Stability of Admissible Functions
Abstract
By using the concept of the weak subordination, we examine the stability (a class of analytic functions in the unit disk is said to be stable if it is closed under weak subordination) for a class of admissible functions in complex Banach spaces. The stability of analytic functions in the following classes is discussed: Bloch class, little Bloch class, hyperbolic little Bloch class, extend Bloch class (Qp), and Hilbert Hardy class (H2).
1. Introduction
If f and g are analytic functions with f, g ∈ 𝒢(X, Y), then f is said to be weakly subordinate to g, written as f≺wg if there exist analytic functions ϕ, ω : U → X, with ϕ an inner function (∥ϕ∥X ≤ 1), so that f∘ϕ = g∘ω. A class 𝒞 of analytic functions in X is said to be stable if it is closed under weak subordination, that is, if f ∈ 𝒞 whenever f and g are analytic functions in X with g ∈ 𝒞 and f≺wg.
By making use of the above concept of the weak subordination, we examine the stability for a class of admissible functions in complex Banach spaces 𝒢(X, Y). The stability of analytic functions appears in Bloch class, little Bloch class, hyperbolic little Bloch class, extend Bloch class (Qp), and Hilbert Hardy class (H2).
2. Stability of Bloch Classes
Theorem 2.1. Let X be a complex Banach space. If X contains all inner functions in U, then 𝒢(X, X) is stable.
Proof. Suppose that X contains all inner functions I : U → X. Take g(z) = ϕ(z) = z and ω(z) = I(z) (z ∈ U). Then, ϕ and ω are inner functions and I = I∘ϕ = g∘ω. Hence, I≺wg, g ∈ X, and I ∈ X. Thus, X is stable.
Theorem 2.2. Let X = ℋ(U) be a space of analytic functions in U which satisfies ℬ ⊂ X. Then, 𝒢(U, X) is stable.
Proof. Suppose that X = ℋ(U) and ℬ ⊂ X. Let f ∈ X, ℰ = {m + ni : m, n ∈ ℤ} and F = {z ∈ U : f(z) ∈ ℰ}. Since F is a countable subset of U, it has capacity zero and therefore the universal covering map I from U onto U∖F is an inner function (see, e.g., Chapter 2 of [1]). Set g = f∘I, then the image of g is contained in ℂ/ℰ. Consequently, see [2], g is a Bloch function. Since ℬ ⊂ X, we have that g = f∘I ∈ X even though f ∈ X. Thus, X is stable.
Theorem 2.3. Let X = ℋ(U) be a space of analytic functions in U and f ∈ 𝒢(X, X). If I : U → X satisfying I(0) = Θ (the zero element in X) and ∥f(I(z))∥X < 1, then 𝒢(X, X) is stable.
Proof. Assume that X = ℋ(U), f ∈ 𝒢(X, X), and I : U → X with I(0) = Θ. Then (see [3])
Next we discuss the stability of the spaces ℬ0 and . An analytic self-map φ of U induces a linear operator Cφ : ℋ(U) → ℋ(U), defined by Cφf = f∘φ. This operator is called the composition operator induced by φ.
Recall that a linear operator T : X → Y is said to be bounded if the image of a bounded set in X is a bounded subset of Y, while T is compact if it takes bounded sets to sets with compact closure. Furthermore, if T is a bounded linear operator, then it is called weakly compact, if T takes bounded sets in X to relatively weakly compact sets in Y. By using the operator Cφf, we have the following result.
Theorem 2.4. If 𝒢(ℬ0, ℬ0) is compact, then it is stable.
Proof. Assume the analytic self-map φ of U and f ∈ ℬ0; thus, we have the linear operator Cφ : ℬ0 → ℬ0, defined by Cφf = f∘φ : = g. By the assumption, we obtain that g is compact function in ℬ0. Hence, φ is an inner function [4, Corollary 1.3] which implies the stability of 𝒢(ℬ0, ℬ0).
Theorem 2.5. Let φ be holomorphic self-map of U such that
Proof. Assume the analytic self-map φ of U and f ∈ ℬ0; hence, in virtue of [5, Theorem 4.7], it is implied that the composition operator Cφf on ℬ0 is compact. Thus we pose that 𝒢(ℬ0, ℬ0) is stable.
Theorem 2.6. Consider φ is a holomorphic self-map of U, satisfying the following condition: for every ϵ > 0, there exists 0 < r < 1 such that
Proof. Assume the analytic self-map φ of U and f ∈ ℬ0; hence, in virtue of [5, Theorem 4.8], it is yielded that the composition operator Cφf on ℬ0 is compact. Hence, we obtain that 𝒢(ℬ0, ℬ0) is stable.
Theorem 2.7. If Cφf is weakly compact in ℬ0, then 𝒢(ℬ0, ℬ0) is stable.
Proof. According to [5, Theorem 4.10], we have that Cφf is compact in ℬ0 and, consequently, 𝒢(ℬ0, ℬ0) is stable.
Theorem 2.8. Let φ be holomorphic self-map of U. If the function
Proof. Assume the analytic self-map φ of U and . Since τφ(z) is bounded, then in virtue of [4, Theorem 1.2], it is yielded that φ is an inner function. By putting g : = f∘φ, where , we have the desired result.
Theorem 2.9. If , then 𝒢(ℬ0, ℬ0) is stable.
Proof. Following [4], it will be shown that there are inner functions ; then, Cφ : ℬ0 → ℬ0 is compact (see [4, 5]). Thus, 𝒢(ℬ0, ℬ0) is stable.
Theorem 2.10. Let φ be self-map in U and w : (0,1]→(0, ∞) be continuous with lim t=0w(t) = 0 satisfying
Proof. According to [5, Theorem 5.15], we pose that φ is inner. Thus, in view of [4, Corollary 1.3], Cφ : ℬ0 → ℬ0 is compact; hence, 𝒢(ℬ0, ℬ0) is stable.
Remark 2.11. The Schwarz-Pick Lemma implies
(i) Cφ maps ℬ to ℬ;
(ii) 0 ≤ |τφ(z)| ≤ 1;
(iii) φ ∈ ℬ0 if Cφ maps ℬ0 → ℬ0 and conversely, f, φ ∈ ℬ0⇒f∘φ ∈ ℬ0.
3. Stability of the Hilbert Hardy Space
Theorem 3.1. Let φ be self-map of U and f ∈ H2. If (1.1) holds, then 𝒢(H2, H2) is stable.
Proof. Assume the analytic self-map φ of U and f ∈ H2. Condition (1.1) implies that φ is an inner function. By setting g : = Cφf = f∘φ and, consequently, g ∈ H2, it is yielded that 𝒢(H2, H2) is stable.
Next we will show that the compactness of Cφf introduces the stability of 𝒢(H2, H2). Two positive (or complex) measures μ and ν defined on a measurable space (Ω, Σ) are called singular if there exist two disjoint sets A and B in Σ whose union is Ω such that μ is zero on all measurable subsets of B while ν is zero on all measurable subsets of A.
Theorem 3.2. If the composition operator Cφf : H2 → H2 is compact, then 𝒢(H2, H2) is stable.
Proof. Since Cφ : H2 → H2 is compact, all the Aleksandrov measures of φ are singular absolutely continuous with respect to the arc-length measure (see [7, 8]). Thus, in view of [4, Remark 1], φ is inner. By letting g : = Cφf = f∘φ, and, consequently, g ∈ H2, it is yielded that 𝒢(H2, H2) is stable.
Theorem 3.3. If φ has values never approach the boundary of U, then 𝒢(H2, H2) is stable.
Proof. Assume the composition operator Cφ : H2 → H2. Since φ has values never approach the boundary of U:
Remark 3.4. (i) It is well known that if Cφ is compact on H2, then it is compact on Hp for all 0 < p < ∞ (see [9, Theorem 6.1]).
(ii) Cφ is compact on H∞ if and only if ∥φ∥∞ < 1 (see [10, Theorem 2.8]).
Theorem 3.5. If is univalent then, is stable, where are the classical Bergman and Hardy spaces.
Proof. Since φ is univalent, is compact for all 0 < p < q < ∞(see [11, Theorem 6.4]). In view of Remark 3.4, we obtain that φ is an inner function; hence, is stable.
Next, we use the angular derivative criteria to discuss the stability of admissible functions. Recall that φ has angular derivative at ζ ∈ ∂U if the nontangential lim w = f(ζ) ∈ ∂U exists and if (f(z) − f(ζ))/(z − ζ) converges to some μ ∈ ℂ as z → ζ nontangentially.
Theorem 3.6. If φ satisfies both the angular derivative criteria and
4. Stability of Qp Class
Theorem 4.1. If f ∈ Q1, then 𝒢(Q1, Q1) is stable.
Proof. In the similar manner of Theorem 2.2, we pose an inner function φ on U. Now, in view of [15, Theorem H], yields g : = f∘φ ∈ Q1, even though f ∈ Q1. Thus, Q1 is stable.
Theorem 4.2. If f ∈ Λα, 0 < α < 1 such that
5. Conclusion
From above, we conclude that the composition operator Cφ, of admissible functions in different complex Banach spaces, plays an important role in stability of these spaces. It was shown that the compactness of this operator implied the stability, when φ is an inner function on the unit disk U. Furthermore, weakly compactness imposed the stability of Bloch spaces. In addition, noncompactness leaded to the stability for some spaces such as Qp-spaces and Lipschitz spaces.