollary B. Let α ∈ (0,1). First, a careful inspection of the proof of a result of Stampfli [5] leads to the following. For TL() and α > 0, there exists Kα𝒞α() such that σ(T + Kα)∖σw(T) consists of a countable set which clusters only on σw(T). Therefore μ2(σ(T + Kα)) = 0 and thus Theorem 1 applies.

The proof of Theorem 1 makes use of the following three inequalities.

Proposition D (Hansen′s inequality [6]). If A, BL(), A ≥ 0, | | B|| ≤ 1, and α ∈ (0,1], then B*AαB ≤ (B*AB) α.

Proposition E (Lowner′s inequality [7]). If A, BL(), AB ≥ 0, and α ∈ (0,1], then AαBα.

The following is a consequence of Theorem 3.4 of [8].

Proposition F (Jocic′s inequality [8]). Let A, BL(), A,   B ≥ 0, α ∈ (0,1], and 1 ≤ p < . If AB𝒞αp(), then AαBα𝒞p() and | | BαAα | |p≤| |    | BA|α   | |p.

Proof of Theorem 1. Let α ∈ (0,1),  , and K𝒞α() with μ2α(σ(T + K)) = 0, and assume m(T + K) = , otherwise Theorem C implies .

Let {en} n be an orthonormal basis of and let

(5)
Assume that with respect to the decomposition , operators T and K are written as
(6)
Since n is a rationally invariant subspace for T + K, we have T3n + K3n = 0, and thus T3n = −K3n𝒞α(n)⊆𝒞2α(n), and σ(T1n + K1n)⊆σ(T + K), which implies μ2α(σ(T1n + K1n)) = 0.

Let Pn be the orthogonal projection onto n, and thus PnI strongly. We will prove next that by first establishing that

(7a)
where is positive semidefinite and .

Assuming that equality (7a) was already proved and writing with Q ≥ 0 and K𝒞1(), then we have

(7b)
that is, is the sum of , which is a positive semidefinite operator, and of , which is a trace-class operator.

Indeed, the expression can be written as D1D2, where

(8)
We can write , where
(9)
which according to Hansen′s inequality is a positive semidefinite operator, and
(10)
which according to Jocic′s inequality is a trace-class operator that satisfies
(11)
Concerning operator D2, we can write , where
(12)
which according to Lowner′s inequality is a positive semidefinite operator, and
(13)
which is also a trace-class operator since
(14)
and according to Jocic′s inequality
(15)
Therefore,
(16)
and consequently, , where is positive semidefinite and is trace-class, which establishes equality (7a).

According to (7b), , and since m(T1n + K1n) ≤ n and σ(T1n + K1n)⊆σ(T + K), Theorem C implies that ,   and furthermore, by replacing T1n with ,    . Furthermore, equality (7a) implies

(17)
which further implies
(18)
Similar utilization of Lowner′s and Hansen′s inequalities implies that and are positive semidefinite, and thus so is . Therefore
(19)
Since T3n = −K3n𝒞p(n) and K3n → 0 weakly and both |T3n| and ,   we have | | T3n | |α → 0, and thus . Replacing T with T* we conclude that .

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