Existence and Uniqueness of Periodic Solutions for a Second-Order Nonlinear Differential Equation with Piecewise Constant Argument
Abstract
Based on a continuation theorem of Mawhin, a unique periodic solution is found for a second-order nonlinear differential equation with piecewise constant argument.
1. Introduction
Qualitative behaviors of first-order delay differential equations with piecewise constant arguments are the subject of many investigations (see, e.g., [1–19]), while those of higher-order equations are not.
However, there are reasons for studying higher-order equations with piecewise constant arguments. Indeed, as mentioned in [10], a potential application of these equations is in the stabilization of hybrid control systems with feedback delay, where a hybrid system is one with a continuous plant and with a discrete (sampled) controller. As an example, suppose that a moving particle with time variable mass r(t) is subjected to a restoring controller −ϕ(x[t]) which acts at sampled time [t]. Then Newton′s second law asserts that
In this paper we study a slightly more general second-order delay differential equation with piecewise constant argument:
By a solution of (1.3) we mean a function x(t) which is defined on R and which satisfies the following conditions: (i) x′(t) is continuous on R, (ii) r(t)x′(t) is differentiable at each point t ∈ R, with the possible exception of the points [t] ∈ R where one-sided derivatives exist, and (iii) substitution of x(t) into (1.3) leads to an identity on each interval [n, n + 1) ⊂ R with integral endpoints.
In this note, existence and uniqueness criteria for periodic solutions of (1.3) will be established. For this purpose, we will make use of a continuation theorem of Mawhin. Let X and Y be two Banach spaces and L : Dom L ⊂ X → Y is a linear mapping and N : X → Y a continuous mapping. The mapping L will be called a Fredholm mapping of index zero if dim Ker L = codimImL < +∞, and Im L is closed in Y. If L is a Fredholm mapping of index zero, there exist continuous projectors P : X → X and Q : Y → Y such that Im P = Ker L and Im L = Ker Q = Im (I − Q). It follows that L|Dom L∩Ker P : (I − P)X → Im L has an inverse which will be denoted by KP. If Ω is an open and bounded subset of X, the mapping N will be called L-compact on if is bounded and is compact. Since Im Q is isomorphic to Ker L, there exists an isomorphism J : Im Q → Ker L.
Theorem 1 A (Mawhin′s continuation theorem [18]). Let L be a Fredholm mapping of index zero, and let N be L-compact on . Suppose that
- (i)
for each λ ∈ (0,1), x ∈ ∂Ω, Lx ≠ λNx;
- (ii)
for each x ∈ ∂Ω∩Ker L, QNx ≠ 0 and deg (JQN, Ω∩Ker , 0) ≠ 0.
2. Existence and Uniqueness Criteria
Our main results of this paper are as follows.
Theorem 2.1. Suppose that there exist constants D > 0 and δ⩾0 such that
- (i)
f(t, x)sgn x > 0 for t ∈ R and |x| > D,
- (ii)
lim x→−∞max 0≤t≤ω(f(t, x)/x) ≤ δ (or lim x→+∞max 0≤t≤ω(f(t, x)/x) ≤ δ).
- (iii)
f(t, x) is strictly monotonous in x and there exists nonnegative constant b < (4/ω2)min 0≤t≤ωr(t) such that
Theorem 2.2. Suppose that there exist constants D > 0 and δ⩾0 such that
-
i′ f(t, x)sgn x < 0 for t ∈ R and |x| > D,
-
ii′ lim x→−∞max 0≤t≤ω(f(t, x)/x)⩾−δ (or lim x→+∞max 0≤t≤ω(f(t, x)/x)⩾−δ).
- (iii)
f(t, x) is strictly monotonous in x and there exists nonnegative constant b < (4/ω2)min 0≤t≤ωr(t) such that (2.1) holds.
We only give the proof of Theorem 2.1, as Theorem 2.2 can be proved similarly.
First we make the simple observation that x(t) is an ω-periodic solution of the following equation:
Define the mappings L : Xω → Yω and N : Xω → Yω, respectively, by
Lemma 2.3. Let the mapping L be defined by (2.3). Then
Proof. It suffices to show that if x(t) is a real ω-periodic continuously differentiable function which satisfies
Lemma 2.4. Let the mapping L be defined by (2.3). Then
Proof. It suffices to show that for each y = y(t) ∈ Xω that satisfies y(0) = 0, there is a x = x(t) ∈ Xω such that
Lemma 2.5. The mapping L defined by (2.3) is a Fredholm mapping of index zero.
Indeed, from Lemmas 2.3 and 2.4 and the definition of Yω, dim Ker L = codim Im L = 1 < +∞. From (2.13), we see that Im L is closed in Yω. Hence L is a Fredholm mapping of index zero.
Lemma 2.6. Let the mapping L, P, and Q be defined by (2.3), (2.6), and (2.7), respectively. Then Im P = Ker L and Im L = Ker Q.
Indeed, from Lemmas 2.3 and 2.4 and defining conditions (2.6) and (2.7), it is easy to see that Im P = Ker L and Im L = Ker Q.
Lemma 2.7. Let L and N be defined by (2.3) and (2.4), respectively. Suppose that Ω is an open and bounded subset of Xω. Then N is L-compact on .
Proof. It is easy to see that for any
Lemma 2.8. Suppose that g(t) is a real, bounded and continuous function on [a, b) and exists. Then there is a point ξ ∈ (a, b) such that
The above result is only a slight extension of the integral mean value theorem and is easily proved.
Lemma 2.9. Suppose that condition (i) in Theorem 2.1 holds. Suppose further that x(t) ∈ Xω satisfies
Proof. From (2.22) and Lemma 2.8, we have ξi ∈ (i − 1, i) for i = 1, …, ω such that
Now, we consider that following equation:
Lemma 2.10. Suppose that conditions (i) and (ii) of Theorem 2.1 hold. If ω2δ(max 0≤t≤ω(1/r(t))) < 1, then there are positive constants D0 and D1 such that for any ω-periodic solution x(t) of (2.24),
Proof. Let x(t) be a ω-periodic solution of (2.24). By (2.24) and our assumption that we have
Lemma 2.11. Suppose that condition (iii) of Theorem 2.1 is satisfied. Then (1.3) has at most one ω-periodic solution.
Proof. Suppose that x1(t) and x2(t) are two ω-periodic solutions of (1.3). Set z(t) = x1(t) − x2(t). Then we have
Case 2 (i). For all t ∈ [0, ω], z(t) ≠ 0. Without loss of generality, we assume that z(t) > 0, that is, x1(t) > x2(t) for t ∈ [0, ω]. Integrating (2.48) from 0 to ω, we have
Case 2 (ii). There exist ξ ∈ [0, ω] such that z(ξ) = 0. As in the proof of (2.30) in Lemma 2.10, we have
We now turn to the proof of Theorem 2.1. Suppose ω2δ(max 0≤t≤ω(1/r(t))) < 1. Let L, N, P, and Q be defined by (2.3), (2.4), (2.6), and (2.7), respectively. By Lemma 2.10, there are positive constants D0 and D1 such that for any ω-periodic solution x(t) of (2.24) such that (2.25) holds. Set
3. Example
Consider the equation
Acknowledgment
The first author is supported by the Natural Science Foundation of Guangdong Province of China under Grant no. 9151008002000012.