Infinitely Many Solutions for a Robin Boundary Value Problem
Abstract
By combining the embedding arguments and the variational methods, we obtain infinitely many solutions for a class of superlinear elliptic problems with the Robin boundary value under weaker conditions.
1. Introduction
In this paper, we consider the following equation:
-
f1 , ∃q ∈ (2, 2*) such that
(1.3)
where 1 ≤ s < 2N/(N − 2), N ≥ 3. If N = 1,2, let 2* = ∞;
-
f2 f(x, s)s ≥ 0, lim |s|→+∞(f(x, s)s)/|s|2 = +∞ uniformly for x ∈ Ω.
-
f3 there exist θ ≥ 1, s ∈ [0,1] s.t.
-
f4 f(x, −t) = −f(x, t), (x, t) ∈ Ω × ℝ.
Because of (f2), (1.1) is usually called a superlinear problem. In [1, 2], the author obtained infinitely many solutions of (1.1) with Dirichlet boundary value condition under (f1), (f4) and
-
(AR) ∃ μ > 2, R > 0 such that
Obviously, (f2) can be deduced form (AR). Under (AR), the (PS) sequence can be deduced bounded. However, it is easy to see that the example [3]
We need the following condition (C), see [3, 5, 6].
Definition 1.1. Assume that X is a Banach space, we say that J ∈ C1(X, ℝ) satisfies Cerami condition (C), if for all c ∈ ℝ:
- (i)
any bounded sequence {un} ⊂ X satisfying J(un) → c, J′(un) → 0 possesses a convergent subsequence;
- (ii)
there exist σ, R, β > 0 s.t. for any u ∈ J−1([c − σ, c + σ]) with ∥u∥≥R, ∥J′(u)∥∥u∥≥β.
In the work in [2, 7], the Fountain theorem was obtained under the condition (PS). Though condition (C) is weaker than (PS), the well-known deformation theorem is still true under condition (C) (see [5]). There is the following Fountain theorem under condition (C).
Assume , where Xj are finite dimensional subspace of X. For each k ∈ ℕ, let
Proposition 1.2. Assume that J ∈ C1(X, ℝ) satisfies condition (C), and J(−u) = J(u). For each k ∈ ℕ, there exist ρk > rk > 0 such that
- (i)
, k → ∞,
- (ii)
.
As a particular linking theorem, Fountain theorem is a version of the symmetric Mountain-Pass theorem. Using the aforementioned theorem, the author in [6] proved multiple solutions for the problem (1.1) with Neumann boundary value condition; the author in [3] proved multiple solutions for the problem (1.1) with Dirichlet boundary value condition. In the present paper, we also use the theorem to give infinitely many solutions for problem (1.1). The main results are follows.
Theorem 1.3. Under assumptions (f1)–(f4), problem (1.1) has infinitely many solutions.
Remark 1.4. In the work in [1, 2], they got infinitely many solutions for problem (1.1) with Dirichlet boundary value condition under condition (AR).
Remark 1.5. In the work in [8], they showed the existence of one nontrivial solution for problem (1.1), while we get its infinitely many solutions under weaker conditions than [8].
Remark 1.6. In the work in [9], they also obtained infinitely many solutions for problem (1.1) with Dirichlet boundary value condition under stronger conditions than the aforementioned (f2) and (f3) above. Furthermore, function (1.6) does not satisfy all conditions in [9]. Therefore, Theorem 1.3 applied to Dirichlet boundary value problem improves those results in [1, 2, 8, 9].
2. Preliminaries
Let the Sobolev space X = H1(Ω). Denote
Since we do not assume condition (AR), we have to prove that the functional J satisfies condition (C) instead of condition (PS).
Lemma 2.1. Under (f1)–(f3), J satisfies condition (C).
Proof. For all c ∈ ℝ, we assume that {un} ⊂ X is bounded and
Since the Sobolev imbedding W1,2(Ω)↪Lγ(Ω) (1 ≤ γ < 2*) is compact, we have the right-hand side of (2.6) converges to 0. While ∫∂Ωb(x)(un − u) 2dS ≥ 0, we have ∥un − u∥2 → 0. It follows that un → u in X and J′(u) = 0, that is, condition (i) of Definition 1.1 holds.
Next, we prove condition (ii) of Definition 1.1, if not, there exist c ∈ ℝ and {un} ⊂ X satisfying, as n → ∞
Denote vn = un/∥un∥, then ∥vn∥ = 1, that is, {vn} is bounded in X, thus for some v ∈ X, we get
If v = 0, define a sequence {tn} ⊂ ℝ as in [4]
If v≢0, by (2.7)
This proves that J satisfies condition (C).
3. Proof of Theorem 1.3
We will apply the Fountain theorem of Proposition 1.2 to the functional in (2.2). Let
- (i)
After integrating, we obtain from (f1) that there exist c1 > 0 such that
Let us define . By [2, Lemma 3.8], we get βk → 0 as k → ∞. Since |u|2 ≤ C(Ω) | u|q, let c = c1 + (1/2)C(Ω), and , then by (3.2), for u ∈ Zk with ∥u∥ = rk, we have
- (ii)
While
Remark 3.1. By Theorem 1.3, the following equation:
Remark 3.2. In the next paper, we wish to consider the sign-changing solutions for problem (1.1).
Acknowledgments
We thank the referee for useful comments. C. Li is supported by NSFC (10601058, 10471098, 10571096). This work was supported by the Chinese National Science Foundation (10726003), the National Science Foundation of Shandong (Q2008A03), and the Foundation of Qufu Normal University.