Volume 2010, Issue 1 548702
Review Article
Open Access

Infinitely Many Solutions for a Robin Boundary Value Problem

Aixia Qian

Corresponding Author

Aixia Qian

School of Mathematic Sciences, Qufu Normal University, Qufu Shandong 273165, China qfnu.edu.cn

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Chong Li

Corresponding Author

Chong Li

Institute of Mathematics, AMSS, Academia Sinica, Beijing 100080, China sinica.edu

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First published: 22 November 2009
Citations: 5
Academic Editor: Wenming Zou

Abstract

By combining the embedding arguments and the variational methods, we obtain infinitely many solutions for a class of superlinear elliptic problems with the Robin boundary value under weaker conditions.

1. Introduction

In this paper, we consider the following equation:

(1.1)
where Ω is a bounded domain in n with smooth boundary Ω and 0 ≤ bL(Ω). Denote
(1.2)
and let λ1λ2 ≤ ⋯≤λj < ⋯ be the eigenvalues of −Δ with the Robin boundary conditions. We assume that the following hold:
  • f1 , ∃q ∈ (2, 2*) such that

    (1.3)

where 1 ≤ s < 2N/(N − 2), N ≥ 3. If N = 1,2, let 2* = ;

  • f2 f(x, s)s ≥ 0, lim |s|→+(f(x, s)s)/|s|2 = + uniformly for x ∈ Ω.

  • f3 there exist θ ≥ 1, s ∈ [0,1] s.t.

(1.4)
  • f4 f(x, −t) = −f(x, t), (x, t) ∈ Ω × .

Because of (f2), (1.1) is usually called a superlinear problem. In [1, 2], the author obtained infinitely many solutions of (1.1) with Dirichlet boundary value condition under (f1), (f4) and

  • (AR) ∃ μ > 2, R > 0 such that

(1.5)

Obviously, (f2) can be deduced form (AR). Under (AR), the (PS) sequence can be deduced bounded. However, it is easy to see that the example [3]

(1.6)
does not satisfy (AR), while it satisfies the aforementioned conditions (take θ = 1 in (f3)). (f3) is from [3, 4].

We need the following condition (C), see [3, 5, 6].

Definition 1.1. Assume that X is a Banach space, we say that JC1(X, ) satisfies Cerami condition (C), if for all c:

  • (i)

    any bounded sequence {un} ⊂ X satisfying J(un) → c, J(un) → 0 possesses a convergent subsequence;

  • (ii)

    there exist σ, R, β > 0 s.t. for any uJ−1([cσ, c + σ]) with ∥u∥≥R, ∥J(u)∥∥u∥≥β.

In the work in [2, 7], the Fountain theorem was obtained under the condition (PS). Though condition (C) is weaker than (PS), the well-known deformation theorem is still true under condition (C) (see [5]). There is the following Fountain theorem under condition (C).

Assume , where Xj are finite dimensional subspace of X. For each k, let

(1.7)
Denote Sρ = {uX : ∥u∥ = ρ}.

Proposition 1.2. Assume that JC1(X, ) satisfies condition (C), and J(−u) = J(u). For each k, there exist ρk > rk > 0 such that

  • (i)

    , k,

  • (ii)

    .

Then J has a sequence of critical points un, such that J(un)→+ as n.

As a particular linking theorem, Fountain theorem is a version of the symmetric Mountain-Pass theorem. Using the aforementioned theorem, the author in [6] proved multiple solutions for the problem (1.1) with Neumann boundary value condition; the author in [3] proved multiple solutions for the problem (1.1) with Dirichlet boundary value condition. In the present paper, we also use the theorem to give infinitely many solutions for problem (1.1). The main results are follows.

Theorem 1.3. Under assumptions (f1)–(f4), problem (1.1) has infinitely many solutions.

Remark 1.4. In the work in [1, 2], they got infinitely many solutions for problem (1.1) with Dirichlet boundary value condition under condition (AR).

Remark 1.5. In the work in [8], they showed the existence of one nontrivial solution for problem (1.1), while we get its infinitely many solutions under weaker conditions than [8].

Remark 1.6. In the work in [9], they also obtained infinitely many solutions for problem (1.1) with Dirichlet boundary value condition under stronger conditions than the aforementioned (f2) and (f3) above. Furthermore, function (1.6) does not satisfy all conditions in [9]. Therefore, Theorem 1.3 applied to Dirichlet boundary value problem improves those results in [1, 2, 8, 9].

2. Preliminaries

Let the Sobolev space X = H1(Ω). Denote

(2.1)
to be the norm of u in X, and |u|q the norm of u in Lq(Ω). Consider the functional J : X:
(2.2)
Then by (f1), J is C1 and
(2.3)
The critical point of J is just the weak solution of problem (1.1).

Since we do not assume condition (AR), we have to prove that the functional J satisfies condition (C) instead of condition (PS).

Lemma 2.1. Under (f1)–(f3), J satisfies condition (C).

Proof. For all c, we assume that {un} ⊂ X is bounded and

(2.4)
Going, if necessary, to a subsequence, we can assume that unu in X, then
(2.5)
that is,
(2.6)

Since the Sobolev imbedding W1,2(Ω)↪Lγ(Ω) (1 ≤ γ < 2*) is compact, we have the right-hand side of (2.6) converges to 0. While ∫Ωb(x)(unu) 2dS ≥ 0, we have ∥unu2 → 0. It follows that unu in X and J(u) = 0, that is, condition (i) of Definition 1.1 holds.

Next, we prove condition (ii) of Definition 1.1, if not, there exist c and {un} ⊂ X satisfying, as n

(2.7)
then we have
(2.8)

Denote vn = un/∥un∥, then ∥vn∥ = 1, that is, {vn} is bounded in X, thus for some vX, we get

(2.9)

If v = 0, define a sequence {tn} ⊂ as in [4]

(2.10)
If for some n, there is a number of tn satisfying (2.10), we choose one of them. For all m > 0, let , it follows by vn(x) → v(x) = 0 a.e. x ∈ Ω that
(2.11)
Then for n large enough, by (2.9), (2.11), and , we have
(2.12)
That is, lim nJ(tnun) = +. Since J(0) = 0 and J(un) → c, then 0 < tn < 1. Thus
(2.13)
We see that
(2.14)
From the aforementioned, we infer that
(2.15)
which contradicts (2.8).

If v≢0, by (2.7)

(2.16)
That is,
(2.17)
Since exists, and by vnv in X (the weakly convergent sequence is bounded), we get
(2.18)
where C is the constant of Sobolev Trace imbedding from H1(Ω) → L2(Ω), see [10]. We have
(2.19)
For x ∈ Ω : = {x ∈ Ω : v(x) ≠ 0}, we get |un(x)|→+. Then by (f2)
(2.20)
By using Fatou lemma, since the Lebesgue measure |Ω|   > 0,
(2.21)
On the other hand, by (f2), there exists γ > −, such that (f(x, s)s)/|s|2γ for (x, s) ∈ Ω × . Moreover,
(2.22)
Now, there is Λ > − s.t.
(2.23)
Together with (2.19) and (2.21), (2.23), it is a contradiction.

This proves that J satisfies condition (C).

3. Proof of Theorem 1.3

We will apply the Fountain theorem of Proposition 1.2 to the functional in (2.2). Let

(3.1)
then . It shows that JC1(X, ) by (f1) and satisfies condition (C) by Lemma 2.1.
  • (i)

    After integrating, we obtain from (f1) that there exist c1 > 0 such that

(3.2)

Let us define . By [2, Lemma 3.8], we get βk → 0 as k. Since |u|2C(Ω) | u|q, let c = c1 + (1/2)C(Ω), and , then by (3.2), for uZk with ∥u∥ = rk, we have

(3.3)
Notice that βk → 0 and q > 2, we infer that
(3.4)
  • (ii)

    While

(3.5)
we can deduce that ∫Ω | ∇u|2dx + ∫Ωα(x)u2dS is the equivalent norm of ∥u2 in X. Since dim Yk < + and all norms are equivalent in the finite-dimensional space, there exists Ck > 0, for all uYk, we get
(3.6)
Next by (f2), there is Rk > 0 such that F(x, s) ≥ 2Ck | s|2 for |s | ≥ Rk. Take Mk := max {0, , then for all (x, s) ∈ Ω × , we obtain
(3.7)
It follows from (3.6), (3.7), for all uYk that
(3.8)
Therefore, we get that for ρk large enough (ρk > rk),
(3.9)
By Fountain theorem of Proposition 1.2, J has a sequence of critical points unX, such that J(un)→+ as n, that is, (1.1) has infinitely many solutions.

Remark 3.1. By Theorem 1.3, the following equation:

(3.10)
has infinitely many solutions, while the results cannot be obtained by [1, 2, 8, 9]

Remark 3.2. In the next paper, we wish to consider the sign-changing solutions for problem (1.1).

Acknowledgments

We thank the referee for useful comments. C. Li is supported by NSFC (10601058, 10471098, 10571096). This work was supported by the Chinese National Science Foundation (10726003), the National Science Foundation of Shandong (Q2008A03), and the Foundation of Qufu Normal University.

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